4 . 2^x - 3 = 125 

4 . 2^x = 125 + 3

4 .2^x = 128

2^x = 128 : 4

2^x = 32

2^x = 2⁵

=> x = 5

Hok tốt

Bài 1:

6) 3x + 2³ = 17 + 3²

3x + 8 = 17 + 9

3x + 8 = 26

3x = 26 - 8

3x = 18

x = 18 : 3

x = 6

Vậy x = 6

Bài 2:

3) 145 - (125 + x) = 12

125 + x = 145 - 12

125 + x = 133

x = 133 - 125

x = 8

Vậy x = 8

6) 3³ - (x - 5) = 2²

27 - (x - 5) = 4

x - 5 = 27 - 4

x - 5 = 23

x = 23 + 5

x = 28

Vậy x = 28

9) (x + 7) - 15⁰ = 202 - 19

(x + 7) - 1 = 189

x + 7 = 189 + 1

x + 7 = 190

x = 190 - 7

x - 183

Vậy x = 183

a,   \(2^x-15=17\)

\(\Rightarrow2^x=17+15\)

\(\Rightarrow2^x=32\)

\(\Rightarrow2^x=2^5\)

\(\Rightarrow x=5\)

b,   \(\left(7x-11\right)^3=2^5.5^2+200\)

\(\Rightarrow\left(7x-11\right)^3=32.25+200\)

\(\Rightarrow\left(7x-11\right)^3=1000\)

\(\Rightarrow\left(7x-11\right)^3=10^3\)

\(\Rightarrow7x-11=10\)

\(\Rightarrow7x=10+11\)

\(\Rightarrow7x=21\)

\(\Rightarrow x=21:7\)

\(\Rightarrow x=3\)

c,   \(x^{10}=1^x\)

\(\Rightarrow x\in\left\{1;0\right\}\)

\(2^x-15=17\)

\(\Rightarrow2^x=17+15\)

\(\Rightarrow2^x=32=2^4\)

\(\Rightarrow x=4\)

\(\left(7x-11\right)^3=2^5.5^2+200\)

Phần này mk ko bt làm đâu

\(x^{10}=1^x\)

\(\Rightarrow\)\(x^{10}=1\)

\(\Rightarrow x=1\)

Ta có: \(A=3+3^2+\cdots+3^{100}\)

=>\(3A=3^2+3^3+\cdots+3^{101}\)

=>\(3A-A=3^2+3^3+\cdots+3^{101}-3-3^2-\cdots-3^{100}\)

=>\(2A=3^{101}-3\)

=>\(2A+3=3^{101}\)

=>\(3^{x+1}=3^{101}\)

=>x+1=101

=>x=100

k

2^1+2^3+2^4+2^5+2^6+2^7+2^8+2^9+2^10+2^11+2^12+2^13+..... á?

2^x = 4³ : 2⁵

2^x = (2²)³ : 2⁵

2^x = 2⁶ : 2⁵

2^x = 2

=> x = 1

viết kiểu gì ko hiểu

kkkkk

\(a,70-5\times\left(x-3\right)=45\)

\(5\times\left(x-3\right)=70-45\)

\(5\times\left(x-3\right)=25\)

\(x-3=25:5\)

x - 3 = 5

x = 5 + 3 = 8

vậy x = 8

\(b,12+\left(5+x\right)=20\)

12 + 5 + x = 20

17 + x = 20

x = 20 - 17 = 3

vậy x = 3

c, 130 - (100 + x) = 25

130 - 100 - x = 25

30 - x = 25

x = 30 - 25 = 5

vậy x = 5

\(g,10+2\times x=4^5:4^3\)

\(10+2\times x=4^2\)

\(10+2\times x=16\)

\(2\times x=16-10\)

\(2\times x=6\)

x = 6 : 2 = 3

vậy x = 3

h, \(14\times x+54=82\)

\(14\times x=82-54\)

\(14\times x=28\)

\(x=28:14=2\)

vậy x = 2

\(k,15\times x-133=17\)

\(15\times x=17+133\)

\(15\times x=150\)

\(x=150:15=10\)

vậy x = 10

Câu a mình ko bt trình bày thông cảm

b) \(^{2^x.\left(2^2\right)^2=\left(2^3\right)^2}\)

\(2^x.2^4=2^6\)

\(2^x=2^6:2^4\)

\(2^x=2^2\)

\(x=2\)

a)(x^5)^10=x<=>x=0 hoặc 1