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20,05*14+40,1*16+60,15*18
=20,05*14+20,05*2*16+20,05*3*18
=20,05*14+20,05*32+20,05*54
=20,05*(14+32+54)
=20,05*100
=2005
20,05*14+40,1*16+16+60,15*18
=20,05*14+20,05*2*16+20,05*3*18+16
=20,05*14+20,05*32+20,05*54+16
=20,05*(14+32+54)+16
=20,05*100+16
=2005+16
=2021
45,6 dam2 = 4560 m2
4,05 hm22= 40500 m2
9,1 km22= 9100000 m22
5,05 km22= 505 hm22
6,003 kg = 6003 g
2, 05 kg = 2050 g
\(B=\frac{2}{8}+\frac{2}{24}+\frac{2}{48}+...+\frac{2}{18\cdot20}\)
\(B=\frac{2}{2\cdot4}+\frac{2}{4\cdot6}+\frac{2}{6\cdot8}+...+\frac{2}{18\cdot20}\)
\(B=\frac{1}{2}-\frac{1}{4}+\frac{1}{4}-\frac{1}{6}+\frac{1}{6}-\frac{1}{8}+...+\frac{1}{18}-\frac{1}{20}\)
\(B=\frac{1}{2}-\frac{1}{20}\)
\(B=\frac{9}{20}\)
=))
\(A=\frac{1}{6}+\frac{1}{12}+\frac{1}{20}+\frac{1}{30}+\frac{1}{42}+\frac{1}{56}+\frac{1}{72}+\frac{1}{90}\)
\(A=\frac{1}{2.3}+\frac{1}{3.4}+\frac{1}{4.5}+\frac{1}{5.6}+\frac{1}{6.7}+\frac{1}{7.8}+\frac{1}{8.9}+\frac{1}{9.10}\)
\(A=\frac{1}{2}-\frac{1}{3}+\frac{1}{3}-\frac{1}{4}+...+\frac{1}{9}-\frac{1}{10}\)
\(A=\frac{1}{2}+\left(\frac{1}{3}-\frac{1}{3}\right)+\left(\frac{1}{4}-\frac{1}{4}\right)+...+\left(\frac{1}{9}-\frac{1}{9}\right)-\frac{1}{10}\)
\(A=\frac{1}{2}-\frac{1}{10}=\frac{2}{5}\)
\(\frac{aaa}{37\times y}=a\)
\(\Rightarrow37\times y=aaa:a\)
\(37\times y=\frac{aaa}{a}=\frac{111.a}{a}=111\)
\(\Rightarrow37\times y=111\)
\(y=111:37\)
\(y=3\)
\(\frac{\overline{aaa}}{37Y}=a\Leftrightarrow37Y=\frac{\overline{aaa}}{a}=111\Leftrightarrow Y=3\)
Vậy số đó là 3
a.8a+a7=aa+87
ta có:
8a+a7=80+a+a*10+7=80+7+a+a*10=87+aa
b.6a+a8>(a+6)x11
ta có:
6a+a8=60+a+a*10+8=60+8+a*10+a=68+aa
(a+6)x11=a*11+6*11=11a+66=10a+a+66=aa+66
Xin lỗi mk nhầm
đề là:
\(1\cdot2\cdot3\cdot4\cdot...\cdot99999999999+\left(\frac{1}{2}+\frac{2}{1}+0,5-1+3-5\right)\)
1