\(\frac{15}{29}+\frac{-9}{31}+\frac{-7}{8}+\frac{14}{29}-\frac{-22}{31}=\frac{15}{29}+\frac{14}{29}+\left(\frac{-9}{31}+\frac{-22}{31}\right)-\frac{-7}{8}=0-\frac{-7}{8}=\frac{7}{8}\)

\(1\frac57-\frac57\times\frac{2}{11}-\frac57\times\frac{9}{11}\)

=\(\frac57\times\left(1-\frac{2}{11}-\frac{9}{11}\right)\)

=\(\frac57\times\left(\frac{11}{11}-\frac{2}{11}-\frac{9}{11}\right)\)

=\(\frac57\times1\)

=\(\frac57\)

\(\frac{5}{11}\times\frac{18}{29}-\frac{5}{11}\times\frac{8}{29}+\frac{5}{11}\times\frac{19}{26}\)

=\(\frac{5}{11}\times\left(\frac{18}{29}-\frac{8}{29}+\frac{19}{29}\right)\)

=\(\frac{5}{11}\times1\)

=\(\frac{5}{11}\)

a)\(\left(\frac{3}{29}-\frac{1}{5}\right)\cdot\frac{29}{3}\)

\(=\left(\frac{3}{29}\cdot\frac{29}{3}\right)-\left(\frac{1}{5}\cdot\frac{29}{3}\right)\)

\(=1-\frac{29}{15}\)

\(=\frac{-14}{15}\)

b)\(\frac{16}{15}\cdot\frac{-5}{14}\cdot\frac{54}{24}\cdot\frac{56}{21}\)

=\(=\frac{16\cdot\left(-5\right)\cdot54\cdot56}{15\cdot14\cdot24\cdot21}\)

\(=\frac{2^4\cdot\left(-5\right)\cdot2\cdot3^3\cdot2^3\cdot7}{3\cdot5\cdot7\cdot2\cdot2^3\cdot3\cdot7}\)

\(=2^4\)

c)\(\frac{37}{7}\cdot\frac{8}{11}+\frac{37}{7}\cdot\frac{5}{11}-\frac{37}{7}\cdot\frac{2}{11}\)

\(=\frac{37}{7}\cdot\left(\frac{8}{11}+\frac{5}{11}-\frac{2}{11}\right)\)

\(=\frac{37}{7}\cdot1\)

\(=\frac{37}{7}\)

Đúng nhớ k nhen!

b)\(-2^4\)nãy mk nhầm

a) \(\frac{28}{29}-\frac{27}{28}=\frac{784}{812}-\frac{783}{812}=\frac{784-783}{812}=\frac{1}{812}\)

b) \(\frac{23}{8}-\frac{7}{2}=\frac{23}{8}-\frac{28}{8}=\frac{23-28}{8}=\frac{-5}{8}\)

c) \(\frac{11}{15}-\frac{3}{5}=\frac{11}{15}-\frac{9}{15}=\frac{11-9}{15}=\frac{2}{15}\)

a, mẫu số chung là 203

b, mẫu chung là 8

c, mẫu chung là 15

tự quy đồng mẫu rồi tính. dễ mà

\(I=\frac{5.4^{15}.9^9-4.3^{20}.8^9}{5.2^9.6^{19}-7.2^{29}.27^6}=\frac{5.2^{30}.3^{27}-2^2.3^{20}.2^{27}}{5.2^9.2^{19}.3^{19}-7.2^{29}.3^{18}}\)

\(=\frac{5.2^{30}.3^{27}-3^{30}.2^{29}}{5.2^{28}.3^{19}-7.2^{29}.3^{18}}\)

\(=\frac{2^{29}.3^{27}.\left(5.2-3^3\right)}{2^{28}.3^{18}.\left(5.3-2.7\right)}\)

\(=\frac{2^{29}.3^{27}.-17}{2^{18}.3^{18}}\)

\(=\frac{2^9.3^9.-17}{1}\)

Ta có \(H=\frac{\left(3.4.2^{16}\right)}{11.2^{13}.4^{11}-16^9}\)

\(=\frac{3.4.2^{16}}{11.2^{13}.2^{22}-2^{36}}\)

\(=\frac{3.2^{18}}{11.2^{35}-2^{36}}\)

\(=\frac{3.2^{18}}{2^{35}.\left(11-2\right)}\)

\(=\frac{3.2^{18}}{2^{35}.3^2}\)

\(=\frac{1}{2^{17}.3}\)

Gọi số học sinh nữ là x

Số học sinh nam là 5/11x

Theo đề, ta có: \(x=\dfrac{15}{29}\left(\dfrac{5}{11}x-25\right)\)

=>Đề sai rồi bạn

\(E=\dfrac{11.3^{29}-3^{2^{15}}}{2.3^{14}.2.3^{14}}\)

\(=\dfrac{11.3-3^{30}}{2^2}=\dfrac{33-3^{30}}{4}\)