công thúc nè
tính số số hạng : (số cuối -số đầu) / khoảng cách +1
tính tổng :(số cuối + số đầu)* số số hạng / 2
cho mình hỏi chút lopw 4 đã hc có nì rồi ah

a) 1 + 5 + 9 + 13 + ... + 393 + 397

= (1 + 397) x (\(\frac{397-1}{4}\) + 1) : 2

= 398 x \(\frac{397-1+4}{4}\) : 2

= (398 : 2) x \(\frac{397+3}{4}\)

= 199 x \(\frac{200}{4}\)

= 199 x 50 = 9950

\(\frac{3}{4}:\frac{5}{6}+\frac{1}{4}:\frac{5}{6}\)

\(=\left(\frac{3}{4}+\frac{1}{4}\right):\frac{5}{6}\)

\(=1:\frac{5}{6}\)

\(=1\times\frac{6}{5}\)

\(=\frac{6}{5}\)

\(\frac{3}{4}:\frac{5}{6}+\frac{1}{4}:\frac{5}{6}\)

\(=\left(\frac{3}{4}+\frac{1}{4}\right):\frac{5}{6}\)

\(=1:\frac{5}{6}\)

\(=1\times\frac{6}{5}\)

\(=\frac{6}{5}\)

4/5 : 2/9 x 2/9 : 4/5
= 4/5 x 9/2 x 2/9 x 5/4
= ( 4/5 x 5/4 ) x ( 9/2 x 2/9 )
= 1x1
= 1

\(\frac{4}{5}:\frac{2}{9}\times\frac{2}{9}:\frac{4}{5}\)

\(=\frac{4}{5}\times\frac{9}{2}\times\frac{2}{9}\times\frac{5}{4}\)

\(=\left(\frac{4}{5}\times\frac{5}{4}\right)\times\left(\frac{2}{9}\times\frac{9}{2}\right)\)

\(=1\times1\)

\(=1\)

\(\frac{17}{2}\times\frac{3}{5}+\frac{3}{5}\times\frac{1}{2}+\frac{3}{5}\)

\(=\frac{3}{5}\times\left(\frac{17}{2}+\frac{1}{2}\right)\)

\(=\frac{3}{5}\times9\)

\(=\frac{27}{5}\)

Ai Fan anh Kha diem danh

\(\frac{17}{2}\times\frac{3}{5}+\frac{3}{5}\times\frac{1}{2}+\frac{3}{5}\)

\(=\frac{3}{5}\times\left(\frac{17}{2}+\frac{1}{2}+1\right)\)

\(=\frac{3}{5}\times\left(\frac{17}{2}+\frac{1}{2}+\frac{2}{2}\right)\)

\(=\frac{3}{5}\times\frac{20}{2}\)

\(=\frac{60}{10}=6\)

CHÚC BẠN HOK TOT

a \(\frac{7}{6}\)

b \(\frac{5}{3}\)

\(a,\frac{2}{5}+\frac{1}{6}+\frac{3}{5}\)

\(=\left(\frac{2}{5}+\frac{3}{5}\right)+\frac{1}{6}\)

\(=1+\frac{1}{6}\)

\(=\frac{7}{6}\)

Hok tốt!~

bài 1:

\(\frac{6}{11}+\frac{1}{3}+\frac{5}{11}\)

\(=\left(\frac{6}{11}+\frac{5}{11}\right)+\frac{1}{3}\)

\(=\frac{11}{11}+\frac{1}{3}=1+\frac{1}{3}=\frac{3}{3}+\frac{1}{3}=\frac{4}{3}\)

bài 2:

\(\frac{1}{2}+\frac{1}{6}+\frac{1}{12}+\frac{1}{20}\)

\(=\left(\frac{1}{2}+\frac{1}{20}\right)+\left(\frac{1}{6}+\frac{1}{12}\right)\)

\(=\frac{11}{20}+\frac{1}{4}=\frac{11}{20}+\frac{5}{20}=\frac{15}{20}=\frac{3}{4}\)

bài 3: 

a) \(\frac{3}{2}\cdot\frac{4}{5}\cdot\frac{2}{3}=\left(\frac{3}{2}\cdot\frac{2}{3}\right)\cdot\frac{4}{5}=1\cdot\frac{4}{5}=\frac{4}{5}\)

b) \(\frac{6}{7}\cdot\frac{5}{3}\cdot\frac{7}{6}=\left(\frac{6}{7}\cdot\frac{7}{6}\right)\cdot\frac{5}{3}=1\cdot\frac{5}{3}=\frac{5}{3}\)

bài 4: 

a) \(\frac{2}{5}\cdot\frac{1}{4}+\frac{3}{4}\cdot\frac{2}{5}=\frac{2}{5}\cdot\left(\frac{1}{4}+\frac{3}{4}\right)=\frac{2}{5}\cdot1=\frac{2}{5}\)

b) \(\frac{6}{11}:\frac{2}{3}+\frac{5}{11}:\frac{2}{3}=\left(\frac{6}{11}+\frac{5}{11}\right):\frac{2}{3}=1:\frac{2}{3}=\frac{3}{2}\)

Bài 1: 

  6/11 + 1/3 + 5/11 

= ( 6/11 + 5/11) + 1/3

= 11/11 + 1/3

= 1 + 1/3 

= 3/3 +1/3  

= 4/3 

Bài 2: 

