a) => 7 . x - 11 = -193

=> 7 . x = - 193 + 11

=> 7 . x = - 182

=> x = - 182 : 7

=> x = -26

a)(7x-11)=2⁵.5².200

(7x-11)=32.25.200

(7x-11)=160000

7x=160000+11

7x=160011

x=160011:7

x=160011/7

b)16.4^x=32⁵

2⁴.4^x=(2⁵)⁵

2⁴.4^x=2²⁵

4^x=2²⁵:2⁴

4^x=2²¹

(2²)^x=2²¹

2^2.x=2²¹

=>2.x=21

x=21:2

x=10,5

Đề sai

tui đang cần gấp ai trả lời nhanh tui sẽ kick cho

a)\(x^{10}=1^x\Leftrightarrow x=1\)

b) \(x^{10}=x\Leftrightarrow\hept{\begin{cases}x=0\\x=1\end{cases}}\)

c) \(\left(2x-15\right)^5=\left(2x-15\right)^3.4\)

\(\Leftrightarrow2x-15=0\Leftrightarrow2x=15\Leftrightarrow x=\frac{15}{2}\)

nếu thắc mắc vì sao \(2x-15=1\)vì nếu như vậy ta có vế trái =1 nhưng vế phải lại phải  nhân cho 4 nên vế trái  ko = vế phải 

d) \(a^x-15=17\)

\(\Leftrightarrow a^x=32\)

\(\Leftrightarrow a^x=2^5\)

g) \(\left(7x-11\right)^3=2^5.5^2+200\)

\(\Leftrightarrow\left(7x-11\right)^3=2^5.5^2+200\)

\(\Leftrightarrow\left(7x-11\right)^3=800+200\)

\(\Leftrightarrow\left(7x-11\right)^3=1000\)

\(\Leftrightarrow\left(7x-11\right)^3=10^3\)

\(\Leftrightarrow7x-11=10\)

\(\Leftrightarrow7x=21\)

\(\Leftrightarrow x=21:7=3\)

mình không biết làm

\(a,\left(7x-11\right)^3=2^5.5^2+200.\)

\(\left(7x+11\right)^3=32.25+200.\)

\(\left(7x+11\right)^3=800+200.\)

\(\left(7x-11\right)^3=1000.\)

\(\left(7x-11\right)^3=10^3.\)

\(\Rightarrow7x-11=10.\)

\(\Rightarrow x=\left(10+11\right):3=7\in Z.\)

Vậy.....

\(b,3^x+25=26.2^2+2.3^0.\)

\(3^x+25=26.4+2.\)

\(3^x+25=104+2.\)

\(3^x+25=106.\)

\(3^x=106-25.\)

\(3^x=81.\)

\(3^x=3^4\Rightarrow x=4\in Z.\)

Vậy.....

\(c,2^x+3.2=64.\)(có vấn đề).

\(d,5^{x+1}+5^x=750.\)

\(5^x.5^1+5^x+1=750.\)

\(5^x\left(5^1+1\right)=750.\)

\(5^x\left(5+1\right)=750.\)

\(5^x.6=750.\)

\(5^x=750:6.\)

\(5^x=125.\)

\(5^x=5^3\Rightarrow x=3\in Z.\)

Vậy.....

\(e,x^{15}=x.\)

\(\Rightarrow x\left(x^{14}-1\right)=0\Rightarrow\left\{{}\begin{matrix}x=0\\x=1\end{matrix}\right..\)

\(f,\left(x-5\right)^4=\left(x-5\right)^6.\)

\(\Leftrightarrow\left(x-5\right)^4-\left(x-5^6\right)=0.\)

\(\Leftrightarrow\left(x-5\right)^4\left[1-\left(x-5\right)^2\right]=0.\)

\(\Leftrightarrow\left(x-5\right)^4\left(1-x+5\right)\left(1+x-5\right)=0.\)

\(\Leftrightarrow\left(x-5\right)^4\left(6-x\right)\left(x-4\right)=0.\)

\(\Leftrightarrow\left(x-5\right)^4=0\Rightarrow x-5=0\Rightarrow x=5\in Z.\)

\(6-x=0\Rightarrow x=6\in Z.\)

\(x-4=0\Rightarrow x=4\in Z.\)

Vậy.....