a) \(\frac{7}{15};\frac{3}{10};0;-\frac{3}{4};-\frac{5}{6}\)

b) 

1) \(-\frac{7}{5};-\frac{7}{9};0;\frac{4}{5};\frac{9}{11};\frac{3}{2}\)

2) \(-\frac{25}{26};-\frac{18}{19};-\frac{11}{12};-\frac{4}{5};-\frac{3}{4}\)

Theo thứ tự tăng dần là:

-7/5;-2/9;0;3/2

Ta có : \(\frac{-2}{9};\frac{-7}{5}\)

=> \(\frac{-2}{9}>\frac{-7}{5}\)

Sắp xếp theo thứ tự tăng dần là :

\(\frac{-7}{5};\frac{-2}{9};0;\frac{3}{2}\)

\(a\)) \(-17;-2;0;1;2;5\)

\(b\))\(2001;15;7;0;-8;-101\)

a) -17, -2, 0, 1, 2, 5. b) 2001, 15, 7, 0, -8, -101.

a: Ta có: -97<-72<-36<-15<-7<-2

=>\(\frac{-97}{24}<\frac{-72}{24}<\frac{-36}{24}<-\frac{15}{24}<-\frac{7}{24}<-\frac{2}{24}\)

b: Ta có: \(\frac{-3}{5}=\frac{-3\cdot4}{5\cdot4}=\frac{-12}{20}\)

\(\frac{1}{-5}=\frac{-1}{5}=\frac{-1\cdot4}{5\cdot4}=\frac{-4}{20}\)

\(\frac{-3}{4}=\frac{-3\cdot5}{4\cdot5}=\frac{-15}{20}\)

mà -4>-12>-15

nên \(\frac{1}{-5}>\frac{-3}{5}>-\frac34\)

=>\(\frac{1}{-5}>\frac{-3}{5}>\frac{-3}{4}>-1\left(1\right)\)

Ta có: \(-1=\frac{-12}{12};\frac{5}{-3}=\frac{-5}{3}=\frac{-5\cdot4}{3\cdot4}=\frac{-20}{12};\frac{5}{-4}=\frac{-5}{4}=\frac{-5\cdot3}{4\cdot3}=\frac{-15}{12}\)

mà -12>-15>-20

nên \(-1>\frac{-5}{4}>-\frac53\) (2)

Từ (1),(2) suy ra \(\frac{1}{-5}>\frac{-3}{5}>\frac{-3}{4}>\frac{-5}{4}>-\frac53\)

-2/15;-1/10;1/6;1/5;4/15,1/3;-2/-5

Vậy...

lấy máy tính mà sắp

\(\frac{-3}{8}=\frac{-9}{24}\)\(;\frac{-7}{12}=\frac{-14}{24};\frac{2}{3}=\frac{16}{24};\frac{5}{6}=\frac{20}{24}\)

Các số xếp thừ bứ đến lớn là: \(\frac{-14}{24};\frac{-9}{24};\frac{16}{24};\frac{20}{24}\)

HT

\(\frac{-9}{24}\); \(\frac{-14}{24}\); \(\frac{16}{24}\); \(\frac{20}{24}\)

=>\(\frac{-14}{24}\); \(\frac{-9}{24}\); \(\frac{16}{24}\); \(\frac{20}{24}\)

=>\(\frac{-7}{12}\); \(\frac{3}{-8}\); \(\frac{2}{3}\); \(\frac{5}{6}\)

-5/9;-1/3;-1/2;1/3;5/12;7/18

- 5/9 <  -1/3 < - 1/2 < 1/3 < 7/18 < 5/12

Học tốt!

\(\frac{-5}{6};\frac{2}{-3};\frac{-1}{8};\frac{-1}{-2}\)

\(-\frac{5}{6};\frac{2}{-3};\frac{-1}{8}\frac{-1}{-2}\)

giúp mk vơi s, thanks

\(a.\frac{-3}{5}< \frac{1}{-2}< \frac{-5}{-12}< \frac{2}{3}< \frac{3}{2}\)

\(b.\frac{6}{-5}< \frac{7}{-6}< \frac{9}{-10}< \frac{-2}{-5}< \frac{3}{4}\)

\(c.\frac{4}{-9}< \frac{-7}{21}< \frac{4}{-15}< \frac{8}{12}< \frac{24}{15}\)

Hok tốt :D