Ta có : (x + 2) : 3 = (2x - 1) : 4

=> \(\frac{x+2}{3}=\frac{2x-1}{4}\)

=> 4(x + 2) = 3(2x - 1)

=> 4x + 8 = 6x - 3

=> 6x - 4x = 8 + 3

=> 2x = 11

=> x = 5,5

Vậy x = 5,5

\(\left(x+2\right):3=\left(2x-1\right):4\)

\(\frac{x+2}{3}=\frac{2x-1}{4}\)
\(\Rightarrow4\left(x+2\right)=3\left(2x-1\right)\)

\(4x+8=6x-3\)

\(4x-6x=-3-8\)

\(-2x=-11\)

\(2x=11\)

\(x=11:2\)

\(x=5,5\)

Vậy \(x=5,5\).

Bài làm :

\(\left(x+2\right):3=\left(2x-1\right):4\)

\(\Rightarrow\left(x+2\right).\frac{1}{3}=\left(2x-1\right).\frac{1}{4}\)

\(\Rightarrow\frac{1}{3}x+\frac{2}{3}=\frac{1}{2}x-\frac{1}{4}\)

\(\Rightarrow\frac{1}{3}x-\frac{1}{2}x=\frac{-1}{4}-\frac{2}{3}\)

\(\Rightarrow\frac{-1}{6}x=\frac{-11}{12}\)

\(\Rightarrow x=\frac{-11}{12}:\left(\frac{-1}{6}\right)\)

\(\Rightarrow x=\frac{11}{2}\)

Vậy \(x=\frac{11}{2}\) .

Học tốt

           Bài làm :

Ta có :

\(\frac{x+2}{3}=\frac{2x-1}{4}\)
\(\Leftrightarrow4\left(x+2\right)=3\left(2x-1\right)\)

\(\Leftrightarrow4x+8=6x-3\)

\(\Leftrightarrow4x-6x=-3-8\)

\(\Leftrightarrow-2x=-11\)

\(\Leftrightarrow x=5,5\)

Vậy x=5,5

\(\frac{\left(x+2\right)}{3}=\frac{\left(2x-1\right)}{4}\)

(x+2).4=3.(2x-1)

4x+8=6x-3

4x+6x=8-3

4x+6x=5

x.(4+6)=5

x.10=5

x=5:10

x=0,5

vậy x=0,5

(x+2):3=(2x-1):4

\(\Rightarrow\)sử dụng tc tỉ lệ thức ,ta có thể biến đổi như sau:

\(\frac{x+2}{3}\)=\(\frac{2x-1}{4}\)

\(\Rightarrow\)(x+2).4=(2x-1).3

\(\Rightarrow\)4x+8=6x-3

\(\Rightarrow\)4x-6x=-8-3

\(\Rightarrow\)-2x=-11

\(\Rightarrow\)x=\(\frac{11}{2}\)

cảm ơn nhiều nha