\(\left(1+x\right)+\left(2+x\right)+\left(3+x\right)+\)\(\left(4+x\right)+\left(5+x\right)=10\times5\)

\(\left(1+2+3+4+5\right)+\left(x+x+x+x+x\right)=50\)

\(15+5x=50\)

\(5x=35\)

\(x=7\)

Vậy \(x=7\)

\(\left(1+x\right)+\left(2+x\right)+\left(3+x\right)+\left(4+x\right)+\left(5+x\right)=10\times5\)

\(\Rightarrow1+x+2+x+3+x+4+x+5+x=50\)

\(\Rightarrow\left(1+2+3+4+5\right)+\left(x+x+x+x+x\right)=50\)

\(\Rightarrow15+5x=50\)

\(\Rightarrow5x=50-15\)

\(\Rightarrow5x=35\)

\(\Rightarrow x=35:5\)

\(\Rightarrow x=7\).

(x + 1) + (x + 4) + (x + 7) + (x + 10) + .... + (x + 28) = 155 (có 10 số hạng ở vế trái)

=> x + 1 + x + 4 + x + 7 + x + 10 + .... + x + 28 = 155

=> (x + x + x + ... + x) + (1 + 4 + 7 + 10 + ... + 28) = 155

      10 hạng tử                   10 hạng tử

=> \(10\times x+10\times\left(28+1\right):2=155\)

=> \(10\times x+145=155\)

=> \(10\times x=10\)

=> x = 1

(x+1)+(x+4)+.......+(x+28)=155

=> x+x+.....+x+1+4+......28=155

=>10x+(28+1):2*10=155

=> 10x+145=155

=>10x=10

=>x=1

vậy x=1

4,25 x (X+ 41,53) - 125= 53,5

4,25 x (X+ 41,53)= 53,5+ 125

4,25 x (X+ 41,53) = 178,5

X+ 41,53= 178,5: 4,25

X+ 41,53= 42

X= 42- 41,53

X= 0,47

Tk cho mk nhé ^^

4,25x(X+41,53)-125=53,5

4,25x(X+41,53)=53,5+125

4,25x(X+41,53)=178,5

X+41,53=42

X=0,47

#H

(8 x 18 - 5 x 18 - 18 x 3)x + 2x = 8 x 7 + 24

<=> [18 x (8 - 5 - 3)]x + 2x =   80

<=> 2x = 80

<=> x = 40,k nhé bạn

(8x18-5x18-18x3)xX+2xX=8x7+24

=>8x(8-5-3)xX+2xX=80

=>8x0xX+2xX=80

=>0+2xX=80

=>X=80:2

=>X=40

x = 3,94

x = 3,95

\(3,9< 3,95< 4< 4,1\)

\(~HT~\)

\(@Mia\)

\(\frac{4}{x}\) \(=\frac{1}{5}\)

Ta có :

\(\frac{4}{x}\) \(=\frac{4}{20}\)

=> \(x=20\)

#Ninh Nguyễn

x.1=4.5

x.1=20

x=20:1

x=20

\(\left(1-\frac{1}{3}\right)x\left(1-\frac{1}{4}\right)x...x\left(1-\frac{1}{2014}\right)\)

A = \(\frac{2}{3}x\frac{3}{4}x\frac{4}{5}x...x\frac{2012}{2013}x\frac{2013}{2014}\)

A = \(\frac{2x3x4x...x2012x2013}{3x4x5x...x2013x2014}\)

a = \(\frac{2}{2014}=\frac{1}{1007}\)

1/1007 do

1) 2015

6)7

7)370

8)8

10)944

Đúng đó bạn. tick giúp mình nhé.

1)2015

6)7

7)370 

8)8

10)944

B1: Chiều rộng là b, CD là a

ta có a = 3b (1), a x b = 108 (2)

thế (1) vào (2) ta có: 3b x b = 108

                                b x b = 108 :3 = 36 => b=6, a=18

CV= ( 6 + 18) x 2 = 48

B2: abcde là 10989

Cảm ơn cậu nhiều nhé,Ngo Mai Ly!

7 -  ( 11 + x -13 ) :  \(2\frac{2}{3}\)  = 2

(11+ x - 13) : \(2\frac{2}{3}\) = 7-2

(11 + x - 13) : \(2\frac{2}{3}\)= 5

11 + x - 13 = 5 . \(2\frac{2}{3}\)

11 + x - 13 = \(\frac{40}{3}\)

11 + x = \(\frac{40}{3}+13\)

11 + x = \(\frac{79}{3}\)

x = \(\frac{79}{3}-11\)

x = \(\frac{46}{3}\)

\(7-\left(11+x-13\right):2\frac{2}{3}=2\)

\(7-\left(11+x-13\right)=2.2\frac{2}{3}\)

\(7-\left(11+x-13\right)=\frac{16}{3}\)

\(11+x-13=7-\frac{16}{3}\)

\(11+x-13=\frac{5}{3}\)

\(11+x=\frac{5}{3}+13\)

\(11+x=\frac{44}{3}\)

\(x=\frac{44}{3}-11\)

\(x=\frac{11}{3}\)