Ta có: 3x + 2 chia hết cho n + 1

<=> 3x + 3 - 1 chia hết cho n + 1

<=> 3.(n + 1) - 1 chia hết cho n + 1

<=> 1 chia hết cho n + 1

=> n + 1 thuộc Ư(1) = {-1;1}

Ta có bảng :
 

a) 3x + 2 chia hết cho x + 1

Ta có : 3x + 2 = 3 ( x + 1 ) - 1

=> 3 ( x + 1 ) - 1 chia hết cho x + 1

=> -1 chia hết cho x + 1

Phần tiếp theo bn tự làm và kẻ bảng nha

Ta có: 3x + 2 chia hết cho n + 1

<=> 3x + 3 - 1 chia hết cho n + 1

<=> 3.(n + 1) - 1 chia hết cho n + 1

<=> 1 chia hết cho n + 1

=> n + 1 thuộc Ư(1) = {-1;1}

Ta có bảng :

\(3x+2⋮x+1\Rightarrow3x+3-1⋮x+1\)

\(\Rightarrow1⋮x+1\Rightarrow x+1\inƯ\left(1\right)\)

\(\Rightarrow\orbr{\begin{cases}x+1=-1\\x+1=1\end{cases}}\Rightarrow\orbr{\begin{cases}x=-1-1=-2\\x=1-1=0\end{cases}}\)

a) x+x+x+91=-2

    x.3          =(-2)-91

    x.3          = -93

    x             =(-93):3

    x             = -31

Trl:

a) \(x+x+x+91=-2\)

\(\Rightarrow x.3+91=-2\)

\(\Rightarrow x.3=-2-91\)

\(\Rightarrow x.3=-93\)

\(\Rightarrow x=-93:3\)

\(\Rightarrow x=-31\)

b) \(-125-\left(3x+1\right)=-2.27\)

\(\Rightarrow-125-\left(3x+1\right)=-54\)

\(\Rightarrow\left(3x+1\right)=-125-\left(-54\right)\)

\(\Rightarrow\left(3x+1\right)=-125+54\)

\(\Rightarrow\left(3x+1\right)=-71\)

\(\Rightarrow3x=-71-1\)

\(\Rightarrow3x=-72\)

\(\Rightarrow x=-72:3\)

\(\Rightarrow x=-24\)

Hc tốt

Câu a:

- \(\frac12\)(3 - 2\(x\)) - 7 = 5 - \(\frac13\)(\(x\) - \(\frac45\))

- \(\frac32\) + \(x\) - 7 = 5 - \(\frac13x\) + \(\frac{4}{15}\)

\(x\) + \(\frac13x\) = 5 + \(\frac{4}{15}\) + 7 + \(\frac32\)

(1 + \(\frac13\))\(x\) = \(\frac{150}{30}\) + \(\frac{8}{30}\) + \(\frac{210}{30}\) + \(\frac{45}{30}\)

\(\frac43x\) = \(\frac{158}{30}\) + \(\frac{210}{30}\) + \(\frac{45}{30}\)

\(\frac43x\) = \(\frac{368}{30}\) + \(\frac{45}{30}\)

\(\frac43x\) = \(\frac{413}{30}\)

\(x\) = \(\frac{413}{30}\) : \(\frac43\)

\(x\) = \(\frac{413}{40}\)

Vậy \(x=\frac{413}{40}\)

Câu b:

(5 - 3x/2) : - 1 3/8 = - 7 1/3

(5 - 3x/2) : (-11/8) = - 22/3

5 - 3x/2 = - 22/3 x (-11/8)

5 - 3x/2 = 121/12

3x/2 = 5 - 121/12

3x/2 = - 61/12

x = - 61/12 : 3/2

x = -61/18

Vậy x = - 61/18

Câu a:

\(\frac{-8}{3x-1}\) = \(\frac{4}{-7}\)

-8.(-7) = 4.(3\(x\) - 1)

56 = 12\(x\) - 4

12\(x\) = 56+ 4

12\(x\) = 60

\(x\) = 60 : 12

\(x\) = 5

Vậy \(x\) = 5

Câu b:

\(\frac{x}{-3}\) = \(\frac{-3}{x}\)

\(x^2\) = (-3)\(^2\)

\(\left[\begin{array}{l}x=-3\\ x=3\end{array}\right.\)

Vậy \(x\in\left\lbrace-3;3\right\rbrace\)

Câu c:

\(-\frac{4}{y}=\frac{x}{2}\)

-4.2 = \(x.y\)

\(xy=-8\)

Ư(8) = (-8; -4; -2; -1; 1; 2; 4; 8}

Vậy (\(x;y\)) = (-8; 1); (-4; 2); (-2; 4); (-1; 8); (1; -8); (2; -4); (4; -2); (8; -1)

Câu 2:

(\(x-1)\)(y + 2) = 7

Ư(7) = {-7; -1; 1; 7}

Lập bảng ta có:

Theo bảng trên ta có:

(\(x;y\)) = (-6; -3); (0; -9); (2; 5); (8; - 1)

Vậy (\(x;y\)) = (-6; -3); (0; -9); (2; 5); (8; -1)

0,5x-2/3x=7/12

=>(1/2-2/3).x=7/12

=>-1/6x=7/12

=>x=7/12:1/6

=>x=7/2

b, x:4 1/3=-2,5

=>x:13/3=-2,5

=>x=-5/2x13/3

=>x=-13

c,5,5x=13/15

=>11/2x=13/15

=>x=13/15:11/2

=>x=26/165

d,(3x/7+1):-4=-1/28

=>3x/7+1=-1/28x(-4)

=>3x/7+1=-1/7

=>3x/7=-1/7-1

=>3x/7=-8/7

=>3x=-8/7x7

=>3x=8

=>x=8:3

=>x=8/3

\(0,5x-\frac{2}{3}x=\frac{7}{12}\)

\(\frac{1}{2}x-\frac{2}{3}x=\frac{7}{12}\)

\(\left(\frac{1}{2}-\frac{2}{3}\right)x=\frac{7}{12}\)

\(\frac{-1}{6}x=\frac{7}{12}\)

\(x=-21\)

b,c,d tương tự

a) -152 - (3x + 1) = (-2).(-3)³

-152 - 3x - 1 = (-2).(-27)

-3x - 153 = 54

-3x = 54 + 153

-3x = 207

x = -69

b) x - 43 = (35 - x) - 48

x - 43 = 35 - x - 48

x - 43= -x - 13

x = -x - 13 + 43

x = 30 + x

x + x = 30

2x = 30

x = 15

x=22/7;-20/7

a) l 3x + 1l = 15

=>\(\hept{\begin{cases}3x+1=15\\3x+1=-15\end{cases}}\Rightarrow\hept{\begin{cases}x=\left(15-1\right):3=\frac{14}{3}\\x=\left(-15-1\right):3=\frac{-16}{3}\end{cases}}\)

a, |3x+1|=15

=>3x+1=15 hoặc -15

• Với 3x+1=15

=>3x=14

=>x=14/3

• Với 3x+1=-15

=>3x=-16

=>x=-16/3

b, (6x+12).(x-2)=0

=>6x+12=0 hoặc x-2=0

=>x=-2 hoặc x=2

c, 5.(x-3)+4=2(x+1)+7

=>5x-15+4=2x+2+7

=>5x-11=2x+9

=>3x=20

=>x=20/3

d chịu

\(x+\frac{3x}{4}=\frac{7}{2}\)

\(x+3x.\frac{1}{4}=\frac{7}{2}\)

\(x.\left(1+3.\frac{1}{4}\right)=\frac{7}{2}\)

\(x.\left(1+\frac{3}{4}\right)=\frac{7}{2}\)

\(x.\frac{7}{4}=\frac{7}{2}\)

\(x=\frac{7}{2}:\frac{7}{4}\)

\(x=2\)

\(x+\frac{3x}{4}=\frac{7}{2}\)

\(\Rightarrow\frac{4x+3x}{4}=\frac{7}{2}\)

\(\Rightarrow\frac{7x}{4}=\frac{14}{4}\)

\(\Rightarrow7x=14\)

\(\Rightarrow x=14:7\)

\(\Rightarrow x=2\)

Vậy x = 2

_Chúc bạn học tốt_