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\(\left(x+1,5-\dfrac{3}{7}\right):\dfrac{1}{2}=1\dfrac{1}{7}\)
=> \(\left(x+\dfrac{3}{2}-\dfrac{3}{7}\right).2=\dfrac{8}{7}\)
=> \(x+\dfrac{3}{2}-\dfrac{3}{7}=\dfrac{8}{7}.\dfrac{1}{2}\)
=> \(x+\dfrac{21}{14}-\dfrac{6}{14}=\dfrac{8}{14}\)
=> x=\(\dfrac{8}{14}+\dfrac{6}{14}-\dfrac{21}{14}\)
=> x=\(\dfrac{-7}{14}=-\dfrac{1}{2}\)
vậy x=-\(\dfrac{1}{2}\)
\(A=\frac{15\times3^{11}+4\times27^4}{9^7}\)
\(A=\frac{15\times177147+4\times531441}{4782969}\)
\(A=\frac{2657205+2125764}{4782969}\)
\(A=\frac{47829969}{47829969}=1\)
\(19\frac{1}{4}+\frac{1}{2}.2\frac{1}{3}+5,75-\frac{1}{6}+74\)
=\(\frac{77}{4}+\frac{1}{2}.\frac{7}{3}+\frac{575}{100}-\frac{1}{6}+74\)
= \(\frac{77}{4}+\frac{7}{6}+\frac{23}{4}-\frac{1}{6}+74\)
= \(\left(\frac{77}{4}+\frac{23}{4}\right)+\left(\frac{7}{6}-\frac{1}{6}\right)+74\)
= \(\frac{100}{4}+1+74\)
= 100
^^
\(\frac{99}{98}+\frac{96}{97}+\frac{1}{97.98}=\frac{99}{98}+\frac{96}{97}+\frac{1}{97}-\frac{1}{98}=\left(\frac{99}{98}-\frac{1}{98}\right)+\left(\frac{1}{97}+\frac{96}{97}\right)=1+1=2\)
= 2
mk bấm máy tính
đúng 10000000000000000000000000000000000000000000000000000000000000000000000%
\(0.25.30.2.\frac{1}{3}=0\)
\(\left|\frac{-2}{5}.x+\frac{1}{5}\right|-\frac{1}{4}=\frac{3}{4}\)
\(\left|\frac{-2}{5}.x+\frac{1}{5}\right|=\frac{3}{4}+\frac{1}{4}\)
\(\left|\frac{-2}{5}.x+\frac{1}{5}\right|=1\)
\(\Leftrightarrow\orbr{\begin{cases}\frac{-2}{5}.x+\frac{1}{5}=1\\\frac{-2}{5}.x+\frac{1}{5}=-1\end{cases}\Leftrightarrow}\orbr{\begin{cases}x=-2\\x=3\end{cases}}\)
đúng thì ủng hộ tớ nha
NHân 3 rồi tìm S đi
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Thành viên OLM dạo này lười thế nhờ có cái đó cũng phải hỏi
a) \(3^{x+1}-2.3^x=81\)
\(\Rightarrow3^x.3-2.3^x\)
\(\Rightarrow3^x\left(3-2\right)=81\)
\(\Rightarrow3^x=3^4\)
\(\Rightarrow x=4\)
Vậy \(x=4\)
b) \(2^{x+2}+2^x=40\)
\(\Rightarrow2^x.2^2+2^x=40\)
\(\Rightarrow2^x.\left(2^2+1\right)=40\)
\(\Rightarrow2^x.5=40\)
\(\Rightarrow2^x=8\)
\(\Rightarrow2^x=2^3\)
\(\Rightarrow x=3\)
Vậy \(x=3\)
c) \(\left(x+1\right)^5-12=20\)
\(\Rightarrow\left(x+1\right)^5=32\)
\(\Rightarrow\left(x+1\right)^5=2^5\)
\(\Rightarrow x+1=2\)
\(\Rightarrow x=1\)
Vậy \(x=1\)
d) \(56-\left(x-2\right)^2=20\)
\(\Rightarrow\left(x-2\right)^2=36\)
\(\Rightarrow x-2=\pm6\)
+) \(x-2=6\Rightarrow x=8\)
+) \(x-2=-6\Rightarrow x=-4\)
Vậy \(x=8\) hoặc \(x=-4\)
2
bằng 2 ngu thế