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a: 2/9-4/9=-2/9
b: 5/7-4/14=5/7-2/7=3/7
c: -2-5/8=-16/8-5/8=-21/8
d: =6/13+14/39=18/39+14/39=32/39
e: =4/5+4/18=72/90+20/90=92/90=46/45
f: =5/30-12/30=-7/30
g: =-63/63=-1
h: =4/13x26=4x2=8
a: 2/9-4/9=-2/9
b: 5/7 - 4/14 = 5/7 - 2/7 = 3/7
c: -2 - 5/8 = - 16/8 - 5/8 = - 21/8
d: = 6/13 + 14/39 = 18/39 + 14/39 = 32/39
e: = 4/5 + 4/18 = 72/90 + 20/90 = 92/90 = 46/45
f: = 5/30 - 12/30 = -7/30
g: = - 63/63 = -1
h: = 4/13 . 26 =4 . 2 = 8
= 35+3
38 :33 = 38-3=35
38 :35= 38-5=33
27:23=27-3=24
27:24=27-4=23
a) 23; 24 ; 25
23=8
24=16
25=32
NGUYỄN NHẬT MINH 6A THCS QUANG THỊNH 2021-2022
\(3^5:3^3=3^2\)
\(3^8:3^3=3^5\)và \(3^8:3^3=243\)
Ta thấy số mũ của luỹ thừa ta tìm được chính là hiệu của 2 luỹ thừa trên
dự đoán \(\hept{\begin{cases}2^7:2^3=2^4\\2^7:2^4=2^3\end{cases}}\)
- 3^5 / 3^3 = 3^ ( 5 - 3) = 3^ 2 = 9
- 3^8 / 3^3 = 3^ ( 8 - 3) = 3^5 = 243
- 2^7/ 2^3 = 2^ ( 7 - 3) = 2^4 = 16
2^7/ 2^4 = 2^( 7 - 4) = 2^3 = 8
\(a,11^8:11^3=11^5\)
\(b,17^{11}:17^9=17^2\)
\(c,4^3:2^2=\left(2^2\right)^3:2^2=2^6:2^2=2^4\)
\(d,a^5:a=a^4\)
!!!
\(a)11^8\div11^3=11^{8-3}=11^5\)
\(b)17^{11}\div17^9=17^{11-9}=17^2\)
\(c)4^3\div2^2=4^3\div4=4^2\)
\(d)a^5\div a=a^4\)
`(-4)^{2}.(-3)-[(-93)+(-11+8).3]`
`=16.(-3)-(-93-3.3)`
`=-48-(-93-9)`
`=-48-(-102)`
`=-48+102=54`
(–4)
2.(–3)–[(–93)+(–11+8).3]
= 16 . (-3)-[(-93)+(-11+8).3]
= 16 . (-3)-[(-93)+ (-3) .3]
= 16 . (-3)-[(-93) + (-9)]
=16 . (-3)- (-102)
= (-48)-(-102)
= 54
(–4)2.(–3)–[(–93)+(–11+8).3]
Hướng dẫn giải:Ta có (-4)^2 .(-3)-\left[(-93)+(-11+8)^3\right](−4)2.(−3)−[(−93)+(−11+8)3]
=16 .(-3)-\left[(-93)+(-3)^3\right]=16.(−3)−[(−93)+(−3)3]
=-48-[(-93)+(-27)]=−48−[(−93)+(−27)]
=-48-(-120)=−48−(−120)
=72=72.
(−4)2.(−3)−[(−93)+(−11+8).3]
=16.(-3)-(-93-3.3)=16.(−3)−(−93−3.3)
=-48-(-93-9)=−48−(−93−9)
=-48-(-102)=−48−(−102)
=-48+102=54=−48+102=54
(−4)2.(−3)−[(−93)+(−11+8)3]
=16 .(-3)-\left[(-93)+(-3)^3\right]=16.(−3)−[(−93)+(−3)3]
=-48-[(-93)+(-27)]=−48−[(−93)+(−27)]
=-48-(-120)=−48−(−120)
=72=72.
(−4)2.(−3)−[(−93)+(−11+8).3]
=16.(-3)-(-93-3.3)=16.(−3)−(−93−3.3)
=-48-(-93-9)=−48−(−93−9)
=-48-(-102)=−48−(−102)
=-48+102=54=−48+102=54
Ta có (−4)2.(−3)−[(−93)+(−11+8)3](−4)2.(−3)−[(−93)+(−11+8)3]
=16.(−3)−[(−93)+(−3)3]=16.(−3)−[(−93)+(−3)3]
=−48−[(−93)+(−27)]=−48−[(−93)+(−27)]
=−48−(−120)=−48−(−120)
=72=72.
(–4)2.(–3) – [(–93) + (–11+8)3] = (-16).(–3) – [(–93) + (–3)3] = (-16).(–3) – [(–93) + (–3)3] = - 48 + 93 - 27 = 18
72.
(−4)2.(−3)−[(−93)+(−11+8).3]
=16.(−3)−(−93−3.3)=16.(−3)−(−93−3.3)
=−48−(−93−9)=−48−(−93−9)
=−48−(−102)=−48−(−102)
=−48+102=54=−48+102=54
(−4)2.(−3)−[(−93)+(−11+8).3]
=16.(−3)−(−93−3.3)=16.(−3)−(−93−3.3)
=−48−(−93−9)=−48−(−93−9)
=−48−(−102)=−48−(−102)
=−48+102=54=−48+102=54
(–4)2.(–3)–[(–93)+(–11+8)3]
=16.(−3)−[(−93)+(−3)3]=16.(−3)−[(−93)+(−3)
]
=−48−[(−93)+(−27)]=−48−[(−93)+(−27)]
=−48−(−120)=−48−(−120)
=72=72.
