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\(x-\dfrac{2}{3}=-\dfrac{5}{12}\)
\(\Rightarrow x=-\dfrac{5}{12}+\dfrac{2}{3}\)
\(\Rightarrow x=-\dfrac{5}{12}+\dfrac{8}{12}\)
\(\Rightarrow x=\dfrac{3}{12}=\dfrac{1}{4}\)
`----`
\(\dfrac{x}{15}=\dfrac{3}{4}+\dfrac{19}{-20}\)
\(\Rightarrow\dfrac{x}{15}=-\dfrac{1}{5}\)
\(\Rightarrow-\dfrac{3}{15}=-\dfrac{1}{5}\)
\(\Rightarrow x=-3\)
`-----`
\(\dfrac{x}{-2}=-\dfrac{8}{x}\)
\(\Rightarrow x^2=-2.\left(-8\right)\)
\(\Rightarrow x^2=16\)
\(\Rightarrow\left[{}\begin{matrix}x=4\\x=-4\end{matrix}\right.\)
a) �−23=−512x−32=12−5
�=−512+23x=12−5+32
�=−512+812x=12−5+128
�=−5+812x=12−5+8
�=312x=123
�=14x=41
b) 85:�=−2358:x=3−2
�=85:( −23)x=58:( 3−2)
�=85. ( 3−2)x=58.
Đúng(0)
a) �−23=−512x−32=12−5
�=−512+23x=12−5+32
�=−512+812x=12−5+128
�=−5+812x=12−5+8
�=312x=123
�=14x=41
b) 85:�=−2358:x=3−2
�=85:( −23)x=58:( 3−2)
�=85. ( 3−2)x=58.
Đúng(0)
a) �−23=−512x−32=12−5
�=−512+23x=12−5+32
�=−512+812x=12−5+128
�=−5+812x=12−5+8
�=312x=123
�=14x=41
b) 85:�=−2358:x=3−2
�=85:( −23)x=58:( 3−2)
�=85. ( 3−2)x=58.
Đúng(0)
a)
�−23=−512x−32=12−5
�=−512+23x=12−5+32
�=−512+812x=12−5+128
�=−5+812x=12−5+8
�=312x=123
�=14x=41
b) 85:�=−2358:x=3−2
�=85:( −23)x=58:( 3−2)
�=85. ( 3−2)x=58
Đúng(0)
a) �−23=−512x−32=12−5
�=−512+23x=12−5+32
�=−512+812x=12−5+128
�=−5+812x=12−5+8
�=312x=123
�=14x=41
b) 85:�=−2358:x=3−2
�=85:( −23)x=58:( 3−2)
�=85. ( 3−2)x=58.
Đúng(0)
a) �−23=−512x−32=12−5
�=−512+23x=12−5+32
�=−512+812x=12−5+128
�=−5+812x=12−5+8
�=312x=123
�=14x=41
b) 85:�=−2358:x=3−2
�=85:( −23)x=58:( 3−2)
�=85. ( 3−2)x=58.
Đúng(0)
a) �−23=−512x−32=12−5
�=−512+23x=12−5+32
�=−512+812x=12−5+128
�=−5+812x=12−5+8
�=312x=123
�=14x=41
b) 85:�=−2358:x=3−2
�=85:( −23)x=58:( 3−2)
�=85. ( 3−2)x=58.
Đúng(0)
a) �−23=−512x−32=12−5
�=−512+23x=12−5+32
�=−512+812x=12−5+128
�=−5+812x=12−5+8
�=312x=123
�=14x=41
b) 85:�=−2358:x=3−2
�=85:( −23)x=58:( 3−2)
�=85. ( 3−2)x=58.
Đúng(0)
a) �−23=−512x−32=12−5
�=−512+23x=12−5+32
�=−512+812x=12−5+128
�=−5+812x=12−5+8
�=312x=123
�=14x=41
b) 85:�=−2358:x=3−2
�=85:( −23)x=58:( 3−2)
�=85. ( 3−2)x=58.
Đúng(0)
a) �−23=−512x−32=12−5
�=−512+23x=12−5+32
�=−512+812x=12−5+128
�=−5+812x=12−5+8
�=312x=123
�=14x=41
b) 85:�=−2358:x=3−2
�=85:( −23)x=58:( 3−2)
�=85. ( 3−2)x=58.
