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1)
a)
\(\frac{-5}{6}.\frac{120}{25}< x< \frac{-7}{15}.\frac{9}{14}\)
\(\frac{-1}{1}.\frac{20}{5}< x< \frac{-1}{5}.\frac{3}{2}\)
\(\frac{-20}{5}< x< \frac{-3}{10}\)
\(\frac{-40}{10}< x< \frac{-3}{10}\)
\(\Rightarrow Z\in\left\{-4;-5;-6;-7;-8;-9;-10;...;-39\right\}\)
a,5x-16+40+x b,4x-10=15-x c,-12+x=5x-20 d,7x-4=20+3x e,5x-7=-21-2x
=5x+x-16+40 4x+x=15+10 20-12=5x-x 7x-3x=20+4 5x+2x=7-21
=6x+24 5x=25 8=4x 4x=24 7x=7+(-21)
=6(x+4) x=25:5 x=8:4=2 x=24:4=6 7x=-14
x=5 x=-14:7=-2
f,x+15=7-6x g,17-x=7-6x h,3x+(-21)=12-8x k,125:(3x-13)=25 l,541+(218-x)=735
6x+x=7-15 6x-x=7-17 3x+8x=12+21 3x-13=125:25 218-x=735-541
7x=7+(-15) 5x=7+(-17) 11x=33 3x-13=5 218-x=194
7x=-8 5x=-10 x=33:11=3 3x=5+13 x=218-194
Không có giá trị của x thích hợp x=-10:5=-2 3x=18 x=24
x=18:3=6
m,3(2x+1)-19=14 n,175-5(x+3)=85 o,4x-40=4+12 p,x+15=20-4x q,8x+3=-4x+39
3(2x+1)=14+19 5(x+3)=175-85 4x-40=16 4x+x=20-15 8x+4x=39-3
3(2x+1)=33 5(x+3)=90 4x=16+40 5x=5 12x=36
2x+1=33;3 x+3=90:5 4x=56 x=5:5=1 x=36:12=3
2x+1=11 x+3=18 x=56:4
2x=11-1 x=18-3=15 x=14
2x=10
x=10:2
x=5
r,6x-12+(-2)=20-4x
6x-14=20-4x
6x+4x=20+14
10x=34
không có giá trị nào của x thích hợp
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PHẢI LÀ
\(5x-16=40+x!!!!!!!!!!\)
e, \(18x-19=21+8x\)
\(\Rightarrow18x-8x=21+19\)
\(\Rightarrow10x=30\)
\(\Rightarrow x=3\)
Vậy \(x=3\)
g, \(18-4x=-20-6x\)
\(\Rightarrow-4x+6x=-20-18\)
\(\Rightarrow-2x=-38\)
\(\Rightarrow x=19\)
Vậy \(x=19\)
h, \(-15x-24=-7x-32\)
\(\Rightarrow-15x+7x=-32+24\)
\(\Rightarrow-8x=-8\)
\(\Rightarrow x=1\)
Vậy \(x=1\)
i, \(15x-3\left(4x-6\right)=-12+36\)
\(\Rightarrow15x-12x+18=-12+36\)
\(\Rightarrow7x=-12+36-18\)
\(\Rightarrow7x=6\)
\(\Rightarrow x=\frac{6}{7}\)
Vậy \(x=\frac{6}{7}\)
k, \(-10x-27=-7x+33\)
\(\Rightarrow-10x+7x=33+27\)
\(\Rightarrow-3x=60\)
\(\Rightarrow x=-20\)
m, \(-17x-24=-9x-40\)
\(\Rightarrow-17x+9x=-40+24\)
\(\Rightarrow-8x=-16\)
\(\Rightarrow x=2\)
Vậy \(x=2\)
n, \(-23x-25=-18x+75\)
\(\Rightarrow-23x+18x=75+25\)
\(\Rightarrow-5x=100\)
\(\Rightarrow x=-20\)
Vậy \(x=-20\)
p, \(-5x+7\left(2x-3\right)=4\left(x-4\right)\)
\(\Rightarrow-5x+14x-21=4x-16\)
\(\Rightarrow-5x+14x-4x=-16+21\)
\(\Rightarrow5x=5\)
\(\Rightarrow x=1\)
Vậy \(x=1\)
q, \(24-6\left(3x+1\right)=-5\left(4x-4\right)-8\)
\(\Rightarrow24-18x-6=-20x+20-8\)
\(\Rightarrow-18x+20x=20-8-24+6\)
\(\Rightarrow2x=-6\)
\(\Rightarrow x=-3\)
Vậy \(x=-3\)
r, \(18-4\left(6-2x\right)=-3\left(4x+5\right)-11\)
\(\Rightarrow18-24+8x=-12x-15-11\)
\(\Rightarrow8x+12x=-15-11-18+24\)
\(\Rightarrow20x=-20\)
\(\Rightarrow x=-1\)
Vậy \(x=-1\)
s, \(-5\left(4x-5\right)-14=6\left(2-3x\right)-10x-9\)
\(\Rightarrow-20x+25-14=12-18x-10x-9\)
\(\Rightarrow-20x+18x+10x=12-9+14-25\)
\(\Rightarrow8x=-8\)
