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Ta có: \(A = \frac{4}{7.31} + \frac{6}{7.41} + \frac{9}{10.41} + \frac{7}{10.57}\)

\(= \frac{20}{35.31} + \frac{30}{35.41} + \frac{45}{50.41} + \frac{35}{50.57}\)

\(= 5 \left(\right. \frac{4}{31.35} + \frac{6}{35.41} + \frac{9}{41.50} + \frac{7}{50.57} \left.\right)\)

\(= 5 \left(\right. \frac{1}{31} - \frac{1}{35} + \frac{1}{35} - \frac{1}{41} + \frac{1}{41} - \frac{1}{50} + \frac{1}{50} - \frac{1}{57} \left.\right)\)

\(= 5 \left(\right. \frac{1}{31} - \frac{1}{57} \left.\right)\)

\(B = \frac{7}{19.31} + \frac{5}{19.43} + \frac{3}{23.43} + \frac{11}{23.57}\)

\(= \frac{14}{38.31} + \frac{10}{38.43} + \frac{6}{46.43} + \frac{22}{46.57}\)

\(= 2 \left(\right. \frac{7}{31.38} + \frac{5}{38.43} + \frac{3}{43.46} + \frac{11}{46.57} \left.\right)\)

\(= 2 \left(\right. \frac{1}{31} - \frac{1}{38} + \frac{1}{38} - \frac{1}{43} + \frac{1}{43} - \frac{1}{46} + \frac{1}{46} - \frac{1}{57} \left.\right)\)

\(= 2 \left(\right. \frac{1}{31} - \frac{1}{57} \left.\right)\)

\(\Rightarrow \frac{A}{B} = \frac{5 \left(\right. \frac{1}{31} - \frac{1}{57} \left.\right)}{2 \left(\right. \frac{1}{31} - \frac{1}{57} \left.\right)} = \frac{5}{2}\)

d=43/37d=43/37 × 23/15−43/3723/15−43/37 × 8/15+31/378/15+31/37

=43/37=43/37 x 23/15+43/3723/15+43/37 x (−8/15)+31/37(−8/15)+31/37

=43/37(23/15−8/15)+31/37=43/37(23/15−8/15)+31/37

=43/37.1+31/37=43/37.1+31/37

=2=2

E=−5/24E=−5/24 × 9/11−5/249/11−5/24 × 2/11+7/122/11+7/12

=−5/24(9/11+2/11)+7/12=−5/24(9/11+2/11)+7/12

=−5/24.1+7/12=−5/24.1+7/12

=3/8=3/8

a)3/7–−11/14−7/3×6/7a)3/7–−11/14−7/3×6/7

=3/7−−11/14−2=3/7−−11/14−2

=3/7+11/14−2=3/7+11/14−2

=−11/14=−11/14

b)6/5:3/2+−2/3×9/14b)6/5:3/2+−2/3×9/14

=4/5−3/7=4/5−3/7

=13/35

d=43/37d=43/37 × 23/15−43/3723/15−43/37 × 8/15+31/378/15+31/37

=43/37=43/37 x 23/15+43/3723/15+43/37 x (−8/15)+31/37(−8/15)+31/37

=43/37(23/15−8/15)+31/37=43/37(23/15−8/15)+31/37

=43/37.1+31/37=43/37.1+31/37

=2=2

E=−5/24E=−5/24 × 9/11−5/249/11−5/24 × 2/11+7/122/11+7/12

=−5/24(9/11+2/11)+7/12=−5/24(9/11+2/11)+7/12

=−5/24.1+7/12=−5/24.1+7/12

=3/8=3/8

a)3/7–−11/14−7/3×6/7a)3/7–−11/14−7/3×6/7

=3/7−−11/14−2=3/7−−11/14−2

=3/7+11/14−2=3/7+11/14−2

=−11/14=−11/14

b)6/5:3/2+−2/3×9/14b)6/5:3/2+−2/3×9/14

=4/5−3/7=4/5−3/7

=13/35

câu cuối là 999,7650928....

rồi mà, câu 3 là 100 

1; - 7264 + (1543 + 7264)

= - 7264 + 1543 + 7264

= (-7264 + 7264) + 1543

= 0 + 1543

= 1543

2; (14497) - 144

= 14497 - 144

= 14353

3; (-145).(18145)

= -145.18145

= -2631025

4; 111 + (-11 + 27)

= 111 + 16

= 127