Đúng(0)
a)
b)
c)
x - 2/3 =5/12
x =2/3 + 5/12
x=8/12 + 5/12
x=13/12
8/5 :x =-2/3
x =8/5 : -2/3
x = 24/-10
x - 2/3 = -5/12
x = 5/12 +2/3
x = 39/36
8/5 : x = -2/3
x = [(-2/3)*8/5]
x = -16/15
1 - 3/7.x = - 2/7
-3/7.x. = -2/7 + 1
-3/7.x. = 5/7
x. = 5/7 : (-3/7)
x. = 5/7 . (-7/3)
x. = -35/21
x-2/3=-5/12
a,
x = -5/12+2/3
x = -5/12+8/12
x = 3/12=1/4
b, 8/5÷x= -2/3
x = 8/5÷ -2/3
x = 8/5× -3/2
x = -24/10 = -12/5
c, 1-3/7x= -2/7
-3/7x = -2/7-1
-3/7x = -2/7-7/7
-3/7x = -9/7
x = -3/7÷ -9/7
x = -3/7×-7/9
x = 3
Ùu
A, a-2/3=-5/12
X=-5/12+2/3
X=-5/12+8/12
=3/12
×=1/4
B,8/5÷x=-2/3
X=-24/10
X=-12/5
C,1-3/7×x=-2/7
=3/7×x=1-(-2/7)
=3/7×x=1+2/7
=3/7×x=9/7
X=9/7÷3/7
X=9/7×7/3
X=9/3
X=3
T
a) x - 2/3 = -5/12
X = -5/12 + 2/3
X = -5/12 + 8/12
X = 3/12 = 1/4
b) 8/5 : x = -2/3
X = 8/5 : -2/3
X = 8/5 • -3/2
X = -24/10 = -12/5
c) 1 - 3/7 • x = -2/7
X = 3/7 • x = 1 - ( -2/7 )
X = 3/7 • x = 1 + 2/7
X = 3/7 • x = 7/7 + 2/7
X = 3/7 • x = 9/7
X = 9/7 : 3/7
X = 9/7 • 7/3
X = 9/3
X = 3
a) 1/4 b) -12/5 c) 3
Tìm x biết: a) \(\dfrac{6}{-x}=\dfrac{x}{-24}\) b) \(x-\dfrac{7}{12}x+\dfrac{3}{8}x=\dfrac{5}{24}\)
c)\(\left(x-\dfrac{1}{3}\right)^2-\dfrac{1}{2}=1\dfrac{3}{4}\) d) \(\dfrac{x-3}{-2}=\dfrac{-8}{x-3}\)
e) \(\dfrac{9}{x}=\dfrac{-35}{105}\) f) \(\left(x-\dfrac{1}{2}\right)\left(-3-\dfrac{x}{2}\right)=0\)
a: =>6/x=x/24
=>x^2=144
=>x=12 hoặc x=-12
b: =>x(1-7/12+3/8)=5/24
=>x*19/24=5/24
=>x=5/24:19/24=5/19
c: =>(x-1/3)^2=1+3/4+1/2=9/4
=>x-1/3=3/2 hoặc x-1/3=-3/2
=>x=11/6 hoặc x=-7/6
d: =>(x-3)^2=16
=>x-3=4 hoặc x-3=-4
=>x=-1 hoặc x=7
e: =>9/x=-1/3
=>x=-27
f: =>x-1/2=0 hoặc -x/2-3=0
=>x=1/2 hoặc x=-6
tìm x:
a)\(\left(x+\dfrac{1}{2}\right).\left(\dfrac{2}{3}-2x\right)=0\)
b) \(\left(x.6\dfrac{2}{7}+\dfrac{3}{7}\right).2\dfrac{1}{5}-\dfrac{3}{7}=-2\)
c) \(x.3\dfrac{1}{4}+\left(\dfrac{-7}{6}\right).x-1\dfrac{2}{3}=\dfrac{5}{12}\)
d) \(5\dfrac{8}{17}:x+\left(-\dfrac{4}{17}\right):x+3\dfrac{1}{7}:17\dfrac{1}{3}=\dfrac{4}{11}\)
a: (x+1/2)(2/3-2x)=0
=>x+1/2=0 hoặc 2/3-2x=0
=>x=-1/2 hoặc x=1/3
b:
c: \(\Leftrightarrow x\cdot\left(\dfrac{13}{4}-\dfrac{7}{6}\right)=\dfrac{5}{12}+\dfrac{5}{3}=\dfrac{5}{12}+\dfrac{20}{12}=\dfrac{25}{12}\)
