Bài 7:

3 . 2⁴ - 2 . 2⁴

= (3 - 2) . 2⁴

= 1 . 2⁴

= 2⁴.

633 - { [(105 + 3) : 3] - 3}

= 633 - { [108 : 3] - 3}

= 633 - {36 - 3}

= 633 - 33

= 600.

Bài 9:

4^{x - 3} - 3 . 4² = 4²

4^{x - 3} - 3 . 16 = 16

4^{x - 3} - 48 = 16

4^{x - 3} = 16 + 48

4^{x - 3} = 64

\(\Rightarrow\) 4^{x - 3} = 4³

\(\Rightarrow\) x - 3 = 3

x = 3 + 3

x = 6.

\(3.2^4-2.2^4\)

\(=2^4.\left(3-2\right)\)

\(=2^4.1\)

\(=2^4=16\)

.

\(633-\left\{\left[\left(105+3\right):3\right]-3\right\}\)

\(=633-\left\{\left[108:3\right]-3\right\}\)

\(=633-\left\{36-3\right\}\)

\(=633-33\)

\(=600\)

.

\(4^{x-3}-3.4^2=4^2\)

\(4^{x-3}-4^2=3.4^2\)

\(4^{x-3}-4^2=48\)

\(4^{x-3}=48+4^2\)

\(4^{x-3}=64\)

Ta có: \(4^3=64\)

\(\Rightarrow4^{x-3}=4^3\)

\(\Rightarrow4^x:4^3=4^3\)

\(\Rightarrow4^x=4^3:4^3\)

\(4^x=4^0\)

\(\Rightarrow x=0\)

Vậy \(x=0\)

. Ko hiểu gì hỏi mình nha <3

Ngoặc cuối cùng bằng 0 suy ra A=0

\(A=\left(2^2+2^3+2^4+2^5 \right).\left(3^2+3^3+3^4\right)\left(2^4-4^2\right)\) 

\(=\left(2^2+2^3+2^4+2^5\right).\left(3^2+3^3+3^4\right).\left(16-16\right)\) 

\(=0\)

NHớ tick và theo dõi mik nhá!

2: \(=234+29-80+52^3=140791\)

3: \(=45\cdot\left(3250-225\right)=45\cdot3025=136125\)

4: \(=\left[\left(192-3\right):3\right]^2=63^2=3969\)

a, \(\dfrac{-7}{9}.2\dfrac{3}{4}\)

= \(\dfrac{-7}{9}.\dfrac{11}{4}\)

= \(\dfrac{-77}{36}\)

b, \(\dfrac{2}{3}+\dfrac{1}{3}.\dfrac{-2}{5}\)

= \(\dfrac{2}{3}+\dfrac{-2}{15}\)

= \(\dfrac{10}{15}+\dfrac{-2}{15}\)

= \(\dfrac{-8}{15}\)

c , \(\dfrac{2}{3}-4\left(\dfrac{1}{2}+\dfrac{3}{4}\right)\)

= \(\dfrac{2}{3}-4.\dfrac{5}{4}\)

= \(\dfrac{2}{3}-5\)

= \(\dfrac{-13}{3}\)

d, \(\left(\dfrac{1}{-3}+\dfrac{5}{6}\right).11-7\)

= \(\dfrac{1}{2}\) . 11 - 7

= \(\dfrac{11}{2}-\dfrac{14}{2}\)

= \(\dfrac{-3}{2}\)

e, \(\dfrac{3}{4}.15\dfrac{1}{3}-\dfrac{3}{4}.43\dfrac{1}{3}\)

= \(\dfrac{3}{4}.\left(15\dfrac{1}{3}-43\dfrac{1}{3}\right)\)

= \(\dfrac{3}{4}.-28\)

= \(-21\)

\(8-12x+6x^2-x^3\)

\(=\left(2-x\right)^3\)

\(125x^3-75x^2+15x-1\)