\(\Rightarrow x=-1\)
Vậy \(x=-1\)
Chúc bạn hok tốt!!! tỷ tỷ
Câu a:
\(\frac{x+5}{x+9}\) = \(\frac{x+4}{x+3}\)
(\(x\) + 5)(\(x+3\)) = (\(x+4\))(\(x+9\))
\(x^2\) + 3\(x\) + 5\(x\) + 15 = \(x^2\) + 9\(x\) + 4\(x\) + 36
\(x^2+3x+5x\) - \(x^2-9x\) - 4\(x\) = 36 - 15
(\(x^2-x^2\)) + (\(3x+5x\) - 9\(x-4x\)) = 21
0 + (8\(x\) - 9\(x\) - 4\(x\)) = 21
-\(x-4x\) = 21
-5\(x\) = 21
\(x\) = 21 : (-5)
\(x\) = - \(\frac{21}{5}\)
Vậy \(x=-\frac{21}{5}\)
a) \(2\left(x-5\right)-3\left(x+7\right)=14\)
\(\Leftrightarrow2x-10-3x-21=14\)
\(\Leftrightarrow-x-31=14\)
\(\Leftrightarrow-x=45\Leftrightarrow x=-45\)
b) \(5\left(x-6\right)-2\left(x+3\right)=12\)
\(\Leftrightarrow5x-30-2x-6=12\)
\(\Leftrightarrow3x-36=12\)
\(\Leftrightarrow3x=48\Leftrightarrow x=16\)
c) \(3\left(x-4\right)-\left(8-x\right)=12\)
\(\Leftrightarrow3x-12-8+x=12\)
\(\Leftrightarrow4x-20=12\)
\(\Leftrightarrow4x=32\Leftrightarrow x=8\)
d) \(-7\left(3x-5\right)+2\left(7x-14\right)=28\)
\(\Leftrightarrow-21x+35+14x-28=28\)
\(\Leftrightarrow-7x+35=0\Leftrightarrow x=5\)
a)|1/2x|=3-2x
\(\frac{\left|x\right|}{2}=-\left(2x-3\right)\)
\(x=\frac{6}{5}\)
a) => 4/3x = 7/9 - 4/9 = 1/3
=> x = 1/3 : 4/3 = 1/4
b) => 5/2 - x = 9/14 : (-4/7) = -9/8
=> x = 5/2 - (-9/8) = 5/2 + 9/8 = 29/8
c) => 3x = 2 và 2/3 - 3/4 = 8/3 - 3/4 = 23/12
=> x = 23/12 : 3 = 23/36
D) => -5/6 - x = 1/4
=> x = -5/6 - 1/4 = -13/12
a) \(\dfrac{4}{9}+\dfrac{4}{3}x=\dfrac{7}{9}\)
\(\dfrac{4}{3}x=\dfrac{7}{9}-\dfrac{4}{9}=\dfrac{1}{3}\)
\(x=\dfrac{1}{3}:\dfrac{4}{3}\)
\(x=\dfrac{1}{4}\)
b) \(\left(\dfrac{5}{2}-x\right)\left(-\dfrac{4}{7}\right)=\dfrac{9}{14}\)
\(\dfrac{5}{2}-x=\dfrac{9}{14}:\left(-\dfrac{4}{7}\right)=-\dfrac{9}{8}\)
\(x=\dfrac{5}{2}-\left(-\dfrac{9}{8}\right)\)
\(x=\dfrac{29}{8}\)
c) \(3x+\dfrac{3}{4}=2\dfrac{2}{3}\)
\(3x+\dfrac{3}{4}=\dfrac{8}{3}\)
\(3x=\dfrac{8}{3}-\dfrac{3}{4}=\dfrac{23}{12}\)
\(x=\dfrac{23}{12}:3\)
\(x=\dfrac{23}{36}\)
d) \(-\dfrac{5}{6}-x=\dfrac{7}{12}+\dfrac{-1}{3}\)
\(-\dfrac{5}{6}-x=\dfrac{1}{4}\)
\(x=-\dfrac{5}{6}-\dfrac{1}{4}\)
\(x=-\dfrac{13}{12}\)
a ) Ta có : 4(x - 5) - 3(x + 7) = -19
<=> 4x - 20 - 3x - 21 = -19
=> x - 41 = -19
=> x = -19 + 41
=> x = 22
b) Ta có " 7(x - 3) - 5(3 - x) = 11x - 5
<=> 7x - 21 - 15 + 5x = 11x - 5
<=> 12x - 36 = 11x - 5
=> 12x - 11x = -5 + 36
=> x = 31
12 + \(x\) = 5\(x\) + 20
12 + \(x\) - 5\(x\) - 20 = 0
- (5\(x-x\)) = 20 - 12
- 4\(x\) = 8
\(x\) = 8 : (-4)
\(x\) = - 2
Vậy \(x=-2\)
Câu 2:
-7(3\(x\) - 5) + 2(7\(x-14\)) = 28
- 21\(x\) + 35 + 14\(x\) - 28 = 28
- (21\(x\) - 14\(x\)) = 28 + 28 - 35
- 7\(x\) = 56 - 35
- 7\(x\) = 21
\(x\) = 21 : (-7)
\(x=-3\)
Vậy \(x=-3\)
a: -12+x=5x+20
=>5x+20=x-12
=>5x-x=-12-20
=>4x=-32
=>\(x=-\frac{32}{4}=-8\)
b: \(-7\left(3x-5\right)+2\left(7x-14\right)=28\)
=>-21x+35+14x-28=28
=>-7x+7=28
=>-7x=21
=>x=-3