7/11 x 6/5 

= 42/55

Bằng 105/55 đó bạn

\(a.\left(\frac{6}{11}+\frac{5}{11}\right).\frac{3}{7}=1\cdot\frac{3}{7}=\frac{3}{7}b.\frac{3}{5}\cdot\frac{7}{9}+\frac{3}{5}\cdot\frac{2}{9}=\frac{3}{5}\cdot\left(\frac{7}{9}+\frac{2}{9}\right)=\frac{3}{5}\cdot1=\frac{3}{5}\)

-5/21-10/21-(-5/7)
=-5/21-10/21+15/21
=0

0

\(\frac{1}{11}+\frac{2}{11}+\frac{3}{11}+\frac{4}{11}+\frac{5}{11}+\frac{6}{11}+\frac{7}{11}+\frac{8}{11}+\frac{9}{11}+\frac{10}{11}\)

\(=\frac{1+2+3+4+5+6+7+8+9+10}{11}\)

\(=\frac{\left(1+10\right)+\left(2+9\right)+\left(3+8\right)+\left(4+7\right)+\left(5+6\right)}{11}\)

\(=\frac{11+11+11+11+11}{11}\)

\(=\frac{11\cdot5}{11}=5\)

\(= \frac{1 + 2 + 3 + 4 + 5 + 6 + 7 + 8 + 9 + 10}{11}\)

\(1 + 2 + 3 + 4 + 5 + 6 + 7 + 8 + 9 + 10 = 55\)

Vậy là bằng 55/11 nhé bạn

\(a,\left(\frac{6}{11}+\frac{5}{11}\right)\times\frac{3}{7}\)

Cách 1: \(\left(\frac{6}{11}+\frac{5}{11}\right)\times\frac{3}{7}=1\times\frac{3}{7}=\frac{10}{7}\)

Cách 2: \(\left(\frac{6}{11}+\frac{5}{11}\right)\times\frac{3}{7}=\frac{6}{11}\times\frac{3}{7}+\frac{5}{11}\times\frac{3}{7}=\frac{18}{77}+\frac{15}{77}=\frac{33}{77}=\frac{3}{7}\)

\(b,\frac{3}{5}\times\frac{7}{9}+\frac{3}{5}\times\frac{2}{9}\)

Cách 1: \(\frac{3}{5}\times\frac{7}{9}+\frac{3}{5}\times\frac{2}{9}=\frac{7}{15}+\frac{2}{15}=\frac{9}{15}\)

Cách 2: \(\frac{3}{5}\times\frac{7}{9}+\frac{3}{5}\times\frac{2}{9}=\frac{3}{5}\times1=\frac{3}{5}\)

P/s: Ý B có vấn đề thì phải

\(a,\left(\frac{6}{11}+\frac{5}{11}\right)x\frac{3}{7}\)

\(=\frac{11}{11}=1x\frac{3}{7}\)

\(=\frac{3}{7}\)

cach 2 

\(\frac{6}{11}x\frac{3}{7}+\frac{5}{11}x\frac{3}{7}\)

\(=\frac{18}{77}+\frac{15}{77}\)

\(=\frac{33}{77}=\frac{3}{7}\)

\(b,\frac{3}{5}x\frac{7}{9}+\frac{3}{5}x\frac{2}{9}\)

\(=\frac{21}{45}+\frac{6}{45}\)

\(=\frac{27}{45}=\frac{3}{5}\)

cách 2 : 

\(\frac{3}{5}x\left(\frac{7}{9}+\frac{2}{9}\right)\)

\(=\frac{3}{5}x\frac{9}{9}\)

\(=\frac{27}{45}=\frac{3}{5}\)

a, \(\frac{5}{11}\times\frac{7}{25}+\frac{15}{11}\times\frac{1}{5}\)

\(=\frac{5}{11}\times\frac{7}{25}+\frac{5}{11}\times\frac{3}{5}\)

\(=\frac{5}{11}\times\left(\frac{7}{25}+\frac{3}{5}\right)\)

\(=\frac{5}{11}\times\frac{22}{25}\)

\(=\frac{2}{5}\)

b, \(\frac{3}{7}\times\frac{25}{19}-\frac{1}{7}\times\frac{18}{19}\)

\(=\frac{1}{7}\times\frac{75}{19}-\frac{1}{7}\times\frac{18}{19}\)

\(=\frac{1}{7}\times\left(\frac{75}{19}-\frac{18}{19}\right)\)

\(=\frac{1}{7}\times3\)

\(=\frac{3}{7}\)

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\(\frac{5}{7}+\frac{7}{5}=\)

ta quy đồng thuaa số lên rồi cộng sẽ ra\(\frac{25}{35}+\frac{49}{35}=\frac{74}{35}\)

mình giải thích nghe hơi khó những món bạn k

\(\frac{5}{7}+\frac{7}{5}=\frac{25}{35}+\frac{49}{35}=\frac{25+49}{35}=\frac{74}{35}\)

\(\frac{3}{7}+\frac{4}{5}+\frac{4}{7}=\left(\frac{3}{7}+\frac{4}{7}\right)+\frac{4}{5}=1+\frac{4}{5}=\frac{9}{5}\)

\(\frac{6}{11}+\frac{1}{3}+\frac{5}{11}=\left(\frac{6}{11}+\frac{5}{11}\right)+\frac{1}{3}=1+\frac{1}{3}=\frac{4}{3}\)

a) \(\frac{3}{7}+\frac{4}{5}+\frac{4}{7}\)

 = \(\left(\frac{3}{7}+\frac{4}{7}\right)+\frac{4}{5}\)

 = \(1+\frac{4}{5}\)

 = \(\frac{9}{5}\)

b) \(\frac{6}{11}+\frac{1}{3}+\frac{5}{11}\)

 = \(\left(\frac{6}{11}+\frac{5}{11}\right)+\frac{1}{3}\)

 = \(1+\frac{1}{3}\)

 = \(\frac{4}{3}\)