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a) \(-12\left(x-5\right)+7\left(3-x\right)=5\)
\(-12x+60+21-7x=5\)
\(-19x=5-60-21\)
\(-19x=-76\)
\(x=4\)
vậy \(x=4\)
tương tự
A, 5+ ( -12 ) - 10 = -17
B, 25 - (-17) + 24 -12=54
C, 5^6 : 5^4 + 2^3 . 2^2 -225 : 15^2 =56
D, ( -5 - 3). (3 -5 ) : ( -3 + 5)=8
E,4. (13-16) -(3-5).(-3^2) =15
F, 235 - (34 + 135)-100=-34
a; (4 - \(\dfrac{12}{5}\)).\(\dfrac{25}{8}\) - \(\dfrac{2}{5}\) : - \(\dfrac{4}{25}\)
= 4.\(\dfrac{25}{8}\) - \(\dfrac{12}{5}\).\(\dfrac{25}{8}\) - \(\dfrac{2}{5}\) x \(\dfrac{-25}{4}\)
= \(\dfrac{25}{2}\) - \(\dfrac{15}{2}\) + \(\dfrac{5}{2}\)
= \(\dfrac{10}{2}\) + \(\dfrac{5}{2}\)
= \(\dfrac{15}{2}\)
b; (- \(\dfrac{5}{24}\) + \(\dfrac{3}{4}\) - \(\dfrac{7}{12}\)) : (- \(\dfrac{5}{16}\))
= (- \(\dfrac{5}{24}\)) : (-\(\dfrac{5}{16}\)) + \(\dfrac{3}{4}\) : (- \(\dfrac{5}{16}\)) - \(\dfrac{7}{12}\) : (- \(\dfrac{5}{16}\))
= \(\dfrac{5}{24}\) x \(\dfrac{16}{5}\) - \(\dfrac{3}{4}\) x \(\dfrac{16}{5}\) + \(\dfrac{7}{12}\) x \(\dfrac{16}{5}\)
= \(\dfrac{2}{3}\) - \(\dfrac{12}{5}\) + \(\dfrac{28}{15}\)
= \(\dfrac{10}{15}\) - \(\dfrac{36}{15}\) + \(\dfrac{28}{15}\)
= \(\dfrac{-26}{15}\) + \(\dfrac{28}{15}\)
= \(\dfrac{2}{15}\)
5/3+5/6+5/12+5//24+...+5/384
\(\frac{5}{3}+\frac{5}{6}+\frac{5}{12}++...+\frac{5}{384}\)
\(\Leftrightarrow\frac{5}{1.3}+\frac{5}{3.2}+\frac{5}{2.6}+...+\frac{5}{6.64}\)
\(\Rightarrow\frac{1}{1}-\frac{1}{3}+\frac{1}{3}-\frac{1}{2}+\frac{1}{2}-\frac{1}{6}+...\frac{1}{6}-\frac{1}{64}\)
\(\Rightarrow\frac{1}{1}-\frac{1}{64}\)
\(=\frac{63}{64}\)
Theo mình nghĩ chắc vậy ^-^
đề cho bằng bao nhiêu vậy
\(A=\frac{5}{3}+\frac{5}{6}+\frac{5}{12}+\frac{5}{24}+...+\frac{5}{384}\)
\(A\cdot2=\frac{10}{3}+\frac{5}{3}+\frac{5}{6}+\frac{5}{12}+...+\frac{5}{192}\)
\(A\cdot2-A=\left(\frac{10}{3}+\frac{5}{3}+\frac{5}{6}+\frac{5}{12}+...+\frac{5}{192}\right)-\left(\frac{5}{3}+\frac{5}{6}+\frac{5}{12}+\frac{5}{24}+...+\frac{5}{384}\right)\)
\(A=\frac{10}{3}-\frac{5}{384}\)
\(A=\frac{425}{128}\)