Đáp án cần chọn là: A

B = 2 2 3 ⋅ 3 2 8 ⋅ 4 2 15 ⋅ 5 2 24 ⋅ 6 2 35 ⋅ 7 2 48 ⋅ 8 2 63 ⋅ 9 2 80 = 2.2 1.3 ⋅ 3.3 2.4 ⋅ 4.4 3.5 ⋅ 5.5 4.6 ⋅ 6.6 5.7 ⋅ 7.7 6.8 ⋅ 8.8 7.9 ⋅ 9.9 8.10 = 2.3.4.5.6.7.8.9 1.2.3.4.5.6.7.8. ⋅ 2.3.4.5.6.7.8.9 3.4.5.6.7.8.9.10 = 9 1 ⋅ 2 10 = 9.2 1.10 = 9 5

c 

\(=160:\left\{17+\left[9\cdot5-\left(14+2^3\right)\right]\right\}\)   

\(=160:\left\{17+\left[45-\left(14+8\right)\right]\right\}\)   

\(=160:\left\{17+\left[45-22\right]\right\}\)   

\(=160:\left(17+23\right)\)   

\(=160:40\)   

\(=4\)   

d 

\(=798+100:\left[16-2\cdot\left(25-22\right)\right]\)   

\(=798+100:\left(16-2\cdot3\right)\)      

\(=798+100:\left(16-6\right)\)   

\(=798+100:10\)   

\(=798+10\)   

\(=808\)

Số học sinh của trường tiểu học đó là:

\(120\div\frac{2}{7}=420\) (em)

95% số học sinh của trường tiểu học đó là:

\(420\times95\%=399\) (em)

Đáp án: 399 em 

Chúc bạn học tốt

B. 399 em

a.\(\left(\dfrac{1}{2}+1\right).\left(\dfrac{1}{3}+1\right).\left(\dfrac{1}{4}+1\right)...\left(\dfrac{1}{99}+1\right)\)

\(=\dfrac{3}{2}.\dfrac{4}{3}.\dfrac{5}{4}...\dfrac{100}{99}\)

\(=\dfrac{3.4.5...100}{2.3.4...99}\)

\(=\dfrac{100}{2}=50\)

a,

\(\left(\dfrac{1}{2}+1\right)\left(\dfrac{1}{3}+1\right)\left(\dfrac{1}{4}+1\right)...\left(\dfrac{1}{99}+1\right)\\ =\dfrac{3}{2}\cdot\dfrac{4}{3}\cdot\dfrac{5}{4}\cdot...\cdot\dfrac{100}{99}\\ =\dfrac{3\cdot4\cdot5\cdot...\cdot100}{2\cdot3\cdot4\cdot...\cdot99}\\ =\dfrac{100}{2}=50\)

b,

\(\left(\dfrac{1}{2}-1\right)\left(\dfrac{1}{3}-1\right)\left(\dfrac{1}{4}-1\right)...\left(\dfrac{1}{100}-1\right)\\ =\dfrac{-1}{2}\cdot\dfrac{-2}{3}\cdot\dfrac{-3}{4}\cdot...\cdot\dfrac{-99}{100}\\ =\dfrac{\left(-1\right)\left(-2\right)\left(-3\right)\cdot...\cdot\left(-99\right)}{2\cdot3\cdot4\cdot...\cdot100}\\ =\dfrac{\left(-1\right)\left(-1\right)\left(-1\right)\cdot...\left(-1\right)}{100}\left(\text{có }99\text{ số }-1\right)\\ =\dfrac{\left(-1\right)^{99}}{100}\\ =\dfrac{-1}{100}\)

c,

\(C=\dfrac{4}{30}+\dfrac{4}{70}+\dfrac{4}{126}+...+\dfrac{4}{798}\\ =\dfrac{2}{15}+\dfrac{2}{35}+\dfrac{2}{63}+...+\dfrac{2}{399}\\ =\dfrac{2}{3\cdot5}+\dfrac{2}{5\cdot7}+\dfrac{2}{7\cdot9}+...+\dfrac{2}{19\cdot21}\\ =\dfrac{1}{3}-\dfrac{1}{5}+\dfrac{1}{5}-\dfrac{1}{7}+\dfrac{1}{7}-\dfrac{1}{9}+...+\dfrac{1}{19}-\dfrac{1}{21}\\ =\dfrac{1}{3}-\dfrac{1}{21}\\ =\dfrac{7}{21}-\dfrac{1}{21}\\ =\dfrac{6}{21}=\dfrac{2}{7}\)

Có ngoặc không pạn???

cái này mk ghi thiếu nên ko biết ngoặc ở đâu , bạn nào có đề thì cho mình xin