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\(8-12x+6x^2-x^3\)
\(=\left(2-x\right)^3\)
\(125x^3-75x^2+15x-1\)
\(=\left(5x-1\right)^3\)
\(x^2-xz-9y^2+3yz\)
\(=\left(x-3y\right)\left(x+3y\right)-z\left(x-3y\right)\)
\(=\left(x-3y\right)\left(x+3y-z\right)\)
\(x^3-x^2-5x+125\)
\(=\left(x+5\right)\left(x^2-5x+25\right)-x\left(x+5\right)\)
\(=\left(x+5\right)\left(x^2-5x+25-x\right)\)
\(=\left(x+5\right)\left(x^2-6x+25\right)\)
\(x^3+2x^2-6x-27\)
\(=x^3+5x^2+9x-3x^2-15x-27\)
\(=x\left(x^2+5x+9\right)-3\left(x^2+5x+9\right)\)
\(=\left(x-3\right)\left(x^2+5x+9\right)\)
\(12x^3+4x^2-27x-9\)
\(=4x^2\left(3x+1\right)-9\left(3x+1\right)\)
\(=\left(3x+1\right)\left(4x^2-9\right)\)
\(=\left(3x+1\right)\left(2x-3\right)\left(2x+3\right)\)
\(4x^4+4x^3-x^2-x\)
\(=4x^3\left(x+1\right)-x\left(x+1\right)\)
\(=x\left(x+1\right)\left(4x^2-1\right)\)
\(=x\left(x+1\right)\left(2x-1\right)\left(2x+1\right)\)
Bài 6:
a: \(x=-\dfrac{2}{3}-\dfrac{1}{7}=\dfrac{-14-3}{21}=\dfrac{-17}{21}\)
d: \(x=\dfrac{9}{10}\cdot\dfrac{-5}{9}=\dfrac{-1}{2}\)
e: \(\Leftrightarrow x\cdot\dfrac{1}{3}=\dfrac{14}{21}-\dfrac{3}{21}=\dfrac{11}{21}\)
=>x=11/7
mik ko chép lại đề, mik làm luôn:
a) x - \(\frac{31}{36}=\frac{-13}{38}\)
x = \(\frac{-13}{18}+\frac{31}{36}\)
\(x=\frac{5}{36}\)
b)\(2-x-\frac{3}{7}=\frac{9}{-21}\)
\(\frac{11}{7}-x=\frac{3}{7}\)
x = \(\frac{11}{7}-\frac{3}{7}\)
x = 8/7
c) x + 3/11 = 23/44
x = 23/44 - 3/11
x = 1/4
d) \(\frac{1}{12}-x=\frac{-11}{9}\)
x = \(\frac{1}{12}+\frac{11}{9}\)
x = 47/36
e) \(x-\frac{2}{3}=\frac{-17}{3}\)
x= -17/3 + 2/3
x = -5
f) \(x-\frac{1}{2}=\frac{11}{4}.\frac{3}{11}\)
x - 1/2 = 3/4
x = 3/4 + 1/2
x = 5/4
g) \(2x+\frac{3}{8}=\frac{-21}{32}.\frac{4}{7}\)
2x + 3/8 = -3 / 8
2x = -3/8 - 3/8
2x = -9/8
x = -9/8.1/2
x = -9/16
h) x - \(\frac{x}{3}=\frac{3}{57}.\frac{19}{12}\)
x - \(\frac{x}{3}=\frac{1}{12}\)
x = \(\frac{1}{12}+\frac{x}{3}\)
x = \(\frac{1+4x}{12}\)
=> 12x = 1+4x
12x - 4x = 1
8x = 1
x = 1/8
9) \(\dfrac{x}{4}=\dfrac{9}{x}\)
Theo định nghĩa về hai phân số bằng nhau, ta có:
\(4\cdot9=x^2\\ 36=x^2\Rightarrow\left[{}\begin{matrix}x=6\\x=-6\end{matrix}\right.\)
8)
\(x:\dfrac{5}{3}+\dfrac{1}{3}=-\dfrac{2}{5}\\ x:\dfrac{5}{3}=-\dfrac{2}{5}+\dfrac{1}{3}\\ x:\dfrac{5}{3}=-\dfrac{1}{15}\\ x=\dfrac{1}{15}\cdot\dfrac{5}{3}\\ x=\dfrac{1}{9}\)
7)
\(2x-16=40+x\\ 2x-x=40+16\\ x\left(2-1\right)=56\\ x=56\)
6)
\(1\dfrac{1}{2}+x=\dfrac{3}{2}-7\\ \dfrac{3}{2}+x=\dfrac{3}{2}-7\\ \dfrac{3}{2}-\dfrac{3}{2}=-7-x\\ -7-x=0\\ x=-7-0\\ x=-7\)
5)
\(3\dfrac{1}{2}-\dfrac{1}{2}x=\dfrac{2}{3}\\ \dfrac{7}{2}-\dfrac{1}{2}x=\dfrac{2}{3}\\ \dfrac{1}{2}x=\dfrac{7}{2}-\dfrac{2}{3}\\ \dfrac{1}{2}x=\dfrac{17}{6}\\ x=\dfrac{17}{6}:\dfrac{1}{2}\\ x=\dfrac{17}{3}\)
4)
\(x\cdot\left(x+1\right)=0\Rightarrow\left[{}\begin{matrix}x=0\\x+1=0\end{matrix}\right.\Rightarrow\left[{}\begin{matrix}x=0\\x=-1\end{matrix}\right.\)
3)
\(\left(\dfrac{2x}{5}+2\right):\left(-4\right)=-1\dfrac{1}{2}\\ \left(\dfrac{2x}{5}+2\right):\left(-4\right)=-\dfrac{3}{2}\\ \dfrac{2x}{5}+2=-\dfrac{3}{2}\cdot\left(-4\right)\\ \dfrac{2x}{5}+2=6\\ \dfrac{2x}{5}=6-2\\ \dfrac{2x}{5}=4\\ 2x=4\cdot5\\ 2x=20\\ x=20:2\\ x=10\)
2)
\(\dfrac{1}{3}+\dfrac{1}{2}:x=-0,25\\ \dfrac{1}{3}+\dfrac{1}{2}:x=-\dfrac{1}{4}\\ \dfrac{1}{2}:x=-\dfrac{1}{4}-\dfrac{1}{3}\\ \dfrac{1}{2}:x=-\dfrac{7}{12}\\ x=\dfrac{1}{2}:-\dfrac{7}{12}\\ x=-\dfrac{6}{7}\)
1)
\(\dfrac{4}{3}+x=\dfrac{2}{15}\\ x=\dfrac{2}{15}-\dfrac{4}{3}x=-\dfrac{6}{5}\)
\(a,\left(19x+2.5^2\right):14=\left(13-8\right)^2-4^2\)
\(\Leftrightarrow\left(19x+50\right):14=5^2-4^2\)
\(\Leftrightarrow\left(19x+50\right):14=9\)
\(\Leftrightarrow19x+50=126\)
\(\Leftrightarrow19x=76\Leftrightarrow x=4\)
b) x + ( x + 1 ) + ( x + 2 ) + ... + ( x + 30 ) = 1240
x + x + 1 + x + 2 + ... + x + 30 = 1240
( x + x + ... + x ) + ( 1 + 2 + ... + 30 ) = 1240
Số số hạng là : ( 30 - 1 ) : 1 + 1 = 30 ( số )
Tổng là : ( 30 + 1 ) . 30 : 2 = 465
=> 31x + 465 = 1240
=> 31x = 775
=> x = 25
Vậy........
Làm thế nào v mg 💤
Tra chatgpt đi, ko ai hơi đâu giải hộ m
1.
(x + 73) - 26 = 76
x + 47 = 76
x = 76 - 47
x = 29
2.
4(x - 3) = 7² - 1 × 10
4(x - 3) = 49 - 10
4(x - 3) = 39
x - 3 = 39 : 4
x = 9,75 + 3
x = 12,75
3.
4(x + 41) = 400
x + 41 = 400 : 4
x + 41 = 100
x = 100 - 41
x = 59
4.
11(x - 9) = 77
x - 9 = 77 : 11
x - 9 = 7
x = 7 + 9
x = 16
5.
2x - 49 = 5,3²
2x - 49 = 28,09
2x = 28,09 + 49
2x = 77,09
x = 77,09 : 2
x = 38,545
6.
3x = 9
x = 9 : 3
x = 3
7.
4x = 64
x = 64 : 4
x = 16
8.
2^x = 16
16 = 2⁴
x = 4
9.
9^x - 1 = 9
9^x = 9 + 1
9^x = 10
x = ≈ 1,05
10.
x⁴ = 16
x = ±√√16
x = ±2
x = 2 hoặc -2
11.
114 : (x - 8) = 7
x - 8 = 114 : 7
x - 8 = 16,2857
x = 16,2857 + 8
x = 24,2857
12.
200 - (2x + 6) = 4³
200 - 2x - 6 = 64
194 - 2x = 64
2x = 194 - 64
2x = 130
x = 130 : 2
x = 65
13.
25 + 3(x - 8) = 106
3(x - 8) = 106 - 25
3(x - 8) = 81
x - 8 = 81 : 3
x - 8 = 27
x = 27 + 8
x = 35
bn à bn k giải thì để ng khác giải đi
1: (x+73)-26=76
=>x+73=26+76=76+24+2=102
=>x=102-73=29
2: \(4\left(x-3\right)=7^2-1^{10}\)
=>4(x-3)=49-1=48
=>x-3=12
=>x=12+3=15
3: \(4\left(x+41\right)=400\)
=>x+41=400:4=100
=>x=100-41=59
4: \(11\left(x-9\right)=77\)
=>\(x-9=\frac{77}{11}=7\)
=>x=7+9=16
5: \(2x-49=5\cdot3^2\)
=>2x-49=45
=>2x=49+45=94
=>\(x=\frac{94}{2}=47\)
6: \(3^{x}=9\)
=>\(3^{x}=3^2\)
=>x=2
7: \(4^{x}=64\)
=>\(4^{x}=4^3\)
=>x=3
8: \(2^{x}=16\)
=>\(2^{x}=2^4\)
=>x=4
9: \(9^{x-1}=9\)
=>x-1=1
=>x=1+1
=>x=2
10: \(x^4=16\)
=>\(x^4=2^4\)
=>\(\left[\begin{array}{l}x=2\\ x=-2\end{array}\right.\)
11: \(1141:\left(x-8\right)=7\)
=>x-8=1141:7=163
=>x=163+8=171
12: \(200-\left(2x+6\right)=4^3\)
=>200-2x-6=64
=>194-2x=64
=>2x=194-64=130
=>\(x=\frac{130}{2}=65\)
13: 25+3(x-8)=106
=>3(x-8)=106-25=81
=>x-8=27
=>x=27+8=35
14: \(3^2\cdot\left(X+4\right)-5^2=5\cdot2\)
=>9(x+4)=10+25=35
=>\(x+4=\frac{35}{9}\)
=>\(x=\frac{35}{9}-4=-\frac19\)