X:2

\(2^{x}.4=16\)

\(\Rightarrow2^{x}.2^2=2^4\) \(2^{x}=2^4:2^2=2^2\) \(\Rightarrow x=2\)

a, 15 - 2 | x + \(\dfrac{1}{3}\)| = \(\dfrac{4}{7}\)

=>2| x + \(\dfrac{1}{3}\)| = 15 - \(\dfrac{4}{7}\)

=> 2 | x + \(\dfrac{1}{3}\)| =\(\dfrac{101}{7}\)

=> | x + \(\dfrac{1}{3}\)| = \(\dfrac{101}{14}\)

=> x+ \(\dfrac{1}{3}\)= \(\dfrac{101}{14}\) hoặc x +\(\dfrac{1}{3}\)= - \(\dfrac{101}{14}\)

+) x+\(\dfrac{1}{3}\)= \(\dfrac{101}{14}\)=> x = \(\dfrac{302}{3}\)

+) x + \(\dfrac{1}{3}\)= - \(\dfrac{101}{14}\)=> x =-\(\dfrac{317}{42}\)

Vậy ...........

b, \(\dfrac{13}{11}\).\(\dfrac{22}{26}\)-x²=\(\dfrac{7}{16}\)

=>1 -x² = \(\dfrac{7}{16}\)

=> x²= \(\dfrac{9}{16}\)

=> x= \(\dfrac{3}{4}\)hoặc x = -\(\dfrac{3}{4}\)

Vậy ..................

\(a,15-2\left|x+\dfrac{1}{3}\right|=\dfrac{4}{7}\)

\(2\left|x+\dfrac{1}{3}\right|=15-\dfrac{4}{7}\)

\(2\left|x+\dfrac{1}{3}\right|=\dfrac{101}{7}\)

\(\left|x+\dfrac{1}{3}\right|=\dfrac{101}{7}:2\)

\(\left|x+\dfrac{1}{3}\right|=\dfrac{101}{14}\)

\(\Rightarrow x+\dfrac{1}{3}=\dfrac{101}{14}\) hoặc \(x+\dfrac{1}{3}=-\dfrac{101}{14}\)

\(x=\dfrac{101}{14}-\dfrac{1}{3}\) \(x=-\dfrac{101}{14}-\dfrac{1}{3}\)

\(x=\dfrac{302}{3}\) \(x=-\dfrac{317}{42}\)

a)\(3^2.3^x=243\)

    \(3^2.3^x=3^5\)

    \(3^x=3^5:3^2\)

     \(3^x=3^3\)

\(\Rightarrow x=3\)

b)\(2^x.16^2=1024\)

    \(2^x.\left(2^4\right)^2=2^{10}\)

            \(2^x.2^8=2^{10}\)

                  \(2^x=2^{10}:2^8\)

                  \(2^x=2^2\)

              \(\Rightarrow x=2\)

Học tốt nha^^

3^2.3=243 vậy x=3

2^x.16^2=1024 vậy x=2

64.4^x=16^8 vậy x=13

2^x-26=6 vậy x=5

phần cuối đề sai

a/\(\frac{13}{11}.\frac{22}{26}-x^2=\frac{7}{16}\)

\(\Rightarrow1-x^2=\frac{7}{16}\)

\(\Rightarrow x^2=\frac{9}{16}\)

\(\Rightarrow x=\orbr{\begin{cases}\frac{3}{4}\\-\frac{3}{4}\end{cases}}\)

\(a,\frac{13}{11}.\frac{22}{26}-x^2=\frac{7}{16}\)

\(1-x^2=\frac{7}{16}\)

\(x^2=1-\frac{7}{16}=\frac{9}{16}\)

\(\Rightarrow\orbr{\begin{cases}x=\frac{3}{4}\\x=-\frac{3}{4}\end{cases}}\)

\(b,x^2+-\frac{9}{25}=\frac{2}{5}.\frac{8}{5}\)

\(x^2+-\frac{9}{25}=\frac{16}{25}\)

\(x^2=\frac{16}{25}--\frac{9}{25}=1\)

