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a) => 4/3x = 7/9 - 4/9 = 1/3
=> x = 1/3 : 4/3 = 1/4
b) => 5/2 - x = 9/14 : (-4/7) = -9/8
=> x = 5/2 - (-9/8) = 5/2 + 9/8 = 29/8
c) => 3x = 2 và 2/3 - 3/4 = 8/3 - 3/4 = 23/12
=> x = 23/12 : 3 = 23/36
D) => -5/6 - x = 1/4
=> x = -5/6 - 1/4 = -13/12
a) \(\dfrac{4}{9}+\dfrac{4}{3}x=\dfrac{7}{9}\)
\(\dfrac{4}{3}x=\dfrac{7}{9}-\dfrac{4}{9}=\dfrac{1}{3}\)
\(x=\dfrac{1}{3}:\dfrac{4}{3}\)
\(x=\dfrac{1}{4}\)
b) \(\left(\dfrac{5}{2}-x\right)\left(-\dfrac{4}{7}\right)=\dfrac{9}{14}\)
\(\dfrac{5}{2}-x=\dfrac{9}{14}:\left(-\dfrac{4}{7}\right)=-\dfrac{9}{8}\)
\(x=\dfrac{5}{2}-\left(-\dfrac{9}{8}\right)\)
\(x=\dfrac{29}{8}\)
c) \(3x+\dfrac{3}{4}=2\dfrac{2}{3}\)
\(3x+\dfrac{3}{4}=\dfrac{8}{3}\)
\(3x=\dfrac{8}{3}-\dfrac{3}{4}=\dfrac{23}{12}\)
\(x=\dfrac{23}{12}:3\)
\(x=\dfrac{23}{36}\)
d) \(-\dfrac{5}{6}-x=\dfrac{7}{12}+\dfrac{-1}{3}\)
\(-\dfrac{5}{6}-x=\dfrac{1}{4}\)
\(x=-\dfrac{5}{6}-\dfrac{1}{4}\)
\(x=-\dfrac{13}{12}\)
Bài 1 :
36/1212 = 3/101
13/1313 = 1/101
3/101 + 1/101 = 4/101
Vậy 36/1212 + 13/1313 = 4/101.
Bài 2 :
A = 5/13 + 1/2 + -5/9 + -3/6 + 4/-9
A = 5/13 + 1/2 + -5/9 + -1/2 + -4/9
A = (1/2 + -1/2) + (-5/9 + -4/9) + 5/13
A = 0 + (-1) + 5/13
A = (-1) + 5/13 = -13/13 + 5/13 = 8/13.
Chúc bạn học giỏi nhé.
\(A=8\frac{4}{17}-\left(2\frac{5}{9}+3\frac{4}{17}\right)\)
\(A=8\frac{4}{17}-2\frac{5}{9}-3\frac{4}{17}\)
\(A=\left(8\frac{4}{17}-3\frac{4}{17}\right)-\frac{23}{9}\)
\(A=5-\frac{23}{9}\)
\(A=\frac{45}{9}-\frac{23}{9}\)
\(A=\frac{22}{9}\)
\(A=8\frac{4}{7}-2\frac{5}{9}-3\frac{4}{7}\)
\(A=\left(8\frac{4}{7}-3\frac{4}{7}\right)-2\frac{5}{9}\)
\(A=5-2\frac{5}{9}\)
\(A=4+1-2\frac{5}{9}\)
\(A=4+1-\frac{23}{9}\)
\(A=4+\frac{-14}{9}\)
\(A=1\frac{5}{9}\)
Câu a: xem lại đề bài
Câu b:
3^9 : 3^7 + 5.2^3
= 3^2 + 5.8
= 9 + 40
= 49
Câu c:
2^3.3^2 - 5^16 : 5^14
= 8.9 - 5^2
= 72 - 25
= 47
TL
= (39 (3 -1)) : 29 : 310 = 2 : 29 x 1/3 = 1/28 x 1/3
Khi nào rảnh vào kênh H-EDITOR xem vid nha!!! Thanks!
1/2^2>1/2.3;1/3^2>1/3.4;......;1/9^2>1/9.10
suy ra S > 1/2.3+1/3.4+......+1/9.10
S> 1/2-1/3+1/3-1/4 +.....+1/9-1/10
S> 1/2-1/10=2/5
Vay 2/5 < S
Vậy còn S < \(\frac{8}{9}\)thì sao, bạn quên chưa chứng minh rồi
1. a) \(45x-37=53\)
\(45x=90\)
\(x=2\)
vay \(x=2\)
b) \(\frac{x}{9}+500=600\)
\(\frac{x}{9}=100\)
\(\frac{x}{9}=\frac{900}{9}\)
\(\Rightarrow x=900\)
vay \(x=900\)
c) \(576-x=139\)
\(x=576-139\)
\(x=437\)
vay \(x=437\)
d) \(\left(48+x\right)-27=79\)
\(48+x=79+27\)
\(48+x=106\)
\(x=58\)
vay \(x=58\)
2. \(2^5.2^7.2^9=2^{5+7+9}=2^{21}\)
\(3^9.3^2.3=3^{9+2+1}=3^{12}\)
\(10^9:10^7=10^{10-7}=10^3\)
3). \(2.2.2.2.2.2=2^6\)
\(2.3.2.2.3.3.3=2^3.3^4\)
\(10.9.10.10.10.9.9=10^4.9^3\)
1 a) x= 720
b ) x=chín trăm
c)x= 437
d)x=58
bài2 a)= 221 b)312 c ) =102
bài 3 a)=26 b)=22 nhân 34 c )= 103 nhân chín mũ 3
- Ta co : \(\frac{1}{9}.x=\frac{12}{11}-\frac{8}{9}\)
=> \(\frac{1}{9}.x=\frac{20}{99}\)
=> \(x=\frac{20}{99}:\frac{1}{9}\)
=> \(x=\frac{20}{11}\)
45.17558299
\(\frac{\left(2^3\cdot9^4+9^3\cdot45\right)}{9^2\cdot10-9^2}\)
\(=\frac{2^3\cdot9^4+9^4\cdot5}{9^2\cdot\left(10-1\right)}=\frac{9^4\cdot\left(2^3+5\right)}{9^2\cdot9}=9\left(2^3+5\right)\)
\(=9\cdot\left(8+5\right)=9\cdot13=117\)
Cảm ơn các bạn
=(8.6561+729.45):(81.10-81)
=(52488+32805):(810-81)
=85293:729
=117