\(\Leftrightarrow x=\dfrac{25}{12}:\dfrac{39-14}{12}=\dfrac{25}{25}=1\)
Tìm \(x\) biết :
a) \(x.\dfrac{3}{7}=\dfrac{2}{3}\)
b) \(x:\dfrac{8}{11}=\dfrac{11}{3}\)
c) \(\dfrac{2}{5}:x=-\dfrac{1}{4}\)
d) \(\dfrac{4}{7}.x-\dfrac{2}{3}=\dfrac{1}{5}\)
e) \(\dfrac{2}{9}-\dfrac{7}{8}.x=\dfrac{1}{3}\)
g) \(\dfrac{4}{5}+\dfrac{5}{7}:x=\dfrac{1}{6}\)
\(A.\dfrac{-15}{28}x\dfrac{7}{25}\\ B.\dfrac{-5}{14}x\dfrac{7}{-3}\\ C.\dfrac{-1}{5}-\dfrac{7}{15}x\dfrac{9}{35}\\ D.\dfrac{-3}{4}-(\dfrac{-1}{2})^2\\ E.\dfrac{-4}{5}-\dfrac{-4}{5}x\dfrac{15}{16}\\F.(\dfrac{3}{4}+\dfrac{-7}{2})x(\dfrac{2}{11}+\dfrac{12}{22})\)
a: \(A=\dfrac{-7}{28}\cdot\dfrac{15}{25}=\dfrac{-1}{4}\cdot\dfrac{3}{5}=\dfrac{-3}{20}\)
b: \(B=\dfrac{-5\cdot7}{14\cdot\left(-3\right)}=\dfrac{35}{42}=\dfrac{5}{6}\)
c: \(C=\dfrac{-1}{5}-\dfrac{1}{5}\cdot\dfrac{3}{5}=\dfrac{-1}{5}-\dfrac{3}{25}=\dfrac{-8}{25}\)
d: \(D=\dfrac{-3}{4}-\dfrac{1}{4}=-1\)
e: \(E=\dfrac{-4}{5}\left(1-\dfrac{15}{16}\right)=\dfrac{-4}{5}\cdot\dfrac{1}{16}=\dfrac{-1}{20}\)
f: \(F=\dfrac{6-7}{4}\cdot\dfrac{4+12}{22}=\dfrac{-1}{4}\cdot\dfrac{8}{11}=\dfrac{-2}{11}\)
a)x=\(\dfrac{1}{4}+\dfrac{2}{13}\)
b)\(\dfrac{x}{3}=\dfrac{2}{3}+\dfrac{-1}{7}\)
c)\(\dfrac{-8}{3}+\dfrac{-1}{3}\le x\le\dfrac{-2}{7}+\dfrac{-5}{7}\)
d)\(\dfrac{-5}{6}+\dfrac{8}{3}\dfrac{29}{-x}\le x\le\dfrac{-1}{2}+2+\dfrac{5}{2}\)
Đề là j zậy bn
tính
Tìm x, biết:
a) \(\dfrac{-2}{5}\) + \(\dfrac{4}{5}\) . x = \(\dfrac{3}{5}\)
b) \(\dfrac{-3}{7}\) - \(\dfrac{4}{7}\) : x = \(\dfrac{2}{5}\)
c) \(\dfrac{4}{7}\) . x + \(\dfrac{2}{3}\) = \(\dfrac{-1}{5}\)
d) \(\dfrac{5}{7}\) : x -1 = \(\dfrac{2}{3}\)
a, - \(\dfrac{2}{5}\) + \(\dfrac{4}{5}\).\(x\) = \(\dfrac{3}{5}\)
\(\dfrac{4}{5}\).\(x\) = \(\dfrac{3}{5}\)+ \(\dfrac{2}{5}\)
\(\dfrac{4}{5}\).\(x\) = 1
\(x\) = \(\dfrac{5}{4}\)
b, - \(\dfrac{3}{7}\) - \(\dfrac{4}{7}\): \(x\) = \(\dfrac{2}{5}\)
\(\dfrac{4}{7}\): \(x\) = - \(\dfrac{3}{7}\) - \(\dfrac{2}{5}\)
\(\dfrac{4}{7}\): \(x\) = - \(\dfrac{29}{35}\)
\(x\) = \(\dfrac{4}{7}\): (- \(\dfrac{29}{35}\) )
\(x\) = - \(\dfrac{20}{29}\)
c, \(\dfrac{4}{7}\).\(x\) + \(\dfrac{2}{3}\) = - \(\dfrac{1}{5}\)
