có k nhá

=> (42+4)x = -996

=> 46x = -996 

=> x = -996 : 46

x = \(-\frac{498}{23}\)

Vậy x = \(-\frac{498}{23}\)

\(\left(7,6+4\right)x=-996\)

           \(11,6x=-996\)

                    \(x=-996:11,6\)

                    \(x=-\frac{2090}{29}\)

Vậy x = -2090/29

a, 2 x 14 x 12 + 4 x 6 x 21 + 8 x 3 x 62

= 24 x 14 + 24 x 21 + 24 x 62

= 24 x ( 14 + 21 + 62 )

= 24 x 97

= 21 x ( 97 + 3 )

= 21 x 100

= 2100 

b,  và c, ( Tương tự câu a, )

mất thời gian vậy

Dài zậy trời

a) Ta có: \(\frac{179}{197}< 1\)và \(\frac{971}{917}>1\)

\(\Rightarrow\frac{179}{197}< 1< \frac{971}{917}\)

\(\Rightarrow\frac{179}{197}< \frac{971}{917}\)

b)Ta có: \(\frac{64}{85}< \frac{64}{81}\) mà \(\frac{73}{81}>\frac{64}{81}\)

\(\Rightarrow\frac{64}{85}< \frac{64}{81}< \frac{73}{81}\)

\(\Rightarrow\frac{64}{85}< \frac{73}{81}\)

Tự làm tiếp nha ~

a) Vì 179/197 < 1 ; 971/917 > 1

=> 179/197 < 971/917

b) Vì 64/85 < 64/81 < 73/81

=> 64/85 < 73/81

c) Ta có: 456/461 = 1 - 5/461 ; 123/128 = 1 - 5/128

Vì 5/461 < 5/128 => 1 - 5/461 > 1 - 5/128

=> 456/461 > 123/128

d) 53/57 = 530/570

Áp dụng a/b < 1 => a/b < a+m/b+m (a,b,m thuộc N*)

Do 530/570 < 1 => 530/570 < 530+1/570+1

=> 53/57 < 531/571

e) Ta có: 58/89 > 58/87 = 2/3

36/53 < 36/54 = 2/3

=> 58/89 > 36/53

g) Ta có: 11/32 > 11/33 = 1/3

16/49 < 16/48 = 1/3

=> 11/32 > 16/49

\(\text{Ta thấy }:\frac{-1}{3}<0;\frac{1}{63}>0\)

\(\text{Vậy }\frac{-1}{3}<\frac{1}{63}\)

\(a,\frac{\left(21\right)^{15}.49^{11}.5^6}{\left(63\right)^{14}.7}=\frac{\left(3.7\right)^{15}.\left(7^2\right)^{11}.5^6}{\left(3^2.7\right)^{14}.7}=\frac{3^{15}.7^{15}.7^{22}.5^6}{\left(3^2\right)^{14}.7^{14}}=\frac{3^{15}.7^{37}.5^6}{3^{28}.7^{14}}\)

\(=\frac{7^{23}.5^6}{3^{13}}\)

sao số to thế nhỉ

1+2+3+...+x = (1 + x) * x / 2 = 666

(1 + x) * x = 666 * 2 = 1332

1332 / x - 1 = x <=> x * (x + 1) = 1332

=> x = 36