\(2\left(x-5\right)-3\left(x-4\right)=-6+15.\left(-3\right)\)

\(2x-10-3x+12=-51\)

\(2-x=-51\)

\(\Rightarrow x=2-\left(-51\right)=53\)

vậy x=53

       \(2\left(x-5\right)-3\left(x-4\right)=-6+15.\left(-3\right)\)

\(\Leftrightarrow2x-10-3x+12=-51\)

\(\Leftrightarrow\left(2x-3x\right)-\left(10-12\right)=51\)

\(\Leftrightarrow-x-\left(-2\right)=-51\)

\(\Leftrightarrow-x+2=-51\)

\(\Rightarrow-x=-53\)

\(\Rightarrow x=53\)

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\(a.x^{10}=x\)

\(=>x=1\)

a, (x-15):5+22=24

    ( x - 15 ) : 5 = 2

      x-15  = 10

       x = 25

Câu a:

(x -15) : 5 + 22 = 24

(x -15) : 5 = 24 - 22

(x -15) : 5 = 2

x - 15 = 2 x 5

x - 15 = 10

x = 10 + 15

x = 25

Vậy x = 25

a)Ta có: \(\frac{-2}{5}+\frac{6}{5}.\left(y-\frac{2}{3}\right)=\frac{-4}{15}\)

\(\Rightarrow\frac{6}{5}.\left(y-\frac{2}{3}\right)=\frac{-4}{15}-\frac{-2}{15}\)

\(\Rightarrow\frac{6}{5}.\left(y-\frac{2}{3}=\right)\frac{-2}{5}\)

\(\Rightarrow y-\frac{2}{3}=\frac{-2}{5}:\frac{6}{5}=\frac{-1}{3}\)

\(\Rightarrow y=\frac{-1}{3}+\frac{2}{3}=\frac{1}{3}\)

Vậy x = \(\frac{1}{3}\)

b) Ta có: \(\frac{-2}{5}+\frac{2}{3}x+\frac{1}{6}x=\frac{-4}{15}\)

        \(\Rightarrow\frac{-2}{5}+x.\left(\frac{2}{3}+\frac{1}{6}\right)=\frac{-4}{15}\)

        \(\Rightarrow x.\frac{5}{6}=\frac{-4}{15}-\frac{-2}{15}\)

         \(x.\frac{5}{6}=\frac{-2}{15}\)

\(\Rightarrow x=\frac{-2}{15}:\frac{5}{6}=\frac{-4}{25}\)

Vậy x = \(\frac{-4}{25}\)

c) Ta có: \(\frac{3}{2}x+\frac{-2}{5}-\frac{2}{3}.x=\frac{-4}{15}\)

\(\Rightarrow\frac{3}{2}x-\frac{2}{3}x+\frac{-2}{5}=\frac{-4}{15}\)

\(\Rightarrow x.\left(\frac{3}{2}-\frac{2}{4}\right)=\frac{-4}{15}-\frac{-2}{15}\)

\(\Rightarrow x.\frac{5}{6}=\frac{-2}{15}\)

\(\Rightarrow x=\frac{-2}{15}:\frac{5}{6}=\frac{-4}{25}\)

Vậy x = \(\frac{-4}{25}\)

Ủng hộ tớ nha m.n

a)Ta có: \(\frac{- 2}{5} + \frac{6}{5} . \left(\right. y - \frac{2}{3} \left.\right) = \frac{- 4}{15}\)

\(\Rightarrow \frac{6}{5} . \left(\right. y - \frac{2}{3} \left.\right) = \frac{- 4}{15} - \frac{- 2}{15}\)

\(\Rightarrow \frac{6}{5} . \left(\right. y - \frac{2}{3} = \left.\right) \frac{- 2}{5}\)

\(\Rightarrow y - \frac{2}{3} = \frac{- 2}{5} : \frac{6}{5} = \frac{- 1}{3}\)

\(\Rightarrow y = \frac{- 1}{3} + \frac{2}{3} = \frac{1}{3}\)

Vậy x = \(\frac{1}{3}\)

b) Ta có: \(\frac{- 2}{5} + \frac{2}{3} x + \frac{1}{6} x = \frac{- 4}{15}\)

        \(\Rightarrow \frac{- 2}{5} + x . \left(\right. \frac{2}{3} + \frac{1}{6} \left.\right) = \frac{- 4}{15}\)

        \(\Rightarrow x . \frac{5}{6} = \frac{- 4}{15} - \frac{- 2}{15}\)

         \(x . \frac{5}{6} = \frac{- 2}{15}\)

\(\Rightarrow x = \frac{- 2}{15} : \frac{5}{6} = \frac{- 4}{25}\)

Vậy x = \(\frac{- 4}{25}\)

c) Ta có: \(\frac{3}{2} x + \frac{- 2}{5} - \frac{2}{3} . x = \frac{- 4}{15}\)

\(\Rightarrow \frac{3}{2} x - \frac{2}{3} x + \frac{- 2}{5} = \frac{- 4}{15}\)

\(\Rightarrow x . \left(\right. \frac{3}{2} - \frac{2}{4} \left.\right) = \frac{- 4}{15} - \frac{- 2}{15}\)

\(\Rightarrow x . \frac{5}{6} = \frac{- 2}{15}\)

\(\Rightarrow x = \frac{- 2}{15} : \frac{5}{6} = \frac{- 4}{25}\)

Vậy x = \(\frac{- 4}{25}\)

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ko rảnh thì thôi đừng trả lời linh tinh chứ

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