a) -24+3(x-4)=111

=>3(x-4)=111-(-24)

=>3(x-4)=135

=>(x-4)=135:3

=>x-4=45

=>x=45+4

=>x=49

Vậy x=49

b)(2x-4)(3x+63)=0

=>\(\hept{\begin{cases}\left(2x-4\right)\\\left(3x+63\right)\end{cases}}=0\)=>\(\hept{\begin{cases}2x-4=0\\3x+63=0\end{cases}}\)

=>\(\hept{\begin{cases}2x=0+4=4\\3x=0-63=-63\end{cases}}\)=>\(\hept{\begin{cases}x=4:2=2\\x=-63:3=-21\end{cases}}\)

Vậy \(\hept{\begin{cases}x=2\\x=-21\end{cases}}\)

x = 2k

y = 7k với kEZ , k khác 0

x/y = 2/7

=> x . 7 = 2 . y

=> x thuộc { 2 ; -2 }

=> y thuộc { 7 ; -7 }

+> Nếu x = 2 thì y = 7 

+>Nếu x = -2 thì y = -7

+> Nếu x = 2 thì y = -7

+> Nếu x = -2 thì y = 7

Vậy _____

Câu a: 2\(^3\).\(x\) : |\(\frac{13}{23}\) - 5\(\frac{13}{23}\)| = - 2\(\frac13\)

\(8x\) : |-5| = - \(\frac73\)

8\(x\) : 5 = -\(\frac73\)

8\(x\) = - \(\frac73\times5\)

8\(x\) = - \(\frac{35}{3}\)

\(x\) = - \(\frac{35}{3}\) : 8

\(x\) = - \(\frac{35}{24}\)

Vậy \(x=-\frac{35}{24}\)

Câu b:

||\(x-3\)| - 5| = 7

|\(x-3\)| - 5 = 7 hoặc |\(x-3\)| - 5 = - 7

TH1: |\(x-3\)| - 5 = 7

|\(x-3\)| = 7+ 5

|\(x-3\)| = 12

\(\left[\begin{array}{l}x-3=-12\\ x-3=12\end{array}\right.\)

\(\left[\begin{array}{l}x=-12+3\\ x=12+3\end{array}\right.\)

\(\left[\begin{array}{l}x=-9\\ x=15\end{array}\right.\)

TH2: |\(x-3\)| - 5 = - 7

|\(x-3\)| = - 7 + 5

|\(x\) - 3| = - 2(loại) Vì trị tuyêt đối của một số luôn không âm.

Vậy \(x\in\) {-9; 15}

a) x² - 3x = 0

<=> x(x - 3) = 0

<=> x = 0 hoặc x - 3 = 0 

<=> x = 0 hoặc x = 3

câu a vì x mũ 2 - 3x = 0 suy ra x mũ 2 = 3x 

x mũ 2 - 3x = 0 

x mũ 2 - x  = 0 : 3

x mũ 2 - x = 0

suy ra x.x-x=0

suy ra 2x-x=0

         1x    =0

          x     =0

Vậy x=0

\(\frac{x+2}{17}+\frac{x+4}{15}+\frac{x+6}{13}=\frac{x+8}{11}+\frac{x+10}{9}+\frac{x+12}{7}\)

\(\Rightarrow\left(\frac{x+2}{17}+1\right)+\left(\frac{x+4}{15}+1\right)+\left(\frac{x+6}{13}+1\right)-\left(\frac{x+8}{11}+1\right)-\left(\frac{x+10}{9}+1\right)-\left(\frac{x+12}{7}+1\right)=0\)

\(\Rightarrow\frac{x+19}{17}+\frac{x+19}{15}+\frac{x+19}{13}-\frac{x+19}{11}-\frac{x+19}{10}-\frac{x+19}{7}=0\)

\(\Rightarrow\left(x+19\right)(\frac{1}{17}+\frac{1}{15}+\frac{1}{13}-\frac{1}{11}-\frac{1}{9}-\frac{1}{7})\)

\(\Rightarrow x+19=0\)\(\left(Vì\frac{1}{17}+\frac{1}{15}+\frac{1}{13}-\frac{1}{11}-\frac{1}{9}-\frac{1}{7}\ne0\right)\)

\(\Rightarrow x=-19\)

Ta có : \(\frac{x+2}{17}+\frac{x+4}{15}+\frac{x+6}{13}=\frac{x+8}{11}+\frac{x+10}{9}+\frac{x+12}{7}\)

\(\Rightarrow\left(\frac{x+2}{17}+1\right)+\left(\frac{x+4}{15}+1\right)+\left(\frac{x+6}{13}+1\right)=\left(\frac{x+8}{11}+1\right)+\left(\frac{x+10}{9}+1\right)+\left(\frac{x+12}{7}+1\right)\)

\(\Rightarrow\frac{x+19}{17}+\frac{x+19}{15}+\frac{x+19}{13}-\frac{x+19}{11}-\frac{x+19}{9}-\frac{x+19}{7}=0\)

\(\Rightarrow\left(x+19\right)\left(\frac{1}{17}+\frac{1}{15}+\frac{1}{13}-\frac{1}{11}-\frac{1}{9}-\frac{1}{7}\right)=0\)

\(\Rightarrow x+19=0\Rightarrow x=-19\)

(1 - 1/7) x (1 - 2/7) x ............(1 - 10/7)

= 6/7 x 5/7 x ..... x -3/7

=6/7 x 5/7x 4/7 x 3/7x 2/7 x 1/7 x 0 x -1/7x -2/7 x -3/7

=0

nhớ tk cho mình nha

thanks nha

Ta có:\(\frac{4}{x}=\frac{2}{x+4}\)

\(\Leftrightarrow4x+16=2x\)

\(\Leftrightarrow4x-2x=-16\)

\(\Leftrightarrow2x=-16\)

\(\Leftrightarrow x=-8\)

hok tốt!!

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