Ta có:

\(\left(\frac{1}{32}\right)^7=\frac{1^7}{32^7}=\frac{1}{\left(2^5\right)^7}=\frac{1}{2^{35}}\)

\(\left(\frac{1}{16}\right)^9=\frac{1^9}{16^9}=\frac{1}{\left(2^4\right)^9}=\frac{1}{2^{36}}\)

Vì 2³⁵ < 2³⁶

=> \(\frac{1}{2^{35}}>\frac{1}{2^{36}}\)

=> \(\left(\frac{1}{32}\right)^7>\left(\frac{1}{16}\right)^9\)

\(\left(\frac{1}{32}\right)^7=\left[\left(\frac{1}{2}\right)^5\right]^7=\left(\frac{1}{2}\right)^{35}\)và \(\left(\frac{1}{16}\right)^9=\left[\left(\frac{1}{2}\right)^4\right]^9=\left(\frac{1}{2}\right)^{32}\)

Mà:\(\left(\frac{1}{2}\right)^{35}>\left(\frac{1}{2}\right)^{32}\Rightarrow\left(\frac{1}{32}\right)^7>\left(\frac{1}{16}\right)^9\)

Ta có:

3³²=(3²)¹⁶=9¹⁶

2¹⁶*9¹⁶=18¹⁶

Vì 18<19;16<17=>18¹⁶<19¹⁷

Vậy 2¹⁶.3³²<19¹⁷

k mình nha

Ta có: 16⁵⁰⁴ = (2⁴)⁵⁰⁴ = 2²⁰¹⁶

           32⁴⁰³ = (2⁵)⁴⁰³ = 2²⁰¹⁵

=> 16⁵⁰⁴  > 32⁴⁰³

a: 16¹² lớn hơn

b: 1/6​9 lớn hơn

ta có cả\(\dfrac{-11}{15}\)và \(\dfrac{-12}{16}\) đều bé hơn 1

ta có 1-\(\dfrac{-11}{15}\)=\(\dfrac{26}{15}\)

1-\(\dfrac{-12}{16}\)=\(\dfrac{28}{16}\)mà ​\(\dfrac{26}{15}\)​>\(\dfrac{28}{16}\)=>\(\dfrac{-11}{15}\)>\(\dfrac{-12}{16}\)

tick cho mình nha

thanks em hiếu