\(\dfrac{4}{7}\).\(x\) = -\(\dfrac{1}{5}\) - \(\dfrac{2}{3}\)
\(\dfrac{4}{7}\).\(x\) = - \(\dfrac{13}{15}\)
\(x\) = - \(\dfrac{13}{15}\): \(\dfrac{4}{7}\)
\(x\) = - \(\dfrac{91}{60}\)
Tìm x, biết:
a) x+\(\dfrac{1}{6}\)=\(\dfrac{-3}{8}\) b) \(2-\left(\dfrac{3}{4}-x\right)=\dfrac{7}{12}\)
c) \(\dfrac{1}{2}x\)+\(\dfrac{1}{8}x=\dfrac{3}{4}\) d) 75%-\(1\dfrac{1}{2}+0,5:\dfrac{5}{12}-\left(\dfrac{-1}{2}\right)^2\)
\(a.x+\dfrac{1}{6}=-\dfrac{3}{8}\)
\(\Leftrightarrow x=-\dfrac{13}{24}\)
\(b.2-\left(\dfrac{3}{4}-x\right)=\dfrac{7}{12}\)
\(\Leftrightarrow2-\dfrac{3}{4}+x=\dfrac{7}{12}\)
\(\Leftrightarrow x=-\dfrac{2}{3}\)
\(c.\dfrac{1}{2}x+\dfrac{1}{8}x=\dfrac{3}{4}\)
\(\Leftrightarrow\dfrac{5}{8}x=\dfrac{3}{4}\)
\(\Leftrightarrow x=\dfrac{6}{5}\)
\(d.75\%-1\dfrac{1}{2}+0,5:\dfrac{5}{12}-\left(\dfrac{-1}{2}\right)^2\)
\(=\dfrac{75}{100}-\dfrac{3}{2}+\dfrac{1}{2}:\dfrac{5}{12}-\dfrac{1}{4}\)
\(=-\dfrac{3}{4}+\dfrac{6}{5}-\dfrac{1}{4}\)
\(=\dfrac{1}{5}\)
a) \(x+\dfrac{1}{6}=\dfrac{-3}{8}\)
\(x=\dfrac{-3}{8}-\dfrac{1}{6}\)
\(x=\dfrac{-13}{24}\)
vậy x =....
b) \(2-\left(\dfrac{3}{4}-x\right)=\dfrac{7}{12}\)
\(\dfrac{3}{4}-x=2-\dfrac{7}{12}\)
\(\dfrac{3}{4}-x=\dfrac{17}{12}\)
\(x=\dfrac{3}{4}-\dfrac{17}{12}\)
\(x=\dfrac{-2}{3}\)
vậy x =....
Bài 2:Tìm x biết:
a)\(\dfrac{1}{7}+x=\dfrac{-2}{3}\)
b)\(\dfrac{-2}{3}:x=\dfrac{-5}{6}\)
c)\(\left\{\dfrac{3}{5}-2x\right\}.\dfrac{5}{8}=1\)
d)\(\dfrac{3}{4}+\dfrac{2}{5}x=\dfrac{29}{60}\)
e)\(\dfrac{3}{4}+\dfrac{1}{4}:x=\dfrac{2}{5}\)
f)\(\dfrac{11}{12}-\left(\dfrac{2}{5}+x\right)=\dfrac{2}{3}\)
g)\(\left|X+\dfrac{1}{3}\right|-4=\dfrac{-1}{2}\)
h)\(\left(\dfrac{1}{32}\right)^x.8^{2x}=512\)
i)\(5,3x+\left(-3,3\right)x+1,7=-4,9\)
a) Ta có: \(\dfrac{1}{7}+x=-\dfrac{2}{3}\)
\(\Leftrightarrow x=-\dfrac{2}{3}-\dfrac{1}{7}=\dfrac{-14}{21}-\dfrac{3}{21}\)
hay \(x=-\dfrac{17}{21}\)
Vậy: \(x=-\dfrac{17}{21}\)
b) Ta có: \(\dfrac{-2}{3}:x=\dfrac{-5}{6}\)
\(\Leftrightarrow x=\dfrac{-2}{3}:\dfrac{-5}{6}=\dfrac{-2}{3}\cdot\dfrac{6}{-5}=\dfrac{-12}{-15}=\dfrac{4}{5}\)
Vậy: \(x=\dfrac{4}{5}\)
c) Ta có: \(\left(\dfrac{3}{5}-2x\right)\cdot\dfrac{5}{8}=1\)
