x²-2x+1-y²+2y-1

=(x-1)²-(y²-2y+1)

=(x-1)²-(y-1)²

a.)x^2-y^2-2x+2y

=(x-y)(x+y)-2(x-y)

=(x-y)(x+y-2)

Theo bài ra , ta có : 

4x² - 4xy + 8y² 

= (2x)² - 2.2xy + y² + 7y² 

= (2x + y)² + 7y² 

Chúc bạn hôc tốt =))

A= \(^{x^3+3x^2y-4xy^2-12y^3=x^2\left(x+3y\right)-4y^2\left(x+3y\right)=\left(x+3y\right)\left(x^2-4y^2\right)}\)

\(x^8y^8+x^4y^4+1=\left[\left(x^4y^4\right)^2+2x^4y^4+1\right]-x^4y^4=\left(x^4y^4+1\right)^2-\left(x^2y^2\right)^2\)

\(=\left(x^4y^4+1-x^2y^2\right)\left(x^4y^4+1+x^2y^2\right)\)

\(=\left(x^4y^4+1-x^2y^2\right)\left[\left(x^2y^2\right)^2+2x^2y^2+1-x^2y^2\right]\)

\(=\left(x^4y^4+1-x^2y^2\right)\left[\left(x^2y^2+1\right)^2-\left(xy\right)^2\right]\)

\(=\left(x^4y^4+1-x^2y^2\right)\left(x^2y^2+1-xy\right)\left(x^2y^2+1+xy\right)\)

Phân tích đa thức thành nhân tử

x³+3x²y−9xy²+5y²

x⁸y⁸+x⁴y⁴+1

a/ = xy(5y - 6x)

b/ = - (15y² - 2x + 5y - 10xy)

a,x²-4xy+4y²

=(x-2y²

b,4x⁴+9y²-12x²y

=(2x²)²+(3y)²-12x²y

(2x²-3y)

a) x² - 4xy + 4y²

= x² - 2.x.2y + (2y)²

=( x- y)²

b) 4x⁴ + 9y² -12x²y

= (2x²)² +12x²y + (3y)²

= [(2x2)  - 3y]

a) 5x² - 10x = 5x( x - 2 )

b) x² - y² - 2x + 2y = (x² - y²) - (2x - 2y)

                             = (x - y ) ( x + y)-2 (x-y)

                             = ( x - y) ( x + y - 2)

c) 4x² - 4xy - 8y² = (4x² - 4xy + 8y²) - 9y²

                           = (2x - 9y²) - 3y²

                           = (2x - y - 3y) (2x - y + 3y)

                           = (2x - 4y) (2x + 2y)

                            = 4(x - 2y) (x + y)

a) 5x² - 10x = 5x( x - 2 )

b) x² - y² - 2x + 2y = (x² - y²) - (2x - 2y)

                             = (x - y ) ( x + y)-2 (x-y)

                             = ( x - y) ( x + y - 2)

c) 4x² - 4xy - 8y² = (4x² - 4xy + 8y²) - 9y²

                           = (2x - 9y²) - 3y²

                           = (2x - y - 3y) (2x - y + 3y)

                           = (2x - 4y) (2x + 2y)

                            = 4(x - 2y) (x + y)

x²-4xy+4y²-x+2y=(x-2y)²-(x-2y)

                         =(x-2y)(x-2y-1)

\(12x-9-4x^2=-\left(2x-3\right)^2\\ Sửa:x^3-6x^2y+12xy^2-8y^3=\left(x-2y\right)^3\)

x² - 2x + 2y - xy = (x² - 2x) - (xy - 2y) = x(x - 2) - y(x - 2) = (x - 2)(x - y)

x² + 4xy - 16 + 4y² = (x² + 4xy + 4y²) - 16 = (x + 2y)² - 16 = (x + 2y + 4)(x + 2y - 4)

cảm ơn nha