1/2 + 1/6 + 1/12 + 1/20 

= ( 1/2 + 1/6 + 1/12 ) + 1/20 

= ( 6/12 + 2/12 + 1/12 ) + 1/20 

=9/12 + 1/20 

= 3/4 +1/20  

= 15/20 + 1/20 

= 16/20 = 4/5

 Bài 3:

a) \(\frac{3}{2}\times\frac{4}{5}\times\frac{2}{3}\) \(=\left(\frac{3}{2}\times\frac{2}{3}\right)\times\frac{4}{5}\)\(=1\times\frac{4}{5}=\frac{4}{5}\) 

b)  \(\frac{6}{7}\times\left(\frac{5}{3}\times\frac{7}{6}\right)\) \(=\frac{6}{7}\times\frac{35}{18}\)\(=\frac{1\times5}{7\times3}=\frac{5}{21}\)   

Bài 4:

a) 2/5  x 1/4 + 3/4 x 2/5 

= 2/5 x ( 1/4  + 3/4) 

 = 2/5 x  1 

= 2/5

 b) 6/11 : 2/3 +5/11 : 2/3 

=  ( 6/11 + 5/11) x 3/2 

= 11/11 x 3/2  

= 1 x 3/2  

=  3/2  

....  

6/4 x 45/10 + 105/10 : 2/3 - 3/2 x 5

= 3/2 x 45/10 + 105/10 x 3/2 - 3/2 x 5

= 3/2 x (45/10 + 105/10 - 5)

= 3/2 x 10

= 15

tôi ko giải đc chịu thôi

\(a.\frac{3}{7}.\frac{5}{6}+\frac{5}{6}.\frac{4}{7}=\left(\frac{3}{7}+\frac{4}{7}\right).\frac{5}{6}=1.\frac{5}{6}=\frac{5}{6}\)

\(b.\frac{1}{6}:\frac{4}{5}+\frac{1}{8}:\frac{4}{5}=\left(\frac{1}{6}+\frac{1}{8}\right):\frac{4}{5}=\left(\frac{4}{24}+\frac{3}{24}\right):\frac{4}{5}=\frac{7}{24}:\frac{4}{5}=\frac{7.5}{24.4}\)\(=\frac{35}{96}\)

\(c.\frac{1}{6}:\frac{4}{5}-\frac{1}{8}:\frac{4}{5}=\left(\frac{1}{6}-\frac{1}{8}\right):\frac{4}{5}=\left(\frac{4}{24}-\frac{3}{24}\right):\frac{4}{5}\)\(=\frac{1}{24}:\frac{4}{5}=\frac{1.5}{24.4}=\frac{5}{96}\)

a) \(\frac{3}{7}\cdot\frac{5}{6}+\frac{5}{6}\cdot\frac{4}{7}\)

\(=\left(\frac{3}{7}+\frac{4}{7}\right)\cdot\frac{5}{6}\)

\(=1\cdot\frac{5}{6}\)

\(=\frac{5}{6}\)

b) \(\frac{1}{6}:\frac{4}{5}+\frac{1}{8}:\frac{4}{5}\)

\(=\left(\frac{1}{6}+\frac{1}{8}\right):\frac{4}{5}\)

\(=\frac{7}{24}:\frac{4}{5}\)

\(=\frac{35}{96}\)

c) \(\frac{1}{6}:\frac{4}{5}-\frac{1}{8}:\frac{4}{5}\)

\(=\left(\frac{1}{6}-\frac{1}{8}\right):\frac{4}{5}\)

\(=\frac{1}{24}:\frac{4}{5}\)

\(=\frac{5}{96}\)

\(\frac{3}{7}+\frac{4}{5}+\frac{4}{7}=\left(\frac{3}{7}+\frac{4}{7}\right)+\frac{4}{5}=1+\frac{4}{5}=\frac{9}{5}\)

\(\frac{6}{11}+\frac{1}{3}+\frac{5}{11}=\left(\frac{6}{11}+\frac{5}{11}\right)+\frac{1}{3}=1+\frac{1}{3}=\frac{4}{3}\)

a) \(\frac{3}{7}+\frac{4}{5}+\frac{4}{7}\)

 = \(\left(\frac{3}{7}+\frac{4}{7}\right)+\frac{4}{5}\)

 = \(1+\frac{4}{5}\)

 = \(\frac{9}{5}\)

b) \(\frac{6}{11}+\frac{1}{3}+\frac{5}{11}\)

 = \(\left(\frac{6}{11}+\frac{5}{11}\right)+\frac{1}{3}\)

 = \(1+\frac{1}{3}\)

 = \(\frac{4}{3}\)

\(\frac{13}{19}+5=\frac{108}{19}\)

bài 1

\(\frac{13}{19}+5=\frac{108}{19}\)

Bài 2 sai de thi phai

Bài 3

Giải

Số phần bạn A làm xong kế hoạch là:

\(\frac{3}{5}+\frac{1}{4}=\frac{17}{20}\)

Vậy còn \(\frac{3}{20}\)phần kế hoạch chưa làm

Bài 4

\(\frac{47}{15}+\frac{40}{17}-\frac{4}{30}-\frac{6}{17}\)

\(=\left(\frac{40-6}{17}\right)+\left(\frac{47-2}{15}\right)=5\)

Bài 5

a)

\(\frac{1}{2}-\frac{1}{3}=\frac{1}{6}\)VÀ  \(\frac{1}{2x3}=\frac{1}{6}\)

Vạy 2 gia trị bằng nhau

b)

\(\frac{2}{3x5}=\frac{2}{15}\)Và \(\frac{1}{3}-\frac{1}{5}=\frac{2}{15}\)

Vậy 2 giá trị bằng nhau