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xy+x+y=2
xy+x+y+1=2+1
(xy+x)+(y+1)=3
x(y+1)+(y+1)=3
(x+1)(y+1)=3=1.3=3.1=-1.-3=-3.-1
\(\Rightarrow\left[{}\begin{matrix}x+1=1;y+1=3\\x+1=3;y+1=1\\x+1=-1;y+1=-3\\x+1=-3;y+1=-1\end{matrix}\right.\)
\(\Leftrightarrow\left[{}\begin{matrix}x=0;y=2\\x=2;y=0\\x=-2;y=-4\\x=-4;y=-2\end{matrix}\right.\)
Vậy:.................
xy+14+2y+7x= -10
\(\Leftrightarrow\)y(x+2)+7(x+2)=-10
\(\Leftrightarrow\)(y+7)(x+2)=-10=1.(-10)=2.(-5)=5.(-2)=10.(-1)
| y+7 | 1 | 2 | 5 | 10 |
| x+2 | -10 | -5 | -2 | -1 |
| y | -6 | -5 | -2 | 3 |
| x | -12 | -7 | -4 | -3 |
3x-(-17)=14
3x=14+(-17)
3x=-3
x=(-3):3
x=-1
Vậy x=-1.
|x+9|.2=10
|x+9|=10:2
|x+9|=5
\(\Rightarrow\orbr{\begin{cases}x+9=-5\\x+9=5\end{cases}\Rightarrow\orbr{\begin{cases}x=-14\\x=-4\end{cases}}}\)
Vậy \(x\in\left\{-14;-4\right\}\)
\(3x-\left(-17\right)=14\)
\(3x+17=14\)
\(3x=14-17\)
\(3x=-3\)
\(x=-1\)
\(a,\left|x+9\right|.2=10\)
\(\left|x+9\right|=5\)
\(th1:x+9=5\)
\(x=-4\)
\(Th2:x+9=-5\)
\(x=-14\)
Vậy.....
hok tốt!!
Trả lời
568-{5.[143-3.(14-1)]+10}:10
=568-{5.[143-3.13]+10}:10
=568-{5.[143-39]+10}:10
=568-{5.104+10}:10
=568-530:10
=568-53
=515
568-{5x[143-3x13+10}:10
=568-{5x[143-39+10}:10
=568-(5x114):10
=568-570:10
=568-57
=511
a) \(-13+x=39\)
\(\Leftrightarrow x=52\)
Vậy x=52
b) \(3x-\left(-17\right)=14\)
\(\Leftrightarrow3x+17=14\)
\(\Leftrightarrow3x=-3\)
\(\Leftrightarrow x=-1\)
\(c)|x+9|\cdot2=10\)
\(\Leftrightarrow|x+9|=5\)
\(\Leftrightarrow\orbr{\begin{cases}x+9=5\\x+9=-5\end{cases}\Leftrightarrow\orbr{\begin{cases}x=4\\x=-14\end{cases}}}\)
a)
\(\frac{2}{3}+\frac{1}{3}:x=\frac{3}{5}\)
\(\frac{1}{3}:x=\frac{3}{5}-\frac{2}{3}\)
\(\frac{1}{3}:x=\frac{-1}{15}\)
\(x=\frac{1}{3}:\frac{-1}{15}\)
\(x=-5\)
b)
\(\frac{10}{3x}+\frac{67}{4}=-13.25\)
\(\frac{10}{3x}+\frac{67}{4}=\frac{-53}{4}\)
\(\frac{10}{3x}=\frac{-53}{4}+\frac{67}{4}\)
\(\frac{10}{3x}=\frac{7}{2}\)
\(\Rightarrow10.2=7.3x\)
\(20=21x\)
\(x=\frac{20}{21}\)
c)
x+30%x=-1.3
x+0.3x=-1.3
x (1+0.3) = -1.3
x . 1.3 = -1.3
x = -1.3 : 1.3
x = 1
d)
\(\left(\frac{14}{5x}-50\right):\frac{2}{3}=51\)
\(\frac{14}{5x}-50=51.\frac{2}{3}\)
\(\frac{14}{5x}-50=34\)
\(\frac{14}{5x}=34+50\)
\(\frac{14}{5x}=84\)
\(84.5x=14\)
420x = 14
\(x=\frac{1}{30}\)
a, \(\frac{2}{3}+\frac{1}{3}:x=\frac{3}{5}\)
=> \(\frac{1}{3}:x=\frac{3}{5}-\frac{2}{3}\)
=>\(\frac{1}{3}:x=\frac{-1}{15}\)
=> \(x=\frac{1}{3}:\frac{-1}{15}\)
=> \(x=\frac{-1}{5}\)
a) 3x - 10 = 2x + 13
<=> 3x - 2x = 13+10
<=> x = 23
Vậy x = 23
b) x + 12 = -5 - x
<=> x + x = -5 - 12
<=> 2x = -17
<=> x = -17 : 2
<=> x = -8,5
Vậy x = -8,5
c) x + 5 = 10 - x
<=> x + x = 10 - 5
<=> 2x = 5
<=> x = 5 : 2
<=> x = 2,5
Vậy x = 2,5
d) 6x + 2 ^ 3 = 2x - 12
<=> 6x + 8 = 2x - 12
<=> 6x - 2x = -12 - 8
<=> 4x = -20
<=> x = -20 : 4
<=> x = -5
Vậy x = -5
e) 12 - x = x + 1
<=> -x - x = 1 - 12
<=> -2x = -11
<=> x = -11 : (-2)
<=> x = 5,5
Vậy x= 5,5
f) 14 - 4x = 3x + 20
<=> -4x - 3x = 20 - 14
<=> -7x = 6
<=> x = 6 : (-7)
<=> x = \(-\frac{6}{7}\)
25-{14-[(2-x)-(x+13)+23]}=62-{8-[(2x-10)-(29-3x)+8]}
<=>25-14+2-x-x-13+23=62-8+2x-10-29+3x+8
<=>13-x-x-13+23=2x+3x+8-10-29
<=>-x-x+23=2x+3x+(-31)
<=>23-(x+x)=2x+2x-31
<=>23-2x=2x+3x-31
<=>23+31=2x+2x+3x
<=>54=x(2+2+3)
<=>54=x.7
=>x=54/7
Vậy x=54/7
<=>54=x.7
a)7(x-1)+10=80 b)14-3(x+5)=2 c)65-5(3x-1)=15 d)4(12-3x)-9=3
7(x-1)=80-10 3(x+5)=14-2 5(3x-1)=65-15 4(12-3x)=3+9
7(x-1)=70 3(x+5)=12 5(3x-1)=50 4(12-3x)=12
(x-1)=70:7 (x+5)=12:3 (3x-1)=50:5 (12-3x)=12:4
x-1=10 x+5=4 3x-1=10 12-3x=3
x=10+1 x=4-5 3x=10+1 3x=12-3
x=11 x=(-1) 3x=11 3x=9
x=11:3 x=9:3
x=3,6...7 x=3
giup mik voi
$3x-10=14$
$3x=14+10$
$3x=24$
$x=24:3$
$x=8$