(2x-6)(2x-18)=0

\(\Rightarrow\hept{\begin{cases}2x-6=0\\2x-18=0\end{cases}}\Rightarrow\hept{\begin{cases}2x=6\\2x=18\end{cases}}\Rightarrow\hept{\begin{cases}x=3\\x=9\end{cases}}\)

Vậy ...

2x-6.18

2x-108

x=108:2

x=54

x + 18 = 6 - 2x

x + 2x = 6 - 18

3x = - 12

x = -4 

=.= hk tốt!!

x+2x = 6 - 18

3x = -12

x = -12 : 3

x = -4

Vậy......

a)  \(\left|18-2x\right|=18\Rightarrow\orbr{\begin{cases}18-2x=18\\18-2x=-18\end{cases}\Rightarrow\orbr{\begin{cases}2x=0\\2x=36\end{cases}\Rightarrow}\orbr{\begin{cases}x=0\\x=18\end{cases}}}\)

b) \(\left|1-x\right|=1-x\Rightarrow\orbr{\begin{cases}1-x=1-x\\1-x=-\left(1-x\right)=-1+x\end{cases}}\)

  \(\Rightarrow\orbr{\begin{cases}x=\left\{\mp1;\mp2;...\right\}\\-x-x=-1-1\Rightarrow x=1\end{cases}}\)

Làm từng nãy đã , mỏi tay

a)  ta có  \(|\)18 - 2x\(|\)=18 
       =>       18-2x = 18                            hoặc  18 -2x=-18
                   -2x    =    0                                          -2x =  -36
                       x    = 0                                               x =  18
                  vậy x = 0 hoặc x=18
 
                  

a) x + 18 = 25

=> x       = 25 - 18

=> x       = 7

b) x + 18 = 6 - 2x

=> x + 2x = 6 - 18

=> 3x       = -12

=> x         = -12 : 3

=> x         = -4

Chúc bn học tốt^^

Bài 1 :
a, x + 18 = 25

x = 25 - 18

x = 7 . Vậy x = 7

b, x + 18 = 6-2x

18 = 6-2x-x

18 - 6 = -2x - x 

12 = -3x

x = 12 : (-3)
x = -4

Vậy x = -4

Đúng tích mk nha!!

(2x + 4)(-6x - 18) = 0

=> \(\orbr{\begin{cases}2x+4=0\\-6x-18=0\end{cases}}\)

=> \(\orbr{\begin{cases}2x=-4\\-6x=18\end{cases}}\)

=> \(\orbr{\begin{cases}x=-2\\x=-3\end{cases}}\)

Vậy ...

\(\left(2x+4\right)\left(-6x-18\right)=0\)

\(\Leftrightarrow\orbr{\begin{cases}2x+4=0\\-6x-18=0\end{cases}}\)

\(\Leftrightarrow\orbr{\begin{cases}2x=-4\\-6x=18\end{cases}}\)

\(\Leftrightarrow\orbr{\begin{cases}x=-2\\x=-3\end{cases}}\)

Bài 1 Tìm x biết:

a)65-(29-x)=32

65 -29+x=31

x=31-65+29

x=-5

b)(x+5)-(x+23)=x-34

x+5 -x +23 = x-34

(x-x)+ (23+5)=x-34

0+28=x-34

28=x-34

28+34=x

62=x

=>x=62

c)(16-x)+(x-38)=x+44

16-x+x-38=x+44

-x+x-x=44-16+38

-x=36

=>x=-36

d)-12+3(-x+7)=-18

3(-x+7)=-18+12

3(-x+7)=-6

-x+7=-6:3

-x+7=-2

-x=-2-7

-x=-9

=>x=9

Baif 2

d)|7-x|=10

=> \(\left[{}\begin{matrix}7-x=10\\7-x=-10\end{matrix}\right.\)

\(\Rightarrow\)\(\left[{}\begin{matrix}x=7-10\\x=-10-7\end{matrix}\right.\)

\(\Rightarrow\)\(\left[{}\begin{matrix}x=-3\\x=-17\end{matrix}\right.\)

e)(x-6).(7-2x)=0

\(\Rightarrow\)\(\left[{}\begin{matrix}x-6=0\\7-2x=0\end{matrix}\right.\)

\(\Rightarrow\)\(\left[{}\begin{matrix}x=0+6\\2x=7\end{matrix}\right.\)

\(\Rightarrow\)\(\left[{}\begin{matrix}x=6\\x=7:2\end{matrix}\right.\)

\(\Rightarrow\)\(\left[{}\begin{matrix}x=6\\x=3,5\end{matrix}\right.\)

f)(9-x).(2x+8)=0

\(\Rightarrow\)\(\left[{}\begin{matrix}9-x=0\\2x+8=0\end{matrix}\right.\)

\(\Rightarrow\)\(\left[{}\begin{matrix}x=0+9\\2x=-8\end{matrix}\right.\)

\(\Rightarrow\)\(\left[{}\begin{matrix}x=9\\x=-4\end{matrix}\right.\)

g)x(-x+8).(-3x-18)=0

\(\Rightarrow\) \(\left[{}\begin{matrix}x=0\\-x+8=0\\-3x-18=0\end{matrix}\right.\)

\(\Rightarrow\)\(\left[{}\begin{matrix}x=0\\-x=0+8\\-3x=0+18\end{matrix}\right.\)

\(\Rightarrow\)\(\left[{}\begin{matrix}x=0\\-x=8\\-3x=18\end{matrix}\right.\)

\(\Rightarrow\)\(\left[{}\begin{matrix}x=0\\x=-8\\x=18:\left(-3\right)\end{matrix}\right.\)

\(\Rightarrow\)\(\left[{}\begin{matrix}x=0\\x=-8\\x=-6\end{matrix}\right.\)

h)(-x+8).(x-54).(-24-x)=0

\(\Rightarrow\)\(\left[{}\begin{matrix}-x+8=0\\x-54=0\\-24-x=0\end{matrix}\right.\)

\(\Rightarrow\)\(\left[{}\begin{matrix}-x=8\\x=0+54\\-x=0+24\end{matrix}\right.\)

\(\Rightarrow\)\(\left[{}\begin{matrix}x=8\\x=54\\-x=24\end{matrix}\right.\)

\(\Rightarrow\)\(\left[{}\begin{matrix}x=8\\x=54\\x=-24\end{matrix}\right.\)