\(x-1\frac{1}{2}=1\frac{1}{3}\)

           \(x=1\frac{1}{3}+1\frac{1}{2}\)

            \(x=\frac{17}{6}\)

\(x-2,1=2,2\)

           \(x=2,2+2,1\)

           \(x=4,3\)

0,56  7,8 + 2,2  0,44 = (0,56+0,44) + (7,8 + 2,2) =11

\(\frac{31}{3}+\frac{31}{15}+\frac{31}{35}+\frac{31}{63}+\frac{31}{99}+\frac{31}{143}=\frac{31}{1.3}+\frac{31}{3.5}+\frac{31}{5.7}+\frac{31}{7.9}+\frac{31}{9.11}+\frac{31}{11.13}\\ \)

\(=\frac{31}{2}.\left(\frac{2}{1.3}+\frac{2}{3.5}+\frac{2}{5.7}+\frac{2}{7.9}+\frac{2}{9.11}+\frac{2}{11.13}\right)\)

\(=\frac{31}{2}.\left(1-\frac{1}{3}+\frac{1}{3}-\frac{1}{5}+\frac{1}{5}-\frac{1}{7}+\frac{1}{7}-\frac{1}{9}+\frac{1}{9}-\frac{1}{11}+\frac{1}{11}-\frac{1}{13}\right)\)

\(=\frac{31}{2}.\left(1-\frac{1}{13}\right)=\frac{31}{2}.\frac{12}{13}=\frac{31.6}{13}=\frac{186}{13}\)

\(\Rightarrow x-\frac{186}{13}=\frac{9}{13}\Leftrightarrow x=\frac{195}{13}=15\)

\(x-\left(\frac{31}{3}+\frac{31}{15}+\frac{31}{35}+\frac{31}{63}+\frac{31}{99}+\frac{31}{143}\right)=\)\(\frac{9}{13}\)(1)

Đặt \(A=\frac{31}{3}+\frac{31}{15}+\frac{31}{35}+\frac{31}{63}+\frac{31}{99}+\frac{31}{143}\)

\(A=31\left(\frac{1}{3}+\frac{1}{15}+\frac{1}{35}+\frac{1}{63}+\frac{1}{99}+\frac{1}{143}\right)\)

\(\Rightarrow2A=31\left(\frac{2}{3}+\frac{2}{15}+\frac{2}{35}+\frac{2}{63}+\frac{2}{99}+\frac{2}{143}\right)\)

\(2A=31\left(\frac{2}{1.3}+\frac{2}{3.5}+\frac{2}{5.7}+\frac{2}{7.9}+\frac{2}{9.11}+\frac{2}{11.13}\right)\)

\(2A=31\left(2-\frac{1}{3}+\frac{1}{3}-\frac{1}{5}+\frac{1}{5}-\frac{1}{7}+\frac{1}{7}-\frac{1}{9}+\frac{1}{9}-\frac{1}{11}+\frac{1}{11}-\frac{1}{13}\right)\)

\(2A=31\left(2-\frac{1}{13}\right)\)

\(2A=31.\frac{25}{13}\)

\(2A=\frac{775}{13}\)

\(\Rightarrow A=\frac{775}{13}:2\)

\(A=\frac{775}{26}\)

   Thay vào (1) ta có:

 \(x-\frac{775}{26}=\frac{9}{13}\)

\(\Leftrightarrow x=\frac{9}{13}+\frac{775}{26}\)

\(\Leftrightarrow x=\frac{61}{2}\)

Đặt A=2,0+2,1+2,2+...+7,9+8,0

A có: (8-2)/0,1+1=61(số hạng)

A =(8+2)*61/2=305(1)

Đặt B =26·49−2325·49+26 

=(25+1)49−23/25*49+26 =1225+49−23/1225+26 =1225+(49−23)/1225+26 =1225+26/1225+26 =1

Từ 1,2 => A/B

=(2,0+2,1+2,2+...+7,9+8,0):(26·49−2325·49+26 )

=305/1 =305

Đặt A=2,0+2,1+2,2+...+7,9+8,0

A có: (8-2)/0,1+1=61(số hạng)

A =(8+2)*61/2=305(1)

Đặt B =26·49−2325·49+26 

=(25+1)49−23/25·49+26 =1225+49−23/1225+26 =1225+(49−23)/1225+26 =1225+26/1225+26 =1

Từ 1,2 => A/B

=(2,0+2,1+2,2+...+7,9+8,0):(26·49−2325·49+26 )

=305/1 =305

Đặt A=2,0+2,1+2,2+...+7,9+8,0

A có: (8-2)/0,1+1=61(số hạng)

A =(8+2)*61/2=305(1)

Đặt B =\(\frac{26\cdot49-23}{25\cdot49+26}\)

\(=\frac{\left(25+1\right)49-23}{25\cdot49+26}=\frac{1225+49-23}{1225+26}=\frac{1225+\left(49-23\right)}{1225+26}=\frac{1225+26}{1225+26}=1\)(2)

Từ 1,2 => A/B

\(=\left(2,0+2,1+2,2+...+7,9+8,0\right):\left(\frac{26\cdot49-23}{25\cdot49+26}\right)\)

\(=\frac{305}{1}=305\)

Chúc bạn học tốt!^_^

Số số hạng 

( 110,0 - 1,1 ) : 1,1 + 1 = 100 

Gọi x là số cần tìm 

Theo đề , ta có 

( x - 1,1 ) : 1,1 + 1 = 50 

( x - 1,1 ) : 1,1 = 50 - 1 

( x - 1,1 ) : 1,1 = 49 

x - 1,1 = 49 x 1,1 

x - 1,1 = 53,9 

x = 53,9 + 1,1 

x = 55 

\(\frac{5}{4};\frac{3}{2};2;2,2;\frac{9}{4}\)

củm ưn bẹn nhìu :))))))))))))))))))))))))))))))))

là 2.11 và 2.12

2,155;2,199

Chữ số ở phần thập phân là 99 số

x\(\times\)(5,5+2,2+10,10+3,3)=20,10

x\(\times\)20,10=20,10

x=20,10\(\div\)20,10=1

Ai tích mình mình tích lại cho.

Xx(5,5+10,10+2,2+3,3)=20,10

Xx20,10=20,10

x=20,10:20,10

x=1

= 1,1 + 2,2 + 3,3 + 4,4+ 5,5+ 6,6+ 7,7+8,8+9,9

= (1,1+9,9)+ (2,2+8,8)+ (3,3+7,7)+ (4,4+6,6)+ 5,5

= 11+ 11 + 11+ 11+ 5,5

= 11x4+5,5=49,5

đáp số:...

k mk nhóe

= 0,5:0,5 - 0,25 :0,25 + 0,125: 0,125+ 0,1:0,1

= 1 -1 +1 +1

= 2

k mk nhoa