Ta có: \(\left(2008-\dfrac{2}{135}+\dfrac{1}{50}\right)-\left(1-\dfrac{7}{135}+\dfrac{4}{150}\right)-\left(5+\dfrac{5}{135}+\dfrac{3}{50}\right)\)

= \(2008-\dfrac{2}{135}+\dfrac{1}{50}-1+\dfrac{7}{135}-\dfrac{4}{150}-5-\dfrac{5}{135}-\dfrac{3}{50}\)

= (2008-1-5) + \(\left(\dfrac{1}{50}-\dfrac{3}{50}\right)-\left(\dfrac{2}{135}-\dfrac{7}{135}\right)-\dfrac{4}{150}\)

=2002 \(-\dfrac{1}{25}\)+\(\dfrac{1}{27}\)\(-\dfrac{4}{150}\)

=2001,9(3)

hình như sai sai đó bạn

\(2\times3^{x+1}+3^{x+2}=135\)

\(3^{x+1}\left(2+3\right)=135\)

\(3^{x+1}\times5=135\)

\(3^{x+1}=\frac{135}{5}\)

\(3^{x+1}=27\)

\(3^{x+1}=3^3\)

x + 1 = 3

x = 3 - 1

x = 2

15 . ( 3 + 42 : x ) = 135

           3 + 42 : x = 135 : 15

                 42 : x = 9 - 3

                 42 : x = 6

                        x = 42 : 6

                        x = 7

3+42:x=135:15

3+42:x=9

42:x=9-3

42:x=6

x=42:6

x=7

\(\left(2018-\frac{2}{135}+\frac{1}{50}\right)-\left(1-\frac{7}{135}+\frac{4}{50}\right)-\left(5+\frac{5}{135}+\frac{3}{50}\right)\)

\(=2018-\frac{2}{135}+\frac{1}{50}-1+\frac{7}{135}-\frac{4}{50}-5-\frac{5}{135}-\frac{3}{50}\)

\(=2012-\frac{6}{50}\)

135 - 5( x + 4 ) = 35

         5( x + 4 ) = 135 - 35 

         5( x + 4 ) = 100

               x + 4 = 100 : 5

               x + 4 = 20

                    x = 20 - 4

                    x = 16

             Vậy x = 16 

\(135-5\left(x+4\right)=35\)

   \(5\left(x+4\right)\)       \(=135-35=100\)

                     \(x+4=100:5=20\)

                           \(x=20-4=16\)

a)\(\frac{x}{15}=\frac{2}{5}\)=> x=\(\frac{15.2}{5}=6\)

b) \(\frac{3}{x^7}hay\frac{3}{x.7}\)

\(a,-13-\left(-15\right)=-13+15=2\)

\(b,43-\left(56-43\right)+\left(56-12\right)=43-13+44=30+44=74\)

\(c,4^4:2^8+\left[13-\left(-5\right)\right]\cdot\left(-3\right)=256:256+\left(13+5\right)\cdot\left(-3\right)\)\(=1+18\cdot\left(-3\right)=1+\left(-54\right)=-53\)

\(d,135\cdot\left(13-37\right)+37\cdot\left(135-13\right)=135\cdot\left(-24\right)+37\cdot122\)\(=-3240+4514=1274\)

a, -13-(-15)=-13+15=2

b, 43-(56-43)+(56-12)=43-13+44=30+44=74

c, 4^4:2^8+[13-(-5)].(-3)=256:256+(13+5).(-3)=1+18.(-3)=1+(-54)=-53

d, 135.(13-37)+37.(135-13)=135.(-24)+37.122=-3240+4514=1274

A=\(\frac{54.107-53}{53.107+54}\)

  = \(\frac{54.\left(106+1\right)-53}{53.107+53+1}\)

  = \(\frac{54.106+54-53}{53.\left(107+1\right)+1}\)

  = \(\frac{54.106+1}{53.108+1}\)

mà \(54.106=53.108\)

=> \(\frac{54.106+1}{53.108+1}=1\)

B = \(\frac{135.269-133}{134.269+135}\)

   = \(\frac{135.\left(268+1\right)-133}{134.269+134+1}\)

   = \(\frac{135.268+135-133}{134.\left(269+1\right)+1}\)

   = \(\frac{135.268+2}{134.270+1}\)

Mà \(135.268=134.270\)

=> \(\frac{135.268+2}{134.270+1}=\frac{135.268+1+1}{134.270+1}\)  

\(=\frac{135.268+1}{134.270+1}+\frac{1}{134.270+1}\)

  \(=1+\frac{1}{134.270+1}>1\) 

=> B > 1 

=> B > A