\(x^2-2xy+5x-10y\)

\(=x\left(x-2y\right)+5\left(x-2y\right)\)

\(=\left(x+5\right)\left(x-2y\right)\)

\(x^2-2xy+5x-10y\)

\(=\left(x^2-2xy\right)+\left(5x-10y\right)\)

\(=x\left(x-2y\right)+5\left(x-2y\right)\)

\(=\left(x-2y\right)\left(x+5\right)\)

\(x-3\sqrt{x}+\sqrt{xy}-3y\)

\(=\left(x-3\sqrt{x}\right)+\left(\sqrt{xy}-3y\right)\)

\(=\sqrt{x}\left(\sqrt{x}-3\right)+y\left(\sqrt{x}-3\right)\)

\(=\left(\sqrt{x}-3\right)\left(\sqrt{x}+y\right)\)

\(x^2-3x+xy-3y\)

\(=x\left(x+y\right)-3\left(x+y\right)\)

\(=\left(x+y\right)\left(x-3\right)\)

\(x^2-2xy+y^2-4=\left(x-y\right)^2-2^2=\left(x-y-2\right)\left(x-y+2\right)\)

\(x^2+x-y^2+y=\left(x-y\right)\left(x+y\right)+\left(x+y\right)=\left(x+y\right)\left(x-y+1\right)\)

      \(x^3+4x^2+4x+3\)

\(=x^3+3x^2+x^2+3x+x+3\)

\(=x^2\left(x+3\right)+x\left(x+3\right)+\left(x+3\right)\)

\(=\left(x+3\right)\left(x^2+x+1\right)\)

      \(x^2-y^2+4y-4\)

\(=x^2-\left(y^2-4y+4\right)\)

\(=x^2-\left(y-2\right)^2\)

\(=\left(x-y+2\right)\left(x+y-2\right)\)

      \(x^4+x^3y-xy^3-y^4\)

\(=x^3\left(x+y\right)-y^3\left(x+y\right)\)

\(=\left(x+y\right)\left(x^3-y^3\right)\)

\(=\left(x+y\right)\left(x-y\right)\left(x^2+xy+y^2\right)\)

Chúc bạn học tốt.

\(2xy-x^2+3y^2-4y+1\)

\(=-\left(x^2-2xy+y^2\right)+4y^2-4y+1\)

\(=-\left(x-y\right)^2+\left(2y-1\right)^2\)

\(=\left(2y-1+x-y\right)\left(2y-1-x+y\right)\)

\(=\left(y+x-1\right)\left(3y-x-1\right)\)

\(2x^2+xy+x^2\)

\(=3x^2+xy\)

\(=x.\left(3x+y\right)\)

\(2x^2+xy+x^2\)

\(=x\left(2x+y+x\right)\)

\(=x\left(3x+y\right)\)

x³ -2x² +x- xy²

= x ( x² - 2x + 1 - y²)

= x\(\left[\left(x-1\right)^2-y^2\right]\)

= x ( x- 1- y) ( x - 1 + y )

X³-2x²+x-xy²

=(x³+x)-(2x²-xy²)

=x(x²+1)-x(2x-y²)

=x(x²-2x+1-y²)

=x[(x-1)²-y]

=x(x-1-y)(x-1+y)

Chúc bạn làm tốt@"

\(=x\left(x^2-2x+1-y^2\right)\)

\(=x\left[\left(x^2-2x+1\right)-y^2\right]\)

\(=x\left[\left(x-1\right)^2-y^2\right]\)

\(=x\left(x-1+y\right)\left(x-1-y\right)\)

= x (x²-2x+1-y²)

= x ( (x-1)²-y²)

=x (x-1-y) (x-1+y)

\(x^3y^3+x^2y^2+4=x^3y^3+2x^2y^2-x^2y^2+4\)

\(=\left(x^3y^3+2x^2y^2\right)-\left(x^2y^2-4\right)=x^2y^2\left(xy+2\right)-\left(xy-2\right)\left(xy+2\right)\)

\(=\left(xy+2\right)\left(x^2y^2-xy+2\right)\)

Phân tích đa thức thành nhân tử( pp tách hạng tử):

x³y³+x²y²+4

Câu trả lời của mik giống bạn Nguyễn Lê Tiến Huy .

\(3x^2-3y^2-2\left(x-y\right)^2\)

\(=3x^2-3y^2-2\left(x^2-2xy+y^2\right)\)

\(=3x^2-3y^2-2x^2+4xy-2y^2\)

\(=x^2+4xy-5y^2\)

\(=x^2+4xy+4y^2-9y^2\)

\(=\left(x+2y\right)^2-\left(3y\right)^2\)

\(=\left(x+2y-3y\right)\left(x+2y+3y\right)\)

\(=\left(x-y\right)\left(x+5y\right)\)