a)\(\frac{25.4-0,5\cdot40\cdot0,2\cdot20\cdot0,25}{1+2+8+...+129+156}\)

\(=\frac{100-100}{1+2+8+...+156}\)

\(=\frac{0}{1+2+8+...+156}\)

\(=0\)

b)\(\frac{0,5\cdot40-0,5\cdot20\cdot8\cdot0,1\cdot0,25\cdot10}{128:8.16.4\left(4+52:4\right)}=\frac{20-20}{128:8.16.4.\left(4+52:4\right)}=\frac{0}{128:8.16.4.\left(4+52:4\right)}=0\)

Chỉ biết \(x\) = \(\frac{109}{6075}\) thôi

Ta có:1/2-1/3+1/3-1/4+...+1/a-1/(a+1)

=>1/2-1/(a+1)

a)13x3x32,27+67,63x39

=39x32,27+67,63x39

=39x(32,27+67,63)

=39x100

=3900

b,= 1- [ 1/2 x 1/3 x1/4 x..... x 1/100 ]

=1/2 x 2/3 x 3/4 x .......x 99/100

= 1x2x3x......x99 / 2x3x4x...... x100 [ rút gọn ]

= 1/100

a)\(\frac{13}{15}+\frac{13}{35}+\frac{13}{63}+\frac{13}{99}\)

\(=\frac{13}{3.5}+\frac{13}{5.7}+\frac{13}{7.9}+\frac{13}{9.11}\)

\(=\frac{13}{2}\left(\frac{1}{3}-\frac{1}{5}+.....+\frac{1}{9}-\frac{1}{11}\right)\)

\(=\frac{13}{2}\left(\frac{1}{3}-\frac{1}{11}\right)\)

\(=\frac{13}{2}\cdot\frac{8}{33}\)

\(=\frac{52}{33}\)

a) Đặt A= 13/15 + 13/35 + 13/63 + 13/99

A = 13/2 ( 2/15 + 2/35 + 2/63 + 2/99)

A= 13/2 ( 2/ 3.5 + 2/5.7 + 2/7.9 + 2/9.11)

A= 13/2 ( 1/3 - 1/5 + 1/5 - 1/7 + 1/7 - 1/9 + 1/9 - 1/11)

A= 13/2 ( 1/3 - 1/11) 

A= 13/2 . 8/33

A= 52/33  

hình như bài này là dạng chuỗi

Bước 1: \(\left(\frac{1}{3\times5}+\frac{1}{5\times7}+\frac{1}{7\times9}+...+\frac{1}{19\times21}\right)=\frac{1}{7}\)

Bước 2: \(x=\frac{9}{7}\div\frac{1}{7}=9\)

= 8 832 600

 Bạn Nguyễn Huyền Diệu Hương ơi, đáp án cô giáo mình bảo ra 504