\(\Leftrightarrow\left(\dfrac{3}{5}-2x\right)=1:\dfrac{5}{8}=\dfrac{8}{5}\)
\(\Leftrightarrow-2x=\dfrac{8}{5}-\dfrac{3}{5}=1\)
hay \(x=-\dfrac{1}{2}\)
Vậy: \(x=-\dfrac{1}{2}\)
d) Ta có: \(\dfrac{3}{4}+\dfrac{2}{5}x=\dfrac{29}{60}\)
\(\Leftrightarrow x\cdot\dfrac{2}{5}=\dfrac{29}{60}-\dfrac{3}{4}=\dfrac{29}{60}-\dfrac{45}{60}=\dfrac{-16}{60}=\dfrac{-4}{15}\)
hay \(x=\dfrac{-4}{15}:\dfrac{2}{5}=\dfrac{-4}{15}\cdot\dfrac{5}{2}=\dfrac{-20}{30}=-\dfrac{2}{3}\)
Vậy: \(x=-\dfrac{2}{3}\)
e) Ta có: \(\dfrac{3}{4}+\dfrac{1}{4}:x=\dfrac{2}{5}\)
\(\Leftrightarrow\dfrac{1}{4}:x=\dfrac{2}{5}-\dfrac{3}{4}=\dfrac{8}{20}-\dfrac{15}{20}=\dfrac{-7}{20}\)
hay \(x=-\dfrac{1}{4}:\dfrac{7}{20}=\dfrac{-1}{4}\cdot\dfrac{20}{7}=\dfrac{-20}{28}=\dfrac{-5}{7}\)
Vậy: \(x=-\dfrac{5}{7}\)
f) Ta có: \(\dfrac{11}{12}-\left(\dfrac{2}{5}+x\right)=\dfrac{2}{3}\)
\(\Leftrightarrow-x+\dfrac{11}{12}-\dfrac{2}{5}-\dfrac{2}{3}=0\)
\(\Leftrightarrow-x+\dfrac{55}{60}-\dfrac{24}{60}-\dfrac{40}{60}=0\)
\(\Leftrightarrow-x-\dfrac{9}{60}=0\)
\(\Leftrightarrow-x=\dfrac{9}{60}=\dfrac{3}{20}\)
hay \(x=-\dfrac{3}{20}\)
Vậy: \(x=-\dfrac{3}{20}\)
g) Ta có: \(\left|x+\dfrac{1}{3}\right|-4=\dfrac{-1}{2}\)
\(\Leftrightarrow\left|x+\dfrac{1}{3}\right|=\dfrac{-1}{2}+4=\dfrac{-1}{2}+\dfrac{8}{2}=\dfrac{7}{2}\)
\(\Leftrightarrow\left[{}\begin{matrix}x+\dfrac{1}{3}=\dfrac{7}{2}\\x+\dfrac{1}{3}=-\dfrac{7}{2}\end{matrix}\right.\Leftrightarrow\left[{}\begin{matrix}x=\dfrac{7}{2}-\dfrac{1}{3}=\dfrac{21}{6}-\dfrac{2}{6}=\dfrac{19}{6}\\x=-\dfrac{7}{2}-\dfrac{1}{3}=\dfrac{-21}{6}-\dfrac{2}{6}=\dfrac{-23}{6}\end{matrix}\right.\)
Vậy: \(x\in\left\{\dfrac{19}{6};-\dfrac{23}{6}\right\}\)
cảm ơn cậu cutee gì đó ơi nha
Tìm x, biết:
a) \(\dfrac{2}{5}\) + \(\dfrac{3}{4}\): x = \(\dfrac{-1}{2}\)
b) \(\dfrac{5}{7}\) - \(\dfrac{2}{3}\) . x = \(\dfrac{4}{5}\)
c) \(\dfrac{1}{2}\) x + \(\dfrac{2}{3}\) x = \(\dfrac{-2}{3}\)
d) \(\dfrac{4}{7}\)x - x= \(\dfrac{-9}{14}\)
a, 2/5 + 3/4 : x = -1/2
3/4 : x = -1/2 - 2/5
3/4 : x = -9/10
x = 3/4 : -9/10
x = -5/6
b, 5/7 - 2/3 . x = 4/5
2/3 . x = 4/5 + 5/7
2/3 . x = 53/35
x = 53/35 : 2/3
x = 159/70
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