\(=\left(5x-1\right)^3\)

\(x^2-xz-9y^2+3yz\)

\(=\left(x-3y\right)\left(x+3y\right)-z\left(x-3y\right)\)

\(=\left(x-3y\right)\left(x+3y-z\right)\)

\(x^3-x^2-5x+125\)

\(=\left(x+5\right)\left(x^2-5x+25\right)-x\left(x+5\right)\)

\(=\left(x+5\right)\left(x^2-5x+25-x\right)\)

\(=\left(x+5\right)\left(x^2-6x+25\right)\)

\(x^3+2x^2-6x-27\)

\(=x^3+5x^2+9x-3x^2-15x-27\)

\(=x\left(x^2+5x+9\right)-3\left(x^2+5x+9\right)\)

\(=\left(x-3\right)\left(x^2+5x+9\right)\)

\(12x^3+4x^2-27x-9\)

\(=4x^2\left(3x+1\right)-9\left(3x+1\right)\)

\(=\left(3x+1\right)\left(4x^2-9\right)\)

\(=\left(3x+1\right)\left(2x-3\right)\left(2x+3\right)\)

\(4x^4+4x^3-x^2-x\)

\(=4x^3\left(x+1\right)-x\left(x+1\right)\)

\(=x\left(x+1\right)\left(4x^2-1\right)\)

\(=x\left(x+1\right)\left(2x-1\right)\left(2x+1\right)\)

Là 00000000000000

1:

a)10/20-15/20+16/20=-5/20+16/20

=11/20.

b)2/3+8/3:8/5=2/3+5/3

=7/3.

2:a)Ta có:

2x=1/4=3/4

2x=4/4=1

x=1:2

x=0,5

b)x:(2/12-1/12)=-3/8.

x:1/12=-3/8.

x=-3/8x1/12.

x=-1/32.

\(A=1+3+3^2+.....+3^{100}\)

\(3A=3+3^2+3^3+.....+3^{101}\)

\(3A-A=3+3^2+3^3+.....+3^{101}-\left(1+3+3^{^2}+....+3^{100}\right)\)

\(2A=3+3^2+3^3+....+3^{101}-1-3-3^2-.....-3^{100}\)

\(2A=3^{101}-1\)

\(A=\frac{3^{101}-1}{2}\)

\(a)\) \(S=1+2+2^2+2^3+...+2^{2017}\)

\(2S=2+2^2+2^3+2^4+...+2^{2018}\)

\(2S-S=\left(2+2^2+2^3+2^4+...+2^{2018}\right)-\left(1+2+2^2+2^3+...+2^{2017}\right)\)

\(S=2^{2018}-1\)

\(b)\) \(S=3+3^2+3^3+...+3^{2017}\)

\(3S=3^2+3^3+3^4+...+3^{2018}\)

\(3S-S=\left(3^2+3^3+3^4+...+3^{2018}\right)-\left(3+3^2+3^3+...+3^{2017}\right)\)

\(2S=3^{2018}-3\)

\(S=\frac{3^{2018}-3}{2}\)

\(c)\) \(S=4+4^2+4^3+...+4^{2017}\)

\(4S=4^2+4^3+4^4+...+4^{2018}\)

\(4S-S=\left(4^2+4^3+4^4+...+4^{2018}\right)-\left(4+4^2+4^3+...+4^{2017}\right)\)

\(3S=4^{2018}-4\)

\(S=\frac{4^{2018}-4}{3}\)

\(d)\) \(S=5+5^2+5^3+...+5^{2017}\)

\(5S=5^2+5^3+5^4+...+5^{2018}\)

\(5S-S=\left(5^2+5^3+5^4+...+5^{2018}\right)-\left(5+5^2+5^3+...+5^{2017}\right)\)

\(4S=5^{2018}-5\)

\(S=\frac{5^{2018}-5}{2}\)

Chúc em học tốt ~ 

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