a) Ta có :

\(x-3=x+5-8\)chia hết cho \(x+5\)\(\Rightarrow\)\(-8\)chia hết cho \(x+5\)\(\Rightarrow\)\(\left(x+5\right)\inƯ\left(-8\right)\)

Mà \(Ư\left(-8\right)=\left\{1;-1;2;-2;4;-4;8;-8\right\}\)

Suy ra \(n\in\left\{-4;-6;-3;-7;-1;-9;3;-13\right\}\)

     \(x-3\)\(⋮\)\(x+5\)

\(\Leftrightarrow\)\(x+5-8\)\(⋮\)\(x+5\)

Ta thấy     \(x+5\)\(⋮\)\(x+5\)

nên    \(8\)\(⋮\)\(x+5\)

\(\Rightarrow\)\(x+5\)\(\inƯ\left(8\right)=\left\{\pm1;\pm2;\pm4;\pm8\right\}\)

\(\Rightarrow\)\(x=\left\{-13;-9;-7;-6;-4;-3;-1;3\right\}\)

Vậy...

g: \(x-\frac{7}{12}x+\frac38x=\frac{5}{24}\)

=>\(x\left(1-\frac{7}{12}+\frac38\right)=\frac{5}{24}\)

=>\(x\left(\frac{24}{24}-\frac{14}{24}+\frac{9}{24}\right)=\frac{5}{24}\)

=>\(x\cdot\frac{19}{24}=\frac{5}{24}\)

=>\(x=\frac{5}{24}:\frac{19}{24}=\frac{5}{19}\)

h: \(\left(x-\frac13\right)^2-\frac12=1\frac34\)

=>\(\left(x-\frac13\right)^2-\frac12=\frac74\)

=>\(\left(x-\frac13\right)^2=\frac12+\frac74=\frac94\)

=>\(\left[\begin{array}{l}x-\frac13=\frac32\\ x-\frac13=-\frac32\end{array}\right.\Rightarrow\left[\begin{array}{l}x=\frac32+\frac13=\frac{9+2}{6}=\frac{11}{6}\\ x=\frac{-3}{2}+\frac13=\frac{-9+2}{6}=-\frac76\end{array}\right.\)

\(\frac{1}{2}\times\left(x-\frac{4}{5}\right)+\frac{3}{4}x=\frac{5}{12}\)

\(\Leftrightarrow\frac{1}{2}x-\frac{2}{5}+\frac{3}{4}x=\frac{5}{12}\)

\(\Leftrightarrow\frac{1}{2}x+\frac{3}{4}x=\frac{5}{12}+\frac{2}{5}\)

\(\Leftrightarrow\frac{5}{4}x=\frac{49}{60}\)

\(\Leftrightarrow x=\frac{49}{75}\)

Vậy \(x=\frac{49}{75}\)

bạn ơi sao lại có 2/5 vâỵ

a, x(x+1)=0

=>\(\orbr{\begin{cases}x=0\\x+1=0\end{cases}}\)<=>\(\orbr{\begin{cases}x=0\\x=-1\end{cases}}\)

b,(x-1)(x+3)=0

=>\(\orbr{\begin{cases}x-1=0\\x+3=0\end{cases}}\)<=>\(\orbr{\begin{cases}x=1\\x=-3\end{cases}}\)

x= -3/4 nhé bạn

Trả lời:

4x+18/4 =3/2

-> 4x + 9/2=3/2

-> 4x = -6/2= -3

-> x=-3/4

17 - | x+1 | = | - 15 |

=> 17 - | x+1 | = 15

=> | x+1| = 15+17 = 32

Chúc bn hc tốt

17 - | x+1 | = | - 15 |

=> 17 - | x+1 | = 15

=> | x+1| = 15+17 = 32

    TH1: x+1 = 32

    => x = 32-1 = 31

    TH2: x+1 = -32

    => x = -32-1 = -33

Vậy, x = 31 hoặc x = -33