(–4)22.(–3)–[(–93)+(–11+8)33].
= 16.(-3) + 93 -(-3)3= 16.(-3) + 93 - (-27) = 16.(-3) + 93 + 27 = 3(-16+31+9) = 3.(-16 + 40) = 3. 24 = 72
16x(-3)-[(-93)+(-3)3]
=(-48)-[(-93)+(-27)]
=−48−[(−93)+(−27)]=−48−[(−93)+(−27)]
=−48−(−120)==
−48−[(−93)+(−27)]=−48−[(−93)+(−27)]
=−48−(−120)=−48−(−120)
=72=72
=(-48)-(-120)
=72
(−4)2.(−3)−[(−93)+(−11+8)3](−4)2.(−3)−[(−93)+(−11+8)3]
=16.(−3)−[(−93)+(−3)3]=16.(−3)−[(−93)+(−3)3]
=−48−[(−93)+(−27)]=−48−[(−93)+(−27)]
=−48−(−120)=−48−(−120)
=72
Ta có (−4)2.(−3)−[(−93)+(−11+8)3](−4)2.(−3)−[(−93)+(−11+8)3]
=16.(−3)−[(−93)+(−3)3]=16.(−3)−[(−93)+(−3)3]
=−48−[(−93)+(−27)]=−48−[(−93)+(−27)]
=−48−(−120)=−48−(−120)
=72=72.
(−4)22.(−3)−[(−93)+(−11+8).3]
=16.(−3)−(−93−3.3)=16.(−3)−(−93−3.3)
=−48−(−93−9)=−48−(−93−9)
=−48−(−102)=−48−(−102)
=−48+102=54=−48+102=54
Ta có (−4)2.(−3)−[(−93)+(−11+8)3](−4)2.(−3)−[(−93)+(−11+8)3]
=16.(−3)−[(−93)+(−3)3]=16.(−3)−[(−93)+(−3)3]
=−48−[(−93)+(−27)]=−48−[(−93)+(−27)]
=−48−(−120)=−48−(−120)
=72=72.
(−4)2.(−3)−[(−93)+(−11+8)3]
=16.(−3)−[(−93)+(−3)3]=16.(−3)−[(−93)+(−3)3]
=−48−[(−93)+(−27)]=−48−[(−93)+(−27)]
=−48−(−120)=−48−(−120)
=72=72.
(–4)
2.(–3)–[(–93)+(–11+8)
3]
= (-16).(-3)-[(-93)+(-3)3]
= (-16).(-3)-[(-93)+(-27)]
= (-16).(-3)-[-(93+27)]
= (-16).(-3)-(-120)
= 48-(-120)
= 48+120
= 168
(−4)2.(−3)−[(−93)+(−11+8).3]
=16.(−3)−(−93−3.3)=16.(−3)−(−93−3.3)
=−48−(−93−9)=−48−(−93−9)
=−48−(−102)=−48−(−102)
=−48+102=54=−48+102=54
(−4)2.(−3)−[(−93)+(−11+8).3]
=16.(−3)−(−93−3.3)=16.(−3)−(−93−3.3)
=−48−(−93−9)=−48−(−93−9)
=−48−(−102)=−48−(−102)
=−48+102=54=−48+102=54
(−4)2.(−3)−[(−93)+(−11+8).3]
=16.(−3)−(−93−3.3)=16.(−3)−(−93−3.3)
=−48−(−93−9)=−48−(−93−9)
=−48−(−102)=−48−(−102)
=−48+102=54=−48+102=54
(−4)2.(−3)−[(−93)+(−11+8).3]
=16.(−3)−(−93−3.3)=16.(−3)−(−93−3.3)
=−48−(−93−9)=−48−(−93−9)
=−48−(−102)=−48−(−102)
=−48+102=54=−48+102=54
(−4)2.(−3)−[(−93)+(−11+8).3]
=16.(−3)−(−93−3.3)=16.(−3)−(−93−3.3)
=−48−(−93−9)=−48−(−93−9)
=−48−(−102)=−48−(−102)
=−48+102=54=−48+102=54
(−4)2.(−3)−[(−93)+(−11+8).3]
=16.(−3)−(−93−3.3)=16.(−3)−(−93−3.3)
=−48−(−93−9)=−48−(−93−9)
=−48−(−102)=−48−(−102)
=−48+102=54=−48+102=54
(−4)2.(−3)−[(−93)+(−11+8).3]
=16.(−3)−(−93−3.3)=16.(−3)−(−93−3.3)
=−48−(−93−9)=−48−(−93−9)
=−48−(−102)=−48−(−102)
=−48+102=54=−48+102=54
(−4)2.(−3)−[(−93)+(−11+8).3]
=16.(−3)−(−93−3.3)=16.(−3)−(−93−3.3)
=−48−(−93−9)=−48−(−93−9)
=−48−(−102)=−48−(−102)
=−48+102=54=−48+102=54
(−4)2.(−3)−[(−93)+(−11+8).3]
=16.(−3)−(−93−3.3)=16.(−3)−(−93−3.3)
=−48−(−93−9)=−48−(−93−9)
=−48−(−102)=−48−(−102)
=−48+102=54=−48+102=54
(−4)2.(−3)−[(−93)+(−11+8).3]
=16.(−3)−(−93−3.3)=16.(−3)−(−93−3.3)
=−48−(−93−9)=−48−(−93−9)
=−48−(−102)=−48−(−102)
=−48+102=54=−48+102=54
(−4)2.(−3)−[(−93)+(−11+8).3]
=16.(−3)−(−93−3.3)=16.(−3)−(−93−3.3)
=−48−(−93−9)=−48−(−93−9)
=−48−(−102)=−48−(−102)
=−48+102=54=−48+102=54