\(\Rightarrow\orbr{\begin{cases}x=1\\x=-1\end{cases}}\)

học tốt ~~~

a)3x+26=5

  3x      =5-26

 3x       =-21

  x       =-21:3

  x=-7

b)|x+3|=0

x=0-3

x=-3

c)2|x+1|=10

     |x+1|=10:2

     |x+1|=5

+)x+1=5             +)x+1=-5

  x=5-1                   x=-5-1

  x=4                      x=-6

d)|x-1|+2=15

   |x-1|   =15-2

   |x-1|  =13

+)x-1=13              +)x-1=-13

  x=13+1                     x=-13+1

  x=14                         x=-12

e)2^x+2=16

  x=2

cau b)chua chac

a,

3x=5-26

3x=-21

x= -21:3

x=-7

b, /x/=0-3

/x/=-3

Vì giá trị tuyệt đối của 1 số luôn là 1 số nguyên dương mà /x/=-3 nên ko có giá trị x nào thỏa mãn

c,/x+1/=10:2

/x+1/=5

=>x+1=5 hoặc x+1=-5

=> x=5-1=4 hoăc x=-5-1=-6

Vậy x=4 hoặc x=-6

Còn lại câu D, cũng tương tự

cho mình nha

26 + 18x = 16x + 146

=> 18x - 16x = 146 - 26

=> 2x = 120

=> x = 60

Vậy: x = 60

Ta có : 26 + 18x = 16x + 146

=> 18x - 16x = 146 - 26

=> 2x = 120

=> x = 60

Vậy x = 60

 \(\frac{15}{26}+\frac{x}{16}=\frac{46}{52}\)

\(\frac{x}{16}=\frac{46}{52}-\frac{15}{26}\)

\(\frac{x}{16}=\frac{4}{13}\)

\(< =>\frac{x}{208}=\frac{64}{208}=\frac{4}{13}\)

                    \(x=4\)

\(\frac{15}{26}+\frac{x}{16}=\frac{46}{52}\)

\(\Rightarrow\frac{15}{26}+\frac{x}{16}=\frac{23}{26}\)

\(\Rightarrow\frac{x}{16}=\frac{23}{26}-\frac{15}{26}\)

\(\Rightarrow\frac{x}{16}=\frac{4}{13}\)

\(\Rightarrow13x=4.16\)

\(\Rightarrow13x=64\)

\(\Rightarrow x=64:13\)

\(\Rightarrow x=\frac{64}{13}\)

Vậy x = \(\frac{64}{13}\)

_Chúc bạn học tốt_

\(\Rightarrow36^{15}<6^x<36^{16}\Rightarrow6^{30}<6^x<6^{32}\Rightarrow30

\(4^{15}.9^{15}<2^{^x}.3^x<2^{16}.18^{16}\)

\(\Rightarrow36^{15}<6^x<36^{16}\)

\(\Rightarrow\left(6^2\right)^{15}<6^x<\left(6^2\right)^{16}\)

\(\Rightarrow6^{30}<6^x<6^{32}\)

=> 30<x<32

\(\Rightarrow x=31\)

bạn làm đúng rồi nhé

chúc bạn học tốt@

bạn ơi có ai trả lời đâu mà bạn bảo đúng thế bạn

\(A=\dfrac{5}{11.16}+\dfrac{5}{16.21}+\dfrac{5}{21.26}+...............+\dfrac{5}{61.66}\)

\(\Leftrightarrow A=\dfrac{1}{11}-\dfrac{1}{16}+\dfrac{1}{16}-\dfrac{1}{21}+\dfrac{1}{21}-\dfrac{1}{26}+............+\dfrac{1}{61}-\dfrac{1}{66}\)

\(\Leftrightarrow A=\dfrac{1}{11}-\dfrac{1}{66}=\dfrac{5}{66}\)

\(A=\dfrac{5}{11\times16}+\dfrac{5}{16\times21}+\dfrac{5}{21\times26}+...+\dfrac{5}{61\times66}\)

\(=\dfrac{1}{11}-\dfrac{1}{16}+\dfrac{1}{16}-\dfrac{1}{21}+\dfrac{1}{21}-\dfrac{1}{26}+...+\dfrac{1}{61}-\dfrac{1}{66}\)

\(=\dfrac{1}{11}-\dfrac{1}{66}\)

\(=\dfrac{5}{66}\)

~ Học tốt ~