1/41>3/124>5/207>2/83

Ta co

3/124=30/1240

1/41=30/1230

5/207=30/1242

2/83=30/1245

k cho mik nha!

2                                                                

2                            

452

Đổi hết ra số thập phân mà so sánh ý bạn.

Vậy bạn đổi và làm giúp mình với

Các câu a,b,c,d,e thì bạn sử quy đồng mẫu số hoặc tử số,mình chỉ làm câu h thôi

\(\dfrac{54.107-53}{53.107+54}\)=\(\dfrac{\left(53+1\right).107-53}{53.107+54}\)=\(\dfrac{53.107+107-53}{53.107+54}\)=\(\dfrac{53.107+54}{53.107+54}\)=1

B=\(\dfrac{135.269-133}{134.269+135}\)=\(\dfrac{\left(134+1\right).269-133}{134.269+135}\)=\(\dfrac{134.269+269-133}{134.269+135}\)=

\(\dfrac{134.269+136}{134.269+135}\)>1

=) A<B

a , \(\dfrac{2}{3}\) > \(\dfrac{1}{2}\) > \(\dfrac{1}{3}\)

b , \(\dfrac{4}{41}\) > \(\dfrac{2}{83}\) > \(\dfrac{3}{124}\) > \(\dfrac{5}{207}\)

c , \(\dfrac{24}{13}\) > \(\dfrac{16}{19}\)

d , \(\dfrac{26}{75}\) < \(\dfrac{27}{82}\)

Câu h đã có bạn làm cho nên mk ko làm nữa!

\(\frac{x-28-124}{2011}+\frac{x-124-2011}{28}+\frac{x-2011-28}{124}=3\)

<=> \(\left(\frac{x-152}{2011}-1\right)+\left(\frac{x-2135}{28}-1\right)+\left(\frac{x-2039}{124}-1\right)=0\)

<=> \(\frac{x-2163}{2011}+\frac{x-2163}{28}+\frac{x-2163}{124}=0\)

<=> \(\left(x-2163\right)\left(\frac{1}{2011}+\frac{1}{28}+\frac{1}{124}\right)=0\)

<=> \(x-2163=0\)(vì \(\frac{1}{2011}+\frac{1}{28}+\frac{1}{124}\ne0\)

<=> \(x=2163\)

\(\frac{x-28-124}{2011}+\frac{x-124-2011}{28}+\frac{x-2011-28}{124}=3\)

<=> \(\frac{x-28-124}{2011}+\frac{x-124-2011}{28}+\frac{x-2011-28}{124}-3=0\)

<=> \(\left(\frac{x-28-124}{2011}-1\right)+\left(\frac{x-124-2011}{28}-1\right)+\left(\frac{x-2011-28}{124}-1\right)=0\)

<=> \(\frac{x-28-124-2011}{2011}+\frac{x-124-2011-28}{28}+\frac{x-2011-28-124}{124}=0\)

<=> \(\frac{x-2163}{2011}+\frac{x-2163}{28}+\frac{x-2163}{124}=0\)

<=> \(\left(x-2163\right)\left(\frac{1}{2011}+\frac{1}{28}+\frac{1}{124}\right)=0\)

Vì \(\frac{1}{2011}+\frac{1}{28}+\frac{1}{124}\ne0\)

=> \(x-2163=0\)

=> \(x=2163\)