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Sữa lỗi:
phần khai báo:a:array[1..250] of integer (ngoặc vuông ko phải ngoặc tròn)
Bài làm của bạn @lê chí hiếu(bạn được 2,1 điểm)
bài 1
program PTYN;
uses crt;
var a:array[1..100,1..100]of integer;
i,j,m,n:integer;
f1,f2:text;
Max, Min:Integer;
Kt:boolean;
Procedure XuatMang;
begin
For i:=1 to n do
begin
for j:=1 to m do
Write(a[i,j]:4);
Writeln;
end;
end;
Procedure MaxCot(l:Integer);
var p:Integer;
begin
Max:=A[1,l];
For p:=2 to n do
if A[p,l]>Max then Max:=A[p,l];
end;
Procedure MinHang(k:Integer);
var o:integer;
begin
Min:=A[k,1];
For o:=2 to n do
if A[k,o]<Min then Min:=A[k,o];
end;
begin
clrscr;
assign(f1,'ptyn.inp');
assign(f2,'ptyn.out');
reset(f1);rewrite(f2);
while not EOF(f1) do
begin
kt:=false;
readln(f1,n,m);
for i:=1 to n do
begin
for j:=1 to m do
Read(f1,a[i,j]);
readln(f1);
end;
for i:=1 to n do
begin
for j:=1 to n do
begin
MaxCot(j);
MinHang(i);
if Max=Min then
begin
Writeln(f2,'(',i,',',j,')');
kt:=true;
end;
end;
end;
If kt=false then Writeln(f2,'Khong co ptu yen ngua.');
end;
Close(f1); Close(f2);
Readln
End.
Bài 4
const fi='tvh.inp';
fo='tvh.out';
var n,d,dem,sl,s2cs,s3cs,s4cs,s5cs,s6cs,s7cs,k,i,d1:longint;
st,st1,stk:string;
f1,f2:text;
begin
assign(f1,fi); reset(f1);
assign(f2,fo); rewrite(f2);
readln(f1,n,k);
str(n,st);
d:=length(st);
case d of
1: write(9);
2: begin
sl:=n-9;
dem:=9+sl*2;
end;
3: begin
s2cs:=(99-10)+1;
s3cs:=n-99;
dem:=9+s2cs*2+s3cs*3;
end;
4: begin
s2cs:=(99-10)+1;
s3cs:=(999-100)+1;
s4cs:=n-999;
dem:=9+s2cs*2+s3cs*3+s4cs*4;
end;
5: begin
s2cs:=(99-10)+1;
s3cs:=(999-100)+1;
s4cs:=(9999-1000)+1;
s5cs:=n-9999;
dem:=9+s2cs*2+s3cs*3+s4cs*4+s5cs*5;
end;
6: begin
s2cs:=(99-10)+1;
s3cs:=(999-100)+1;
s4cs:=(9999-1000)+1;
s5cs:=(99999-10000)+1;
s6cs:=n-99999;
dem:=9+s2cs*2+s3cs*3+s4cs*4+s5cs*5+s6cs*6;
end;
7: begin
s2cs:=(99-10)+1;
s3cs:=(999-100)+1;
s4cs:=(9999-1000)+1;
s5cs:=(99999-10000)+1;
s6cs:=(999999-1000000)+1;
s7cs:=n-999999;
dem:=9+s2cs*2+s3cs*3+s4cs*4+s5cs*5+s6cs*6+s7cs*7;
end;
end;
if k<=dem then
begin
i:=1;
d1:=0;
repeat
str(i,st1);
d1:=d1+length(st1);
i:=i+1;
until d1>=k;
stk:=st1[length(st1)-(d1-k)];
writeln(f2,stk);
end;
close(f1);
close(f2);
end.
Bài 5
PROGRAM robot;
VAR A:ARRAY[0..30,0..30] OF BYTE;
F:ARRAY[0..30,0..30] OF LONGINT;
m,n:INTEGER;
PROCEDURE Enter;
VAR i,j:INTEGER;
BEGIN
readln(m,n);
FOR i:=1 TO m DO
BEGIN
FOR j:=1 TO n DO read(A[i,j]);
readln;
END;
FOR i:=0 TO m DO A[i,0]:=-1;
FOR j:=0 TO n DO A[0,j]:=-1;
END;
FUNCTION Max(a,b:LONGINT):LONGINT;
BEGINIF (a>b) THEN Max:=a ELSE Max:=b;
END;
PROCEDURE Optimize;
VAR i,j:INTEGER;
BEGIN
FOR i:=0 TO m DO F[i,0]:=-1;
FOR j:=0 TO n DO F[0,j]:=-1;
F[0,1]:=0;
FOR i:=1 TO m DO
FOR j:=1 TO n DO
F[i,j]:=2*Max(F[i,j-1],F[i-1,j])+A[i,j];
END;
PROCEDURE Trace(i,j:INTEGER);
BEGINIF (i=1) AND (j=1) THEN
writeln(F[m,n])
ELSE
BEGIN
IF F[i,j-1]>F[i-1,j] THEN
Trace(i,j-1)
ELSE
Trace(i-1,j);
writeln(i,' ',j);
END;
END;
BEGIN
Assign(Input,'Robot.inp'); Reset(Input);
Assign(Output,'Robot.out');Rewrite(Output);
Enter;
Optimize;
Trace(m,n);
close(Input);
close(Output);
END.
Em hiểu,nhưng cách anh chỉ đến 8 chữ số là cùng.
Cách em thì chỉ cần lấy int64(em dùng luôn mấy biến real vì bự hơn) thì chấp 10^30
Câu 1: Bạn phải cho xâu S như thế nào đã chứ. Nhìn chung đoạn chương trình không mắc lỗi nào về cú pháp.
Câu 2:
Program hotrotinhoc;
var s1,s2: string;
begin
write('Nhap xau s1 :'); readln(s1);
write('Nhap xau s2 :'); readln(s2);
insert(s1,s2,1);
write('Xau s2 sau khi chen la :',s2);
readln
end.
Bài 1:
uses crt;
var a:array[1..100,1..100]of integer;
m,n,i,j,k,g,tam:integer;
begin
clrscr;
write('nhap so n='); readln(n);
write('nhap so m='); readln(m);
for i:=1 to n do
for j:=1 to m do
begin
write('a[',i,',',j,']='); readln(a[i,j]);
end;
{----------------------------------------------------------}
for i:=1 to n do
begin
for j:=1 to m do
write(a[i,j]:4);
writeln;
end;
{----------------------------------------------------------}
writeln('day tang dan cua ma tran la: ');
for i:=1 to n do
for j:=1 to m do
for k:=1 to n do
for g:=1 to m do
if a[i,j]<a[k,g] then begin
tam:=a[k,g];
a[k,g]:=a[i,j];
a[i,j]:=tam;
end;
writeln;
for i:=1 to n do
begin
for j:=1 to m do
write(a[i,j]:4);
writeln;
end;
{---------------------------------------------------------}
writeln('day giam dan cua ma tran la: ');
for i:=1 to n do
for j:=1 to m do
for k:=1 to n do
for g:=1 to m do
if a[i,j]>a[k,g] then begin
tam:=a[k,g];
a[k,g]:=a[i,j];
a[i,j]:=tam;
end;
writeln;
for i:=1 to n do
begin
for j:=1 to m do
write(a[i,j]:4);
writeln;
end;
readln;
end.
Bài 2:
uses crt;
var a:array[1..100,1..100]of integer;
i,j,n,m,snn,sln,vtc,vth,x,z,kt,k:integer;
begin
clrscr;
{----------nhap----------}
write('nhap n: ');readln(n);
write('nhap m='); readln(m);
for i:=1 to n do
for j:=1 to m do
begin
write('a[',i,',',j,']='); readln(a[i,j]);
end;
{----------nho nhat hang----------}
for i:=1 to n do
begin
snn:=a[i,1];
for j:=1 to m do
if snn>=a[i,j] then
begin
snn:=a[i,j];
vth:=i;
vtc:=j;
end;
kt:=0;
sln:=a[vth,vtc];
for k:=1 to n do
if sln<a[k,vtc] then kt:=1;
if kt=0 then writeln(k,',',vtc);
end;
readln;
end.
Bài 3:
Program HOC24;
const fi='Nhapvao.txt';
var f: text;
begin
assign(f,fi);
reset(f);
close(f);
end.
Bài 2:
Program HOC24;
const fo='CaDao.txt';
var f: text;
begin
assign(f,fo);
rewrite(f);
writeln(f,'Cong cha nhu nui thai son');
writeln(f,'Nghia me nhu nuoc trong nguon chay ra.');
writeln(f,'Mot long tho me kinh cha');
write(f,'Cho tron chu hieu moi la dao con');
close(f);
end.
Câu 1:
uses crt;
var n,i,t:integer;
begin
clrscr;
write('n='); readln(n);
t:=0;
for i:=1 to n do
t:=t+i;
writeln('tong cua ',n,' so nguyen dau tien la: ',t);
readln;
end.
Câu 2:
uses crt;
var i,t:integer;
begin
clrscr;
t:=0;
for i:=1 to 10 do
if i mod 2=0 then t:=t+i;
writeln('tong cac so chan trong 10 so nguyen dau tien la: ',t);
readln;
end.
Câu 3:
uses crt;
var i,t:integer;
begin
clrscr;
t:=0;
for i:=1 to 10 do
if i mod 2=0=1 then t:=t+i;
writeln('tong cac so le trong 10 so nguyen dau tien la: ',t);
readln;
end.
Câu 4:
uses crt;
var i,dem:integer;
begin
clrscr;
dem:=0;
for i:=1 to 10 do
if i mod 2=0 then inc(dem);
writeln('so cac so chan trong 10 so nguyen dau tien la: ',dem);
readln;
end.
Câu 5:
uses crt;
var i,dem:integer;
begin
clrscr;
dem:=0;
for i:=1 to 10 do
if i mod 2=1 then inc(dem);
writeln('so cac so le trong 10 so nguyen dau tien la: ',dem);
readln;
end.
Câu 6:
uses crt;
var i,n,dem:integer;
begin
clrscr;
write('n='); readln(n);
dem:=0;
for i:=1 to n do
if n mod i=0 then dem:=dem+1;
writeln('so luong uoc cua ',n,' la: ',dem);
readln;
end.
Câu 7:
uses crt;
var i,t,n:integer;
begin
clrscr;
write('n='); readln(n);
t:=0;
for i:=1 to n do
if n mod i=0 then t:=t+i;
writeln('tong cac uoc cua ',n,' la: ',t);
readln;
end.
Câu 8:
uses crt;
var n,i,dem:integer;
begin
clrscr;
write('n='); readln(n);
dem:=0;
for i:=1 to n do
if i mod 3=0 then inc(dem);
writeln('so cac so chia het cho 3 trong pham vi tu 1 toi',n,' la: ',dem);
readln;
end.
Câu 9:
uses crt;
var i,t,n:integer;
begin
clrscr;
write('n='); readln(n);
t:=0;
for i:=1 to n do
if i mod 3=0 then t:=t+i;
writeln('tong cac so chia het cho 3 trong pham vi tu 1 toi ',n,' la: ',t);
readln;
end.
1:
readln(n);
if n mod 2<>0 then t:=t*n
write('t=',t);
readln;