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Ta có :
\(\frac{7^5.6^8.\left(-3\right)^7}{9^2.7^4.6^9}\)\(=\frac{7^4.7.6^8.\left(-1.3\right)^7}{\left(3^2\right)^2.7^4.6^8.6}=\frac{7^4.7.6^8\left(-1\right)^7.3^4.3^3}{3^4.7^4.6^8.6}=\frac{7.\left(-1\right).27}{6}=-\frac{7.27}{6}=-\frac{189}{6}=-\frac{63}{2}\)
Ủng hộ mk nha !!! ^_^
Câu 1:
A = (4/9 + 5/6) : (7/8 - 7/12)
A = (8/18 + 15/18) :(21/24 - 14/24)
A = 23/18 : 7/24
A = 23/18 x 24/7
A = 92/21
Câu B = 3/4.8/9.15/16...9999/10000
B = \(\frac{1.3}{2.2}\).\(\frac{2.4}{3.3}\)....\(\frac{99.101}{100.100}\)
B = \(\frac{1.2.3\ldots99}{2.3\ldots100}\). \(\frac{3.4.\ldots101}{2.3\ldots100}\)
B = \(\frac{1}{100}\) x \(\frac{101}{2}\)
B = \(\frac{101}{200}\)
1, =\(\frac{2\left(\frac{1}{5}+\frac{1}{7}-\frac{1}{9}-\frac{1}{11}\right)}{4\left(\frac{1}{5}+\frac{1}{7}-\frac{1}{9}-\frac{1}{11}\right)}=\frac{1}{2}\)
2, A=\(\frac{1}{2}\cdot\frac{2}{3}\cdot\frac{3}{4}\cdot...\cdot\frac{99}{100}\)
= \(\frac{1\cdot2\cdot3\cdot....\cdot99}{2\cdot3\cdot4\cdot...\cdot100}=\frac{1}{100}\)
Vậy ......
hok tốt
#)Giải :
a) \(A=\frac{4^5.9^4-2^6.6^9}{2^{10}.3^8+6^8.20}=\frac{2^{10}.3^8-2^{10}.3^8.3}{2^{10}.3^8+2^8.3^8.2^2.5}=\frac{2^{10}.3^8-2^{10}.3^8.3}{2^{10}.3^8+2^{10}.3^8.5}=\frac{2^{10}.3^8\left(1-3\right)}{2^{10}.3^8\left(1+5\right)}=-\frac{1}{3}\)
\(a,A=\frac{2^{10}.3^8-2^{10}.3^9}{2^{10}.3^8+2^{10}.3^8.5}\)
\(=\frac{2^{10}.3^8\left(1-3\right)}{2^{10}.3^8\left(1+5\right)}=\frac{-1}{3}\)
Học tốt!!!!!!!!!!!!!
= 7^9 : 7^8
= 79-8
= 7
Học tốt!
=7(dung roi)
79:(-7)8
=79:78
=79-8
=71=7