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1/41>3/124>5/207>2/83
Ta co
3/124=30/1240
1/41=30/1230
5/207=30/1242
2/83=30/1245
k cho mik nha!
7/41 + 5/9 + -7/41 + 16 / 9
\(= \frac{7}{41} - \frac{7}{41} + \frac{5}{9} + \frac{16}{9}\)
\(\frac{7}{41} - \frac{7}{41} = 0\)
\(0 + \frac{5}{9} + \frac{16}{9}\)
\(\frac{5}{9} + \frac{16}{9} = \frac{21}{9}\)
\(\frac{21}{9}=\frac{7}{3}\)
**Trả lời:
\(\frac{7}{41}+\frac59+\frac{-7}{41}+\frac{16}{9}\)
\(=\left(\frac{7}{41}+\frac{-7}{41}\right)+\left(\frac59+\frac{16}{9}\right)\)
\(=0+\frac{21}{9}\)
\(=\frac{21}{9}.\)
a/ \(\left(x-35\right)-120=0\)
\(\Leftrightarrow x-35=0+120\)
\(\Leftrightarrow x-35=120\)
\(\Leftrightarrow x=120+35\)
\(\Leftrightarrow x=155\)
Vậy ...
b/ \(124+\left(188-x\right)=217\)
\(\Leftrightarrow188-x=217-124\)
\(\Leftrightarrow188-x=93\)
\(\Leftrightarrow x=95\)
Vậy ...
b/ \(156-\left(x+61\right)=82\)
\(\Leftrightarrow x+61=74\)
\(\Leftrightarrow x=13\)
Vậy ..
a,\(=\frac{-5}{9}+\frac{8}{15}+\frac{-2}{11}+\frac{-4}{9}+\frac{7}{15}\)
\(\left(\frac{-5}{9}+\frac{-4}{9}\right)+\left(\frac{8}{15}+\frac{7}{15}\right)+\frac{-2}{11}\)
=-1+1+-2/11
=0+-2/11
=-2/11
b,\(=\left(\frac{5}{13}+\frac{8}{13}\right)+\left(\frac{-20}{41}+\frac{-21}{40}\right)+\frac{-5}{17}\)
=1+-1+-5/17
=0+-5/17
=-5/17
c,\(=\left(\frac{1}{5}+\frac{4}{5}\right)+\left(\frac{-2}{9}+-\frac{7}{9}\right)+\frac{16}{17}\)
=1+-1+16/17
=0+16/17
=16/17
d,\(=\frac{1}{3}-\frac{1}{5}+\frac{1}{5}-\frac{1}{7}+\frac{1}{7}-\frac{1}{9}+...+\frac{1}{99}-\frac{1}{101}\)
\(=\frac{1}{3}-\frac{1}{101}=\frac{98}{303}\)
a.\(\frac{-5}{9}\)+\(\frac{8}{15}\)+\(\frac{-2}{11}\)+\(\frac{4}{-9}\)+\(\frac{7}{15}\)
=\(\frac{-5}{9}\)+\(\frac{4}{-9}\)+\(\frac{8}{15}\)+\(\frac{7}{15}\)+\(\frac{-2}{11}\)
=(\(\frac{-5}{9}\)+\(\frac{-4}{9}\))+(\(\frac{8}{15}\)+\(\frac{7}{15}\))+\(\frac{-2}{11}\)
=(-1)+1+\(\frac{-2}{11}\)
=0+\(\frac{-2}{11}\)
=\(\frac{-2}{11}\).
a) x : 13 = 41
x=533
b) 1428 : x = 14
x=102
c) 4x : 17 = 0
4x=0
x=0
d)7x – 8 = 713
7x=721
x=103
e) 8 . (x – 3) = 0
x-3=0
x=3
f) 0 : x = 0
x=0
=-165
-124-41=165
nhầm , -165
-165