\(=49\frac{8}{23}-5\frac{7}{32}-14\frac{8}{23}\)

\(=\left(49\frac{8}{23}-14\frac{8}{23}\right)-5\frac{7}{32}\)

\(=35\frac{0}{23}-5\frac{7}{32}\)

\(=\frac{805}{23}-\frac{167}{32}\)

\(\frac{25760}{736}-\frac{3841}{736}\)

\(=\frac{21919}{736}=\frac{953}{32}\)

\(=49\frac{8}{23}-5\frac{7}{32}-14\frac{8}{23}\)

\(=49\frac{8}{23}-14\frac{8}{23}-5\frac{7}{12}\)

\(=35-5\frac{7}{32}\)

\(=35-\frac{167}{32}\)

\(=\frac{1120}{32}-\frac{167}{32}\)

\(=\frac{935}{32}\)

\(49\frac{8}{23}-\left(5\frac{7}{32}+14\frac{8}{23}\right)\)

\(=49\frac{8}{23}-5\frac{7}{32}-14\frac{8}{23}\)

\(=\left(49\frac{8}{23}-14\frac{8}{23}\right)-5\frac{7}{32}\)

\(=35-5\frac{7}{32}\)

\(=35-\frac{167}{32}\)

\(=\frac{953}{32}\)

Câu 2:

2Q = \(\frac{2}{1.2.3}\) + \(\frac{2}{2.3.4}\) + ... + \(\frac{2}{98.99.100}\)

2Q = \(\frac12\).(\(\frac{2}{1.3}\)) + \(\frac13\).(\(\frac{2}{2.4}\)) + ... + \(\frac{1}{99}\).(\(\frac{2}{98.100}\))

2Q = \(\frac12\).(\(\frac11-\frac13\)) + \(\frac13\).(\(\frac12-\frac14\)) + ...+ \(\frac{1}{99}\).(\(\frac{1}{98}-\frac{1}{100}\))

2Q = \(\frac{1}{1.2}\) - \(\frac{1}{2.3}\) + \(\frac{1}{2.3}\) - \(\frac{1}{3.4}\) + ...+\(\frac{1}{98.99}\) - \(\frac{1}{99.100}\)

2Q = \(\frac12-\frac{1}{9900}\)

2Q = \(\frac{4949}{9900}\)

Q = \(\frac{4949}{9900}\) : 2

Q = \(\frac{4949}{19800}\)

Câu 1:

A = \(\frac14+\frac18+\frac{1}{16}+..+\frac{1}{128}\)

2A = \(\frac12+\frac14+\frac18+\cdots+\frac{1}{64}\)

2A - A = \(\frac12+\frac14+\frac18+\cdots+\frac{1}{64}\) - \(\frac14-\frac15-\frac{1}{16}-\ldots\frac{1}{128}\)

A = (\(\frac12-\frac{1}{128})+\left(\frac14-\frac14)+..+\left(\frac{1}{64}-\frac{1}{64}\right)\right.\)

A = \(\frac{64}{128}-\frac{1}{128}\) + 0 + 0+..+0

A = \(\frac{63}{128}\)

16⁹ nhé!

khó quá đi

=32x-49+32x102-102x49+102x32

=32(-49+102)+102(32-49)

=32x53+102x-17=1696+-1734=-38

CHÚC BẠN HỌC GIỎI!!!!!!!!

\(32.\left(10-35\right)-35.\left(18-32\right)\)

\(=32.-25-35.-14\)

\(=32.\left(-25--14\right)\)

\(=32.-11\)

\(=-352\)

35.47+35.32-47.35+47.32

(35.47 - 47 . 35 ) + 32 . (35 + 47 )

0 + 32 . 82 

= 2624

d​ễ mà bạn, cứ phá ngoặc ra rồi kết hợp vào và sử dụng 1 số nhân một tông hoặc một hiệu gì đó

=32.(10-25)-35.18+32.35

=32.(10-25+35)-35.18

=32.20-630

=640-630

=10

\(32\left(10-25\right)-35\left(18-32\right)\)

\(=32\left(10-25\right)-35\times18+35\times32\)

\(=32\left(10-25+35\right)-35\times18\)

\(=32\times20-35\times18\)

\(=640-630\)

\(=10\)

32.(-84) + 17.(-32)

= -32.(84 + 17)

= -32 . 101

= -32 . (100 + 1)

= -3200 - 32

= -3232

-3232

tich nha nha nha @@@@@@@@@

\(\frac{9\cdot121\cdot49}{7\cdot11\cdot9}\)

\(=\frac99\cdot\frac{121}{11}\cdot\frac{49}{7}\)

\(=11\cdot7=77\)

(9.121.49) :(7.11.9)

=(9:9).(121:11).(49:7)

= 1.11.7

= 11.7

= 77