\(\left(43+89\right)\times8=132\times8=1056\)

( 43 + 89 ) x 8

= 132 x 8

= 1056

97 tấn + 89kg

= 97 000kg + 89kg

= 97 089kg

97 089❗

a)\(\frac{19}{20}+\frac{1}{20}=1\)

\(\frac{20}{21}+\frac{1}{21}=1\)

 vi \(\frac{1}{20}>\frac{1}{21}\) nen \(\frac{19}{20}<\frac{20}{21}\)

b) \(\frac{89}{88}-\frac{1}{88}=1\)

   \(\frac{90}{89}-\frac{1}{89}=1\)

vi \(\frac{1}{88}>\frac{1}{89}nen\frac{89}{88}>\frac{90}{89}\)

c)\(\frac{2005}{2003}-\frac{2}{2003}=1\)

   \(\frac{2003}{2001}-\frac{2}{2001}=1\)

vi \(\frac{2}{2003}<\frac{2}{2001}nen\frac{2005}{2003}<\frac{2003}{2001}\)

1 <

2 <

3 >

125762801

.ươl-₫k

\(\frac{5}{23}\)<\(\frac{45}{89}\)

<

\(\frac{89}{23}=3\frac{20}{23}\)

\(\frac{89}{23}=3\frac{20}{23}\)

\(89+\frac{2}{12}=89+\frac{1}{6}=\frac{534}{6}+\frac{1}{6}=\frac{534+1}{6}=\frac{535}{6}\)

AI THẤY ĐÚNG NHỚ ỦNG HỘ NHA

\(89+\frac{2}{12}=\frac{535}{6}\)

Tk cho mình nha vì mình đang bị âm điểm

Ta có \(x.a=b\)

\(x=b:a\)

Do đó \(-\frac{3}{5}.x=\frac{5}{6}\)

\(x=\frac{5}{6}:\frac{-3}{5}\)

\(x=-\frac{1}{2}\)

Tương tự 

2. \(x=\frac{6}{8}:\frac{2}{4}=\frac{3}{2}\)

Bạn tự làm câu 3

1.\(\frac{-3}{5}\).x=\(\frac{5}{6}\)

x=\(\frac{5}{6}\):\(\frac{-3}{5}\)

x=\(\frac{-25}{18}\)

2.\(\frac{2}{4}\):x=\(\frac{6}{8}\)

\(\frac{1}{2}\):x=\(\frac{3}{4}\)

x=\(\frac{1}{2}\):\(\frac{3}{4}\)

x=\(\frac{2}{3}\)

3.\(\frac{67}{89}\).x=\(\frac{12}{13}\)

x=\(\frac{12}{13}\):\(\frac{67}{89}\)

x=\(\frac{1068}{871}\)

K MIK NHÉ

\(\frac{46}{87}< \frac{67}{90}\)

Ta có:

\(\frac{46}{49}=\frac{46x90}{89x90}=\frac{4140}{8010}\)

\(\frac{67}{90}=\frac{67x89}{90x89}=\frac{5963}{8010}\)

Vậy: \(\frac{4140}{8010}< \frac{5